vm4

3
V e d i c M a t he m a t i c s M. Krishnamoorthy (moorthy) email address: [email protected] URL: http://www.cs.rpi.edu/~moorthy/vm O u t l i ne o f t h i s c l a ss Using Urdhva-triyagbhyam sutra (vertically and crosswise) for division of large numbers. Division using Dhvajanka sutra (on top of the flag). Sutra 1.Urdhva-Tiryak Sutra; 2 3 4 5: 6 4 2 :1 -------------- 8 2 : 12 Quotient is 82 Remainder is 12 A n o t he r E x a m p l e 3: 38 9 8 :2 dividend row 7: 3 3 :1 remainder row ------------------------- 5 3 4 :0 quotient row Quotient is 534 Remainder is 0.

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Page 1: Vm4

Ved

ic M

athe

mat

ics

M. K

rish

nam

oort

hy (

moo

rthy

)

emai

l add

ress

: moo

rthy

@cs

.rpi

.edu

UR

L:

http

://w

ww

.cs.

rpi.e

du/~

moo

rthy

/vm

Out

line

of th

is c

lass

� Usi

ng U

rdhv

a-tr

iyag

bhya

m s

utra

(ve

rtic

ally

and

cros

swis

e) f

or d

ivis

ion

of la

rge

num

bers

.

� Div

isio

n us

ing

Dhv

ajan

ka s

utra

(on

top

ofth

e fl

ag).

Sut

ra

1.U

rdhv

a-T

irya

k Su

tra;

23

4 5

: 6

4

2

:1

----

----

----

--

8 2

: 12

Quo

tient

is 8

2

Rem

aind

er is

12

Ano

ther

Exa

mpl

e

3:

38

9 8

:2 d

ivid

end

row

7:

3

3

:1 r

emai

nder

row

----

----

----

----

----

----

-

5 3

4:0

quo

tient

row

Quo

tient

is 5

34

Rem

aind

er is

0.

Page 2: Vm4

How

doe

s th

e m

etho

d w

ork

� The

re a

re th

ree

row

s. T

he f

irst

row

is th

edi

vide

nd.

� The

sec

ond

row

is th

e re

mai

nder

row

.

� Thi

rd r

ow is

the

rem

aind

er r

ow.

� The

div

isor

is p

lace

d ac

cord

ing

to th

eD

hvaj

anka

Sut

ra.

Wha

t is

the

met

hod?

The

ent

ire

divi

sion

is to

be

by 7

(th

e le

adin

gdi

git)

.

We

allo

t one

pla

ce a

t the

rig

ht e

nd o

f th

edi

vide

nd f

or th

e re

mai

nder

por

tion

of th

ean

swer

.

1) W

e di

vide

38 b

y 7

and

we

get 5

as

the

quot

ient

and

3 a

s th

e re

mai

nder

.

Cru

cial

ste

ps!!

2)

We

put 5

as

the

firs

t quo

tient

and

pla

ce 3

on th

e to

p ro

w. (

note

trea

t the

nex

t tw

odi

gits

as

39 -

thre

e fr

om th

e re

mai

nder

and

9fr

om th

e ne

xt d

igit

in th

e di

vide

nd.)

3) F

rom

this

, we

dedu

ct 3

* 5

(th

e la

st d

igit

ofth

e di

viso

r an

d th

e qu

otie

nt).

39-1

5=24

isou

r ne

xt d

ivid

end.

Con

tinue

4) W

hen

we

divi

de 2

4 by

7 w

e ge

t 3 a

squ

otie

nt a

nd 3

as

the

rem

aind

er. A

s be

fore

,w

e pl

ace

quot

ient

3 in

the

quot

ient

row

and

rem

aind

er 3

in th

e re

mai

nder

row

.

5) N

ow th

e ne

w d

ivid

end

is 3

8-3*

3=29

(3 is

the

rem

aind

er a

nd 8

is th

e ne

xt d

igit

inth

e di

vide

nd -

so

38 a

nd th

en s

ubtr

act t

hepr

oduc

t of

3 an

d 3

(the

quo

tient

and

the

last

digi

t))

Page 3: Vm4

Con

td

6) D

ivid

ing

29 b

y 7,

we

get 4

as

the

quot

ient

and

1 as

the

rem

aind

er. P

lace

4 in

the

quot

ient

row

and

1 in

the

rem

aind

er r

ow.

7) 1

2 is

the

next

dig

it w

e ne

ed to

con

side

r.H

owev

er, s

ince

2 is

the

desi

gnat

edre

mai

nder

in th

e fi

rst r

ow, w

e w

ill s

ubtr

act

as u

sual

fro

m 1

2 , t

he n

umbe

r 4*

3 an

d w

ege

t the

rem

aind

er is

0.

Mor

e E

xam

ples

Div

ide

7632

by

94

476

3:2

9

4

:2

----

----

----

----

----

----

--

81

:18

Quo

tient

: 81

Rem

aind

er 1

8