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Kites team Structurelecture2
TRUSSES1-Axial loads only 2-Loads applies at
end points only 3 -Elements are
joined by pins only
1-Determine the force in each member of the truss?
0 1
0 2
0 3
2tan tan
3
tan 0 43
X X X
Y Y Y
A Y
Y
X
X Y
F A B P
F A B
M B L Ph
B h
B L
B B
2-Determine the force in each member of the truss and indicate whether the the
members are in tension or compression?
1 1
2 2
2 23
2 3 22 2
0
0
0
0 ( )
0 ( )
0 ( )
X X X
Y Y Y Y Y
A Y Y
F A P A P
PhF A B A B
LPh
M Ph B L BL
Ph PhF F Tension
L LF P F P Tension
F L h LF F F Compression
Lh L
3-Determine the force in each member of the truss and indicate whether the the
members are in tension or compression?
0
600
0
400
400*3 600*4 *6 0
600
200
X
X
Y
Y Y
C Y
Y
Y
F
C N
F
A C
M A
A N
C N
At joint A
At joint C
At joint D
1 2
2
2
1
30
5
4600 0
5
600*5750 ( )
43
750 450 ( )5
X
Y
F F F
F F
F N Compression
F N Tension
4
5
0
600 ( )
0
200 ( )
X
Y
F
F N Compression
F
F N Compression
3 3
0
3450 600 250 ( )
5
XF
F F N Tension
4-Determine the force in each member of the truss and indicate whether the the
members are in tension or compression?
At joint B
At joint C
At joint A
0
500 sin 45 0 707.1 ( )
0
45 0 500 ( )
X
BC BC
Y
BC BA BA
F
N F N F N Compression
F
F Cos N F F N Tension
0
707.1 45 0 500 ( )
0
707.1 45 0 500
X
CA CA
Y
Y Y
F
F Cos N F N Tension
F
C Sin N C N
0
500 0 500
0
500 0 500
X
X X
Y
Y Y
F
N A A N
F
N A A N
*
1 1 3 2
1 1 3 2 2 2
2 22 2
2 2
2 2
1 3
13
0
0
0
0
0
( )
0
X
Y
Y
Y
C Y
Y
F
P F F FCos
LP F F F
h L
F
hD P F
h L
h LF P D
h
M D L Ph F h
P h D LF
h
6-Determine the force in each member of the truss and indicate whether the the
members are in tension or compression?
1
Method of joints : we willbegainbyanalzingthe
equilibrium of joint D , and then proceed to
analyze joints C and D
1tan 26.57
2
At joint D
0
600 26.57 0
1341.64 ( )
0
X
DC
DC
Y
F
F Sin
F N Compression
F
/
/
1341.64 26.57 0
1200 ( )
At joint C
0
26.57 0 0
0
1341.64 ( )
At joint E
0
900 45 0
1272.79 ( )
0
1200 1272.79 45 0
DE
DE
X
CE CE
Y
CB
X
EB
EB
Y
EA
EA
Cos F
F N Tension
F
F Cos F
F
F N Compression
F
F Sin
F N Compression
F
Cos F
F
2100 ( )
Note , the equilibrium analysis of joint Acan be used to
determine the components of supports reaction atA
N Tension