126717676 tank heat calculation

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  • 8/13/2019 126717676 Tank Heat Calculation

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    Job ID: Client :

    Title: Tank coil design calculation Item No:1 Tank dia m 74.5

    2 Tank height m 20

    3

    4 Shell Surface area m2 4680.97

    5 = Shell Surface area ft2 50385.57

    6 Roof surface area m2 4359.16

    7 = Roof surface area ft2 46921.57

    8

    9

    10 Minimum ambient temp deg C 18 64.4 F

    11 Temperature of Insulation surface 22.89468104 73.210426 F

    12 Product temperature deg C 65 149 F

    13 Steam inlet temperature deg C 158 316.4 F

    14

    15 Surface temperature Calculation:

    16 Heat transfer coefficient in surrounding h 1.43371 BTU/hr(ft)^2.F

    17 Thickness of insulation(mineral wool) x 0.15 ft

    18 Thermal conductivity of insulation k 0.025 BTU/hr(ft).F

    19 (x/k)*h 8.60226

    20 Surface temperature deg C 22.89468104 73.21043 F

    21

    22 Steam pressure kg/cm2g 4.8

    23 Steam pressure kg/cm2A 5.833 82.964661 psia

    24 Steam saturation temperature 315.00 Deg F

    25 Enthalpy of superheated steam at supply conditions = 1183.80 BTU/lb waspwin software

    26 Enthalpy of saturated steam at supply pressure = 1183.80 BTU/lb waspwin software

    27 Enthalpy of saturated condensate at supply pressure 284.80 BTU/lb waspwin software

    28 Heat available per lb of steam = 899.00 BTU/lb

    29 Specific volume of superheated steam = 5.28541 ft3/lb waspwin software

    30 Specific volume of condensate = 0.01760 ft3/lb waspwin software

    31

    32

    33 CRUDE specific gravity 0.9

    34

    35 Heat loss from shell

    36 hc = 0.3 Dt 0.25

    37 delta t F 8.810425879

    38 hc 0.516857092 BTU/hr(ft)^2.F

    39 Calculation of radiation coeff - hr

    40 hr = 0.173 e [( T1abs/100)^4 - ( T2abs/100)^4]/(T1abs-T2abs)

    41 T1abs = 533.2104259 Rankine

    42 T2abs = 524.4 Rankine

    43 e = 0.8

    44 hr = 0.818678533 BTU/hr(ft)^2.F

    45 hc + hr = 1.335535625 BTU/hr(ft)^2.F

    46 Shell Heat Loss Q = (hc+hr)ADt = 592868.7985 BTU/hr

    47

    48 Heat loss from roof

    49 hc = 0.38 delta t^0.25 0.65468565 BTU/hr(ft)^2.F

    50 hr (remains same) = 0.818678533 BTU/hr(ft)^2.F

    51 hc+hr = 1.473364183 BTU/hr(ft)^2.F

    52 Roof Heat Loss Q = (hc+hr)ADt = 609087.2542 BTU/hr

    53

    54 Combined heat loss from shell and roof

    55 Qc = 1201956.053 BTU/hr

    56 Add 20% for combined losses from appurtenences and tank bottom

    57 and to take care of wind effects.

    58 Total Heat Loss = 1442347.263 BTU/hr

    59

    Date Date

    Description

    PROCESS CALCULATION SHEET Document No:

  • 8/13/2019 126717676 Tank Heat Calculation

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    Job ID: Client :Title: Tank coil design calculation Item No:

    1 Steam flow rate

    2 Steam required for maintaning tank temp 1604.390727 lb/hr

    3 Steam required for maitening tank temp 727.7402576 kg/hr

    4 Steam volume flow rate ( at inlets) 8479.86642 ft3/hr

    5 Steam volume flow rate ( at inlets) 357.3771185 m3/hr

    6 Number of inlets 2

    7 Flow per pipe 178.6885593 m3/hr

    8 Pipe ID 0.053 m

    9 Pipe c/s area 0.002206183 m2

    10 Steam velocity at inlets 22.49845139 m/s

    11

    12 Thermal calculations

    13

    14 Crude side convection coefficient

    15

    16 Neglecting metal tube resistance and neglecting steam superheat

    17 Hot surface temperature Th = 315.00 F

    18 Cold liquid temperature Tc = 149 F

    19 Temperature Difference Dt = 166.00 F

    20 Film temperature tf = 232.00 F

    21 Pipe OD do = 2.4 inches

    22 For a 2" pipe area per ft length 0.62832 ft2/ft

    23

    24 VGO Properties at film temperature25

    26 Thermal Conductivity of VGO k = 0.067 BTU/hr(ft)2(F/ft)

    27 VGO Density r = 55.62 lb/ft3

    28 acceleration of gravity g = 416687846 ft / hr^2

    29 VGO Specific heat c = 0.52 btu/lb/deg F

    30 Coeff. of thermal expansion b = approx 0.004310345 1/F

    31 Viscosity m =( 12 centistokes x 0.84 ) = 27 Centipoises

    32

    33 hc= 116 (( k^3 r^2 c b / m) ( Dt/do))^0.25 = 31.361 BTU/hr(ft)2F

    34

    35 Steam side heat transfer coefficient

    36 h(m^2/(k^3 r^2 g))^(1/3) = 1.51 ( 4 G / m)^ ( -1/3) 12.40 pp 265, 269 12.4537

    38 No of pipes per tank Nt = 2

    39 Assume each pipe length L = 100 ft

    40 Total condensate load W = 1604.390727 lb/hr

    41 Condensate Loading G = W/(0.5 L Nt ) = 16.04390727 lb/hr/ft

    42

    43

    44 Condensate properties at condensing temperature

    45 Viscosity m = 0.463 lb/ft/hr waspwin software

    46 thermal conductivity k = 0.3973 Btu/hr/ft2/(F/ft) waspwin software

    47 density r = 57.619 lb/ft3 waspwin software

    48 acceleration of gravity g = 416687846 ft / hr^2

    49

    50 1.51 ( 4 G / m ) (-1/3) = 0.291774432

    51 ( m^2/(k^3 r^2 g) )^(1/3) = 0.000135193

    52 Condensing film coeff h = 2158.204 Btu/hr/ft2/F

    53 Pipe OD 2.4 inches

    54 Pipe ID 2.09 inches

    55 hio = h ( ID / OD ) 1879.43627 Btu/hr/ft2/F

    56

    Date Date

    Description

    Made by / Revised by

    PROCESS CALCULATION SHEET Document No:

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    Job ID: Client :

    Title: Tank coil design calculation Item No:

    1 Overall Heat Transfer

    2 VGO side ho = 31.361 Btu/hr/ft2/F

    3 Steam side hio = 1879.43627 Btu/hr/ft2/F

    4 Clean coeff Uc = hio ho /( hio + ho ) = 30.84641207 Btu/hr/ft2/F

    5 Fouling factor Rd = 0.004

    6 Dirty Coeff UD = ( Uc / Rd ) / ( Uc + 1/Rd ) 27.45843524 Btu/hr/ft2/F

    7 Area A = Q/ ( UD Dt ) = 316.4360554 ft2

    8 Total pipe length per tank 503.6236239 ft

    9 No of pipes per tank Nt = 2

    10 Length of each pipe 251.811812 ft

    11

    12 Length of each pipe 76.75224029 m

    13 No of pipes per tank 2

    14 Total pipe length per tank 153.5044806 m

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    34 RESULTS:35

    36 Total Heat Loss = 1442347.263 BTU/hr

    37

    38 Steam required for maintaining tank temp 727.7402576 kg/hr

    39

    40 Total pipe length required 153.5044806 m

    41

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    50

    Date Date

    Description

    Made by / Revised by

    Checked by

    Approved by

    0

    PROCESS CALCULATION SHEET Document No:

  • 8/13/2019 126717676 Tank Heat Calculation

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    Job ID: Client :Rev.

    Title: Tank coil design calculation Item No:1 Tank dia m 74.5

    2 Tank height m 20

    3

    4 Shell Surface area m2 4680.97

    5 = Shell Surface area ft2 50385.57

    6 Roof surface area m2 4359.16

    7 = Roof surface area ft2 46921.57

    8

    9

    10 Minimum ambient temp deg C 18 64.4 F

    11 Temperature of Insulation surface 22.89468104 73.210426 F

    12 Product temperature deg C 65 149 F

    13 Steam inlet temperature deg C 158 316.4 F

    14

    15 Surface temperature Calculation:

    16 Heat transfer coefficient in surrounding h 1.43371 BTU/hr(ft)^2.F

    17 Thickness of insulation(mineral wool) x 0.15 ft

    18 Thermal conductivity of insulation k 0.025 BTU/hr(ft).F

    19 (x/k)*h 8.60226

    20 Surface temperature deg C 22.89468104 73.21043 F

    21

    22 Steam pressure kg/cm2g 4.8

    23 Steam pressure kg/cm2A 5.833 82.964661 psia

    24 Steam saturation temperature 315.00 Deg F

    25 Enthalpy of superheated steam at supply conditions = 1183.80 BTU/lb waspwin software

    26 Enthalpy of saturated steam at supply pressure = 1183.80 BTU/lb waspwin software

    27 Enthalpy of saturated condensate at supply pressure 284.80 BTU/lb waspwin software

    28 Heat available per lb of steam = 899.00 BTU/lb

    29 Specific volume of superheated steam = 5.28541 ft3/lb waspwin software

    30 Specific volume of condensate = 0.01760 ft3/lb waspwin software

    31

    32

    33 CRUDE specific gravity 0.9

    34

    35 Heat loss from shell

    36 hc = 0.3 Dt 0.25

    37 delta t F 8.810425879

    38 hc 0.516857092 BTU/hr(ft)^2.F

    39 Calculation of radiation coeff - hr

    40 hr = 0.173 e [( T1abs/100)^4 - ( T2abs/100) 4]/(T1abs-T2abs)

    41 T1abs = 533.2104259 Rankine

    42 T2abs = 524.4 Rankine

    43 e = 0.8

    44 hr = 0.818678533 BTU/hr(ft)^2.F

    45 hc + hr = 1.335535625 BTU/hr(ft)^2.F

    46 Shell Heat Loss Q = (hc+hr)ADt = 592868.7985 BTU/hr

    47

    48 Heat loss from roof

    49 hc = 0.38 delta t^0.25 0.65468565 BTU/hr(ft)^2.F

    50 hr (remains same) = 0.818678533 BTU/hr(ft)^2.F

    51 hc+hr = 1.473364183 BTU/hr(ft)^2.F

    52 Roof Heat Loss Q = (hc+hr)ADt = 609087.2542 BTU/hr

    53

    54 Combined heat loss from shell and roof

    55 Qc = 1201956.053 BTU/hr

    56 Add 20% for combined losses from appurtenences and tank bottom

    57 and to take care of wind effects.

    58 Total Heat Loss = 1442347.263 BTU/hr

    59

    Date Date

    Description Sht

    PROCESS CALCULATION SHEET Document No:

  • 8/13/2019 126717676 Tank Heat Calculation

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    Job ID: Client :Rev.

    Title: Tank coil design calculation Item No: 0

    1 Steam flow rate

    2 Steam required for maintaning tank temp 1604.390727 lb/hr

    3 Steam required for maitening tank temp 727.7402576 kg/hr

    4 Steam volume flow rate ( at inlets) 8479.86642 ft3/hr

    5 Steam volume flow rate ( at inlets) 357.3771185 m3/hr

    6 Number of inlets 2

    7 Flow per pipe 178.6885593 m3/hr

    8 Pipe ID 0.053 m

    9 Pipe c/s area 0.002206183 m2

    10 Steam velocity at inlets 22.49845139 m/s

    11

    12 Thermal calculations

    13

    14 Crude side convection coefficient

    15

    16 Neglecting metal tube resistance and neglecting steam superheat

    17 Hot surface temperature Th = 315.00 F

    18 Cold liquid temperature Tc = 149 F

    19 Temperature Difference Dt = 166.00 F

    20 Film temperature tf = 232.00 F

    21 Pipe OD do = 2.4 inches

    22 For a 2" pipe area per ft length 0.62832 ft2/ft

    23

    24 VGO Properties at film temperature25

    26 Thermal Conductivity of VGO k = 0.067 BTU/hr(ft)2(F/ft)

    27 VGO Density r = 55.62 lb/ft3

    28 acceleration of gravity g = 416687846 ft / hr^2

    29 VGO Specific heat c = 0.52 btu/lb/deg F

    30 Coeff. of thermal expansion b = approx 0.004310345 1/F

    31 Viscosity m =( 12 centistokes x 0.84 ) = 27 Centipoises

    32

    33 hc= 116 (( k^3 r^2 c b / m) ( Dt/do))^0.25 = 31.361 BTU/hr(ft)2F

    34

    35 Steam side heat transfer coefficient

    36 h(m^2/(k^3 r^2 g))^(1/3) = 1.51 ( 4 G / m)^ ( -1/3) 12.40 pp 265, 269 12.4537

    38 No of pipes per tank Nt = 2

    39 Assume each pipe length L = 100 ft

    40 Total condensate load W = 1604.390727 lb/hr

    41 Condensate Loading G = W/(0.5 L Nt ) = 16.04390727 lb/hr/ft

    42

    43

    44 Condensate properties at condensing temperature

    45 Viscosity m = 0.463 lb/ft/hr waspwin software

    46 thermal conductivity k = 0.3973 Btu/hr/ft2/(F/ft) waspwin software

    47 density r = 57.619 lb/ft3 waspwin software

    48 acceleration of gravity g = 416687846 ft / hr^2

    49

    50 1.51 ( 4 G / m ) (-1/3) = 0.291774432

    51 ( m^2/(k^3 r^2 g) )^(1/3) = 0.000135193

    52 Condensing film coeff h = 2158.204 Btu/hr/ft2/F

    53 Pipe OD 2.4 inches

    54 Pipe ID 2.09 inches

    55 hio = h ( ID / OD ) 1879.43627 Btu/hr/ft2/F

    56

    Date Date

    Description Sht

    Made by / Revised by 2

    PROCESS CALCULATION SHEET Document No:

    0

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    Job ID: Client : Rev.

    Title: Tank coil design calculation Item No: 0

    1 Overall Heat Transfer

    2 VGO side ho = 31.361 Btu/hr/ft2/F

    3 Steam side hio = 1879.43627 Btu/hr/ft2/F

    4 Clean coeff Uc = hio ho /( hio + ho ) = 30.84641207 Btu/hr/ft2/F

    5 Fouling factor Rd = 0.004

    6 Dirty Coeff UD = ( Uc / Rd ) / ( Uc + 1/Rd ) 27.45843524 Btu/hr/ft2/F

    7 Area A = Q/ ( UD Dt ) = 316.4360554 ft2

    8 Total pipe length per tank 503.6236239 ft

    9 No of pipes per tank Nt = 2

    10 Length of each pipe 251.811812 ft

    11

    12 Length of each pipe 76.75224029 m

    13 No of pipes per tank 2

    14 Total pipe length per tank 153.5044806 m

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    34 RESULTS:35

    36 Total Heat Loss = 1442347.263 BTU/hr

    37

    38 Steam required for maintaining tank temp 727.7402576 kg/hr

    39

    40 Total pipe length required 153.5044806 m

    41

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    4647

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    Date Date

    Description Sht

    Made by / Revised by 3

    Checked by of

    Approved by 3

    0

    PROCESS CALCULATION SHEET Document No:

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