7.2 factoring using the distributive property cord math mrs. spitz fall 2006

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7.2 Factoring Using the Distributive Property CORD Math Mrs. Spitz Fall 2006

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Page 1: 7.2 Factoring Using the Distributive Property CORD Math Mrs. Spitz Fall 2006

7.2 Factoring Using the Distributive Property

CORD MathMrs. SpitzFall 2006

Page 2: 7.2 Factoring Using the Distributive Property CORD Math Mrs. Spitz Fall 2006

Objectives:

• Use the GCF and the distributive property to factor polynomials.

• Use the information you are gaining now to get into Algebra II next year or test Math 121, so you can get into a decent college next year.

Page 3: 7.2 Factoring Using the Distributive Property CORD Math Mrs. Spitz Fall 2006

Assignment

• Pg. 263 #4-35 all

Page 4: 7.2 Factoring Using the Distributive Property CORD Math Mrs. Spitz Fall 2006

Introduction

• In chapter 6, you multiplied a polynomial by a monomial by using the distributive property. You can also reverse the process and express a polynomial in factored form by using the distributive property.

Page 5: 7.2 Factoring Using the Distributive Property CORD Math Mrs. Spitz Fall 2006

Yeah, so what does that mean?

• Multiplying Polynomials:

• Factoring polynomials:

yxy

yxyxy

xzxyzyx

baba

612

)2(3)4(3)24(3

)(

33)(3

)24(3

)2(3)4(3612

)(

)(333

xy

yxyyxy

zyxxzxy

baba

The expression 3y(4x + 2) at the right above is not considered fully factored since the polynomial 4x + 2 can be factored as 2(2x + 1). The completely factored form of 12xy and 6y would be 6y(2x + 1). Factoring a polynomial or finding the factored form of a polynomial means to find its completely factored form.

Page 6: 7.2 Factoring Using the Distributive Property CORD Math Mrs. Spitz Fall 2006

Ex. 1: Use the distributive property to factor 10y2 + 15y

• First, find the greatest common factor for 10y2 and 15y

• Then, express each term as the product of the GCF and its remaining factors.

yy

yyy

5315

5210 2

The GCF is 5y.

)32(5

)3(5)2(51510 2

yy

yyyyy

Page 7: 7.2 Factoring Using the Distributive Property CORD Math Mrs. Spitz Fall 2006

Ex. 2: Factor 21ab2 – 33a2bc

• First, find the greatest common factor for 21ab2 and 33a2bc

• Then, express each term as the product of the GCF and its remaining factors.

The GCF is 3ab.

cbaabca

bbaab

11333

73212

2

)117(3

)11(3)7(33321 22

acbab

acabbabbcaab

Page 8: 7.2 Factoring Using the Distributive Property CORD Math Mrs. Spitz Fall 2006

Ex. 3: Factor 6x3y2 + 14x2y + 2x2

• First, find the greatest common factor for 6x3y2 and 14x2y and 2x2

• Then, express each term as the product of the GCF and its remaining factors.

The GCF is 2x2.

xxx

yxxyx

yyxxxyx

22

7214

326

2

2

23

)173(2

)1(2)7(2)3(2214622

22222223

yxyx

xyxxyxxyxyx