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Contents I
Preface III
Scientif ic Commit tee IV
Fundamental Constants, Equations and Useful Formulas V
Theoretical Problems
Problem 1 Separation and Identification of Ions 1 Problem 2 Preparation and Applications of Radioisotopes 2 Problem 3 Ion Exchangers 3
Problem 4 Determination of Calcium Ion by Precipitation Followed by Redox Titration 7Problem 5 Nitrogen in Wastewater 8
Problem 6 Use of Isotopes in Mass Spectrometry 10Problem 7 Atomic Orbitals 11Problem 8 Intermolecular Forces 11
Problem 9 Crystal Packing 13Problem 10 Applications of Transition Metals 14Problem 11 Electrochemistry of Inorganic Compounds 15Problem 12 Metal Carbonyl Compounds 16Problem 13 Carbocation and Aromaticity 18Problem 14 Photochemical Ring Closure and Opening 19Problem 15 Stereochemistry 21
Problem 16 Organic Synthesis 24 Problem 17 Spectroscopy and Polymer Chemistry 26
Problem 18 Crown Ether and Molecular Recognition 30Problem 19 Enzyme Catalysis 32Problem 20 Work in Thermodynamics 33
Problem 21 Kinetics Atmospheric Chemistry 33Problem 22 Kinetics and Thermodynamics 33Problem 23 Phase Diagram 34
Problem 24 Standard Deviation in One-Dimensional Quantum Mechanics 35Problem 25 A Particle in a 2-D Box Quantum Mechanics 36Problem 26 Spectral Analyzer 37
Problem 27 Time-of-Flight Mass Spectrometer 39
Practical Problems
Safety Rules 41 Problem 28 Identification of Unknown Solid Samples 47 Problem 29 Identification of Unknown Solutions (I) Spot Test without Electrolysis 48
Problem 30 Identification of Unknown Solutions (II) Spot Test with Electrolysis 49Problem 31 Quantitative Analysis of Ascorbic Acid in a Vitamin C Tablet 50Problem 32 Determination of an Equilibrium Constant 53
Problem 33 Preparation of Acetylsalicylic Acid 55Problem 34 Analysis of Aspirin Tablets 57
Problem 35 Resolution of ()--Methylbenzylamine and Determination of the Optical Purity58
Answers to Problems
Answer 1 Separation and Identification of Ions 61 Answer 2 Preparation and Applications of Radioisotopes 64 Answer 3 Ion Exchangers 65 Answer 4 Determination of Calcium Ion by Precipitation Followed by Redox Titration 66
Answer 5 Nitrogen in Wastewater 68Answer 6 Use of Isotopes in Mass Spectrometry 68
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Answer 7 Atomic Orbitals 69Answer 8 Intermolecular Forces 69
Answer 9 Crystal Packing 71 Answer 10 Applications of Transition Metals 71
Answer 11 Electrochemistry of Inorganic Compounds 72Answer 12 Metal Carbonyl Compounds 73
Answer 13 Carbocation and Aromaticity 75 Answer 14 Photochemical Ring Closure and Opening 75
Answer 15 Stereochemistry 76Answer 16 Organic Synthesis 77Answer 17 Spectroscopy and Polymer Chemistry 78Answer 18 Crown Ether and Molecular Recognition 79
Answer 19 Enzyme Catalysis 79 Answer 20 Work in Thermodynamics 81 Answer 21 Kinetics Atmospheric Chemistry 82
Answer 22 Kinetics and Thermodynamics 82Answer 23 Phase Diagram 83Answer 24 Standard Deviation in One-Dimensional Quantum Mechanics 84
Answer 25 A Particle in a 2-D Box Quantum Mechanics 85Answer 26 Spectral Analyzer 85
Answer 27 Time-of-Flight Mass Spectrometer 85
AppendixI: Minutes of the Steering Committee Meeting 86
Appendix II: Information for Mentors at the International Chemistry Olympiad 90
Appendix III: International Chemistry Olympiad Appendix C (updated 2004)-Syllabus 100
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Preface
This booklet contains preparatory problems and Information for Mentors at the
International Chemistry Olympiad approved by the Taipei Dec. 2-5 2004 Steering
Committee Meeting for the 37th International Chemistry Olympiad in 2005.
According to the Syllabus of the IChO, the problems were designed to emphasize the
discovery and trend of the global chemistry field, and to highlight the unique chemical
researches in Taiwan including natural resources, medicines, energy, materials and
environment.
In spite of proof reading efforts, you will probably find some mistakes, and we will
highly appreciate your critical remarks and constructive comments.
Finally, we hope that the students will benefit from this booklet as they prepare for the
competition in the 37th 2005 IChO. Welcome to Formosa Taiwan and welcome to
Taipei! Good luck!
Prof. Tai-Shan Fang, Ph.D.
Secretariat, 37th 2005 IChO
Department of Chemistry
National Taiwan Normal University
88 Sec. 4, Ting-Chou Road Taipei, Taiwan 116
Tel: +886-2-29350749 ext. 423
Mobile: +886-921882061
Tel & Fax: +886-2-29309074 / +886-2-29307327
E-mail: 2005icho@sec.ntnu.edu.tw
http://icho.chem.ntnu.edu.tw
III
mailto:2005icho@sec.ntnu.edu.twhttp://icho.chem.ntnu.edu.tw/http://icho.chem.ntnu.edu.tw/mailto:2005icho@sec.ntnu.edu.tw -
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37th International Chemistry Olympiad
Taipei, Taiwan
July 16 - 25, 2005
Scientific Committee
President:Dr. Chan, Sunney I. Academia Sinica
Coordination:Dr. Peng, Shie-Ming National Taiwan University
Manager: Dr. Fang, Tai-Shan National Taiwan Normal University
Secretary: Dr. Chang, I-Jy National Taiwan Normal University
Theoretical Section
Dr. Fang, Jim-Min National Taiwan University
Dr. Her, Guor-Rong National Taiwan University
Dr. Jin, Bih-Yaw National Taiwan University
Dr. Leung, Man-Kit National Taiwan University
Dr. Lin, Cheng-Huang National Taiwan Normal University
Dr. Lin, King-Chuen National Taiwan University
Dr. Lin, Sheng-Hsien Academia Sinica
Dr. Lin, Ying-Chih National Taiwan UniversityDr. Lu, Kuang-Lieh Academia Sinica
Dr. Peng, Shie-Ming National Taiwan University
Dr. Shih, Jeng-Shong National Taiwan Normal University
Dr. Whang, Chen-Wen Tunghai University
Dr. Wong, Ken-Tsung National Taiwan University
Practical Section
Dr. Chang, I-Jy National Taiwan Normal University
Dr. Chen, Chien-Tien National Taiwan Normal University
Dr. Chen, Kwunmin National Taiwan Normal University
Dr. Fang, Tai-Shan National Taiwan Normal University
Dr. Horng, Jhy-Ming National Taiwan Normal University
Dr. Shiau, George T. College Entrance Examination Center
Dr. Yao, Ching-Fa National Taiwan Normal University
Dr. Yeh, Ming-Chang P. National Taiwan Normal University
Dr. Mou, Chung-Yuan National Taiwan University
Dr. Shieh, Ming-Huey National Taiwan Normal University
Lecturer She, Jui-Lin National Taiwan University
IV
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Fundamental Constants, Equationsand Conversion Factors
Atomic mass unit 1 amu = 1.6605 10-27kg
Avogadros number N= 6.02 1023
mol-1
Boltzmanns constant k = 1.38065 10-23
J K-1
Electron charge e = 1.6022 10-19
C
Faradays constant F = 9.6485 104
C mol-1
Mass of electron me = 9.11 10-31
kg
Mass of neutron mn = 1.67492716 10-27
kg
Mass of proton mp = 1.67262158 10-27
kg
Plancks constant h = 6.63 10-34
J s
Speed of light c = 3 108
m s-1
Nernst equation (T = 298 K) E =E(0.0592 / n) log K
Clausius-Clapeyron equation lnP= -Hvap/ RT + B
Ideal gas equation PV =nRT
De Broglie relation =h / mvFree energy G =H - TS
Arrhenius equation k =Ae-Ea/RT
E = hv
U = q + w
G = G+RTlnQ G = - nFE
w = - PV
Standard atmosphere = 101325 Pa
RT at 298.15 K = 2.4790 kJ mol-1
Pi ( = 3.1415927
1 = 10-10
m
1 W = 1 J s-1
1 J = 1 kg m2
s-2
1 cal = 4.184 J
1 Pa = 1 kg m-1
s-2
= 1 N m-2
1 bar = 105
Pa
1 atm = 1.01325 105
Pa = 760 mmHg (torr)
1 eV / molecule = 96.4853 kJ mol-1
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VI
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Problem 1: Separation and Identification of Ions
A student studied the chemical reactions between cations, A2+
, B2+
, C2+
, D2+
, E2+
in nitrate
aqueous solutions and anions X-, Y
-, Z
-, Cl
-, OH
- in sodium aqueous solutions as well as an
organic ligand L. Some precipitation (ppt) products and colored complexes were found asshown in Table 1:
Table 1
X-
Y-
Z-
Cl-
OH- L
A2+ *** *** *** *** White
ppt***
B2+ Yellow
pptWhite
ppt*** *** *** BLn
2+
Complex
C2+ White
ppt
Brown
ppt
Brown
ppt
White
ppt
Black
ppt
CL2+
, CL22+
ComplexesD
2+ *** Redppt
*** *** *** ***
E2+ *** Red
pptWhite
ppt*** *** ***
*** = No reaction,
1-1 Design a flow chart for the separation of A2+
, B2+
, C2+
, D2+
, E2+
in a nitrate aqueous solution
by using various aqueous solutions containing anions X-, Y
-, Z
-, Cl
-, OH
-, respectively,
as testing reagents. Write down the product of the chemical reaction for each step in theflow chart.
1-2 Design a flow chart for the separation of anions X-, Y
-, Z
-, Cl
-, OH
- in a sodium aqueous
solution by using various aqueous solutions containing cations A2+
, B2+
, C2+
, D2+
, E2+
,respectively, as testing reagents. Write down the product of the chemical reaction for eachstep in the flow chart.
1-3 The white ppt BY2and brown ppt CY2have low solubilities in water with solubility products
(Ksp) of 3.20 10-8
and 2.56 10-13
, respectively at 25oC.
1-3-1 Calculate the solubility of BY2.
1-3-2 Calculate the solubility of CY2.
1-4 A series of solutions containing B2+
and L were prepared in 50 mL volumetric flasks by
adding a 2 mL of 8.2 10-3
M solution of B2+
to each flask. Varying amounts of a 1.0
10-2
M solution of the ligand L are added to each flask. The solution in each volumetricflask was diluted with water to the mark (50 mL). The absorbance (A) of Complex BLnwasmeasured at 540 nm for each solution in a 1.0 cm cell. The data are summarized in Table
2. (Both B2+
and ligand L show no absorption (A = 0) at 540 nm.) [Mole RatioMethod]
1-4-1 Calculate the value of n (Coordination number) in the complex BLn2+
.
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1-4-2 Calculate the formation constant (Kf) of complex BLn2+
.
Table 2
Added L
VL(mL)
Absorbance
(A)
Added L
VL(mL)
Absorbance
(A)1.00 0.14 2.00 0.263.00 0.40 4.00 0.485.00 0.55 6.00 0.607.00 0.64 8.00 0.669.00 0.66 10.00 0.66
1-5 Solid NaY (soluble) was added very slowly to an aqueous solution containing 0.10 M in B2+
and 0.05 M in C2+
prepared from their respective nitrate aqueous salts.
1-5-1 Which cation (B2+
or C2+
) precipitates first? What is the [Y-] when this happens? (Ksp=
3.20 10
-8
for BY2and Ksp = 2.56 10
-13
for CY2, at 25
o
C.) [Separation by Precipitation]
1-5-2 What are the concentrations of Y-and the remaining cation when complete precipitation
of the first precipitating cation has occurred (assume that the concentration of the first
cation in solution after complete precipitation is 10-6
M)? Is it possible to separate B2+
and C2+
by the precipitation method with Y-ion as a precipitating agent?
Problem 2: Preparation and Applications of Radioisotopes
Radioisotopes can be used in medical diagnosis and therapy as well as industrial analysis.Many radioisotopes, e.g. P-32 (Mass number = 32) and Co-60 can be generated by theirradiation of neutrons in a nuclear reactor. However, some radioisotopes in nature, e.g. C-14and T-3 (Tritium), can be produced by the bombardment of nitrogen N-14 atoms in theatmosphere by neutrons in the cosmic ray. (Atomic numbers of T & H, C, N, P, Co and neutron
are 1, 6, 7, 15, 27 and 0, respectively. P-32 can be denoted as )
2-1 Write down the equations for the nuclear reactions for the production of C-14 and T-3 by
the bombardment of nitrogen N-14 atoms in the atmosphere with neutrons in the cosmicray.
Radioisotope C-14 can be used as a reagent in C-14 dating. The activity (A) in terms of countsper minute (cpm) of the radioisotope C-14 is proportional to the number (N) of C-14 atoms asfollows : [C-14 Dating]
A = N (1)
Where is the detection coefficient of a detector for C-14 and is the decay constant of C-14.An initial amount (No) of C-14 can be reduced to the amount (N) of C-14 by decay after a giventime (t) as follows:
N = Noe-t (2)
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The half life (t1/2) of C-14 is 5730 years which is defined as the time required for 50% of thenumber of the radioisotope C-14 atoms in a sample to undergo decay, that is N = 1/2 N o. It iswell known that activity (Ao) of C-14 in a living animal or plant is kept to be around 16.5 cpm/g ofcarbon. After the death of the animal or plant, the activity (cpm/g of carbon) of C-14 in the bodyof the living animal or plant is decreased by the time passed.
2-2-1 Give the equation showing the relation between the original activity (Ao) and final activity(A) as function of time for a living animal or plant.
2-2-2 The activity of C-14 in an ancient wood boat is found to be 10.2 cpm/g of carbon.Calculate the age of the ancient boat.
2-3 The radioisotope P-32 is a very important leveling reagent for biological research and canbe produced by the bombardment of P-31 by a neutron in a nuclear reactor. Theproduction rate (Rp) of P-32 can be estimated as :
Rp = N (3)
Where N and are the number of atoms and neutron capture cross section ( 0.9 x 10-24
cm2/atom) of P-31, respectively, and is the neutron flux (neutron / (cm
2sec)) of the nuclearreactor. If the detection efficient () of the detector for P-32 is 1.0, the decay rate (Rd) and theactivity (A) of P-32 in the nuclear reactor can be approximately estimated as a function of thenumber (N*) of P-32 atoms as follows:
Rd = N ( e-t
) (4)
and A = N* = Rp Rd (5)
Where is the decay constant of P-32, t is the neutron irradiation time in the nuclear reactor andthe half life (t1/2) of P-32 is 14.3 days.
2-3-1 A 10 mg sample of pure H3PO4is irradiated by neutrons with a neutron flux of 1.00 x 1013
n cm-2
sec-1
for one hour in a nuclear reactor. Calculate the activity of the sample in cps
(counts / second) and Ci. (Ci = Curie, 1 Ci 3.7 x 1010
cps, atomic weight: H=1, P=31,O=16)
2-3-2 The radioisotope P-32 can be used to measure the volume of water in a pool or the bloodvolume of an animal. A 2.0 mL solution of 1.0 Ci/mL P-32 was injected into a pool.After mixing well, the activity of 1.0 mL of water in the pool was found to be 12.4 cps(counts / second). Calculate the volume of water (L) in the pool. (Ci = Curie, 1 Ci 3.7x 10
10cps)
Problem 3: Ion Exchangers
Ion exchangers can be employed to adsorb and separate cations and anions. They can be
prepared from organic or inorganic materials. An organic, cationic ion exchanger can besynthesized by the polymerization of styrene / divinyl benzene followed by sulfonation with H2SO4,
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as shown in Scheme 1:
H 2SO 4
C CCC
C CCCSO 3
-
H
+
[ ca t ion ic exch anger ]
R-H
+
C C
+
C C
C C
N a2S 2O 8
C CCC
C CCC
[ polymer ]
[Scheme 1]
Cationic ion exchanger (denoted as R-H
+) can be employed to adsorb the cations, M
+,the
chemical reaction and the equilibrium constant Kc as well as the distribution coefficient Kd can beexpressed as follows:
R-H
++ M
+= RM + H
+, Kc = [RM][H
+] / ([M
+][RH]) (1)
Kd= [RM] / [M+] (2)
The cationic ion exchanger R-H
+can be transformed into the ion exchanger R
-M
+or R
-M
z+by the
reaction of R-H
+with a metal hydroxide (M(OH)z). The approximate equations are:
R-H
++ MOH = R
-M
++ H2O (3)
and z R
-
H
+
+ M(OH)z= (R
-
)zM
+
+ z HCl (4)
3-1 A cationic ion exchanger R-Na
+was employed to remove CaCl2in tap water,
3-1-1 Give the chemical equation for the adsorption of Ca2+
by the cationic ion exchanger
R-Na
+.
3-1-2 If another ion exchanger R-H
+ is employed instead of R
-Na
+. (a) Give the chemical
equation for the adsorption of Ca2+
by the ion exchanger R-H
+ and (b) tell which ion
exchanger, R-H+or R-Na+, is suitable for drinking purpose and give the reason.
3-2 An organic, anionic ion exchanger (denoted as R+Cl
-) can also be synthesized by the
polymerization of styrene / divinyl benzene followed by the reaction of the resulting polymer,
poly (styrene / divinyl benzene), with the Lewis acid AlCl3and tertiary amine NR3, as shownin Scheme 2:
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The anionic ion exchanger R+OH
- can be obtained from the chemical reaction of the ion
exchanger R+Cl
-with 3.0 M of NaOH by the equation:
R+
Cl-
+ NaOH = R+
OH-
+ NaCl (5)
3-2-1 Tell how the removal of H+ from a solution of HCl can be achieved with an anionic ionexchanger and give the chemical equation for the process.
3-2-2 Tell how the amount of SO42-
in tap water can be estimated by using an anionic ion
exchanger R+OH
-. Give all of the chemical equations involved in the process.
The capacity (S) of the cationic ion exchanger R-H
+ for an adsorbed ion can be expressed in
moles of the adsorbed ion per gram of the ion exchanger in 1.0 mL of aqueous solution and canbe calculated by using the following equation:
S = ([RM] + [RH]) 10-3
(6)
The capacity (S) of the cationic ion exchanger R-H
+ for M
+ ions in an aqueous solution can be
estimated from the equilibrium constant Kc, the distribution coefficient Kd and the concentrations
of M+and H
+ions in the aqueous solution.
3-3 Show that the relationship between Kd, S, Kc, [M+] and [H
+] as shown by the equation:
1 / Kd = [M+] / (S(10
3)) + [H
+] / (S Kc(10
3)) (7)
3-4 Ion exchangers can be employed as stationary phase materials in liquid chromatography to
adsorb and separate various ions. For example, the anionic ion exchanger R+OH
-can be
used to separate X-and Y
- ions with the eluent NaOH. The chromatogram for separation
of X-and Y
-ions using a 30 cm of anionic ion exchange column is shown in Figure 1.
Where t1, t2and toare the retention times (tR) for X-, Y
-and the pure eluent (NaOH) to traverse
the column, respectively. 1 and 2 are the peak-widths for X- and Y
-. The number of
theoretical plates N and the plate height H (height equivalent of the theoretical plates) of thecolumn can be estimated as shown below:
N = 16 (tR /)2
(8)and H = L / N (9)
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X-
tR
t2
1 5
Y-
1 0
t1
t0
14.010.01.0
Retention Time / min
Figure 1. Liquid Chromatogram for X-and Y
-ions
where L is the length of the column. The resolution (R) of the column and the separation factor
() for X-and Y
-also can be estimated using the following equations:
R = 2 (t2- t1) / (1+ 2) (10)
and = (t2 - t0) / (t1 - t0) (11)
3-4-1 Calculate the average number of theoretical plates N of the column.
3-4-2 Calculate the plate height H of the column.
3-4-3 Calculate the resolution (R) of the column for X-and Y
-ions.
3-4-4 Calculate the separation factor () for X-and Y
-ions.
3-5 Some ion exchangers are derived from inorganic matters. Zeolites [(Mz+
)(Al2O3)m / (SiO2)n]
(Mz+
= Na+, K
+ or Ca
2+, Mg
2+) are the best known examples of inorganic ion exchangers.
Some examples of Zeolites are shown in Figure 2.
A Na+-Zeolite (denoted as Z-Na
+) with a pore size of 13 is an important ion exchanger for the
removal of Ca2+
or Mg2+
ion from tap water. Zeolites with definite pore sizes also behave as
highly selective adsorbents for various molecules, e.g. H2O and iso-butane. Thus, the zeolite
can be used as a molecular sieve. The zeolite can also be used as a catalyst by adsorption of a
petroleum component, e.g. iso-butane, in petroleum resulting in the enhancement of rate of the
cracking of the adsorbed component.
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Figure 2. Various types of Zeolites
3-5-1 Give the chemical equation for the removal of Ca2+
ions from tap water with Z-Na+zeolite
ion exchange column.
3-5-2 Give the chemical equation for the adsorption of K+
with Z-Na+
zeolite.
Problem 4: Determination of Calcium Ion by Precipi tation Followed by Redox
Titration
The calcium content of an aqueous sample can be determined by the following procedure:
Step 1 A few drops of methyl red are added to the acidified aqueous sample, followed by
thorough mixing with Na2C2O4solution.
Step 2 Urea ((NH2)2CO) is added and the solution gently boil until the indicator turns yellow
(this typically takes 15 min). CaC2O4precipitates out.
Step 3 The hot solution is filtered and the solid CaC2O4 is washed with ice-cold water to
remove excess C2O42-
ions.
Step 4 The insoluble CaC2O4 is dissolved in hot 0.1 M H2SO4 to give Ca2+
ions and H2C2O4.
The dissolved H2C2O4is titrated with standardized KMnO4solution until the purple end
point is observed.
Relevant reactions and equilibrium constants:
CaC2O4(s)Ca2+(aq)+ C2O42-(aq) Ksp= 1.30x10-8
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Ca(OH)2(s)Ca2+
(aq)+ 2OH-(aq) Ksp= 6.50x10
-6
H2C2O4(aq)HC2O4-(aq)+ H
+(aq) Ka1= 5.60x10
-2
HC2O4-(aq)C2O4
2-(aq)+ H
+(aq) Ka2= 5.42x10
-5
H2O H+
(aq)+ OH-(aq) Kw= 1.00x10
-14
4-1 Write a balanced equation for the reaction that takes place upon the addition of urea (Step
2).
4-2 The calcium content of a 25.00 mL aqueous sample was determined using the above
procedure and found to require 27.41 mL of a 2.50 x 10-3
M KMnO4solution in the final step.
Find the concentration of Ca2+
ions in the sample.
4-3 Calculate the solubility of CaC2O4 in an aqueous solution buffered at pH 4.0. (Neglect
activity coefficients)
In the above analysis, a possible source of error was neglected. The precipitation of CaC2O4in
Step 1 will be incomplete if an excess of C2O42-
ions is added, due to the following reactions:
Ca2+
(aq)+ C2O42-
(aq)CaC2O4(aq) Kf1= 1.0 x 103
CaC2O4(aq)+ C2O42-(aq)Ca(C2O4)22-(aq) Kf2= 10
4-4 Calculate the equilibrium concentrations of Ca2+
and C2O42-
ions in solution after optimal
precipitation of CaC2O4is reached.
4-5 Calculate the concentrations of H+and Ca
2+in a saturated solution of CaC2O4. (Neglect
activity coefficients. Any assumptions made during calculation must be clearly stated.)
Problem 5: Nitrogen in Wastewater
In natural water and waste water, the forms of nitrogen of greatest interest are nitrate, nitrite,
ammonia, and organic nitrogen. All these forms of nitrogen, as well as nitrogen gas, are
biochemically interconvertible and are components of the nitrogen cycle.
5-1 The Macro-kjeldahl method, in combination with a titration method, is often used in the
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determination of organic nitrogen in wastewater. In the first step, H2SO4, K2SO4, and
HgSO4are added to the sample solution. After digestion, the solution is neutralized by the
addition of concentrated NaOH. The gas liberated by the treatment is then distilled into a
solution of excess boric acid and the latter subsequently titrated with 0.02 N H 2SO4.
5-1-1 Identify the product formed in the digestion step.
5-1-2 Identify the gas liberated upon the addition of NaOH.
5-1-3 Write a balanced equation for the reaction between the liberated gas and boric acid.
5-1-4 Write a balanced equation for the final titration step.
5-1-5 Which of the following indicators is most suitable to be used in the final titration step:
Methyl orange (transition range pH 3.1 - 4.4), phenolphthalein (transition range pH 8.0 -
9.6) is chosen as the indicator. Explain your choice.
5-2 Nitrite is known to cause the illness methemoglobinemia in infants. In the laboratory,
nitrite can be determined by a colorimetric method. The method requires the preparation
of a series of standard nitrite solutions. However, nitrite is readily oxidized in the presence
of moisture and hence standardization of the stock nitrite solution is required in order to
achieve high accuracy in the subsequent analysis. The standardization is carried out by
adding a known excess of standard KMnO4solution and H2SO4solution are added into the
nitrite stock solution. The purple color of the solution due to the presence of excess
permanganate was subsequently discharged by the addition of a known quantity of
Na2C2O4and the mixture back titrated with standard permanganate solution.
5-2-1 Write a balanced equation for the reaction of the nitrite solution with KMnO4.
5-2-2 Write a balanced equation for the back titration.
5-2-3 Write a mathematical equation for calculation of nitrogen concentration.
A: mg/ml N in stock NaNO2solution
B: total ml standard KMnO4used
C: molarity of standard KMnO4
D: total ml standard Na2C2O4solution
E: molarity of standard Na2C2O4
F: ml stock NaNO2solution taken for titration
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Problem 6: Use of Isotopes in Mass Spectrometry
Many elements in the periodic table have more than one isotope. The atomic mass of an
element is calculated based on the relative abundance of the isotopes. As an example, the
atomic mass of chlorine is about 35.5 because the abundance of Cl35
is about three times theabundance of Cl
37. In mass spectrometry, instead of average atomic mass, the isotope peaks
are observed. (Cl35
75.77%, Cl37
24.23%, C1298.9%, C
131.1%, Br79
50.7%, Br81
49.3%)
Isotopes are quite useful in quantitative mass spectrometry.
6-1 In addition to the retention time (migration time), the ratio of M and M+2 ions was used as
the qualitative criteria in the analysis of 2,3,7,8, tetra chlorinated dioxin (2,3,7,8-TCDD) by
gas chromatography / mass spectrometry. Calculate the theoretical ratio of the two ions.The intensities of the isotopic species can be found by applying the following formula:
(a+b)n, where a is the relative abundance of the light isotope, b is the relative abundance of
the heavy isotope, and n is the number of chlorine atoms present.
6-2 Molecular ion is often selected in quantitative analysis. The intensity of the molecular ion
needs to be corrected if the signal is interfered by other compounds. In the analysis of a
non-halogenated compound with a molecular weight of 136, the molecular ion was selected
for quantitative analysis. Propose a mathematical equation for calculation the corrected
signal, if the analyte co-elutes (same migration time) with the compound n-butyl bromide.
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Problem 7: Atomic Orbitals
One way to describe the shape of atomic orbitals of H-atom is in terms of the nodal surfaces, or
nodes, where the electron has zero probability. According to wave mechanics, the number ofnodes increases as n increases. For given set of orbitals nlm, there are n-l-1 spherical nodes,
l angular nodes.
7-1 Describe the electron probability distribution for the 1s, 2s and 3s orbitals. How many
nodes does each orbital have respectively?
7-2 Describe the electron probability distribution for the 2pzand 3pzorbitals. How many nodes
does each orbital have respectively?
7-3 Imagine that you are traveling along the z axis, beginning your journey at a distance far
from the nucleus on the z axis, passing through the nucleus to a distant point on the z axis.
How many nodal surfaces would you pass through for each of the following orbitals: 1s, 2s,
3s, 2pzand 3pz.
Problem 8: Intermolecular Forces
Intermolecular forces occur between, rather than within, molecules. Ion-dipole interaction and
dipole-dipole interaction are two common types of intermolecular forces.
Part 1: Ion-Dipole Interactions
The bonding of an ion, such as Na+, with a polar molecule, such as water, is an example of an
ion-dipole interaction. Shown below are a sodium ion, a water molecule, and a crown ethercompound.
O
O
O
O
O
O
H2ONa+
8-1-1 Draw the geometrical structure of the product resulting from the interaction between the
sodium ion and water molecules.
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8-1-2 Draw a diagram showing the interaction between the sodium ion and the crown ether
molecule.
Part 2: Dipole-Dipole Interactions
A hydrogen bond may be regarded as a particular kind of dipole-dipole interaction. Strong
hydrogen bonding forces are seen among molecules in which hydrogen is bound to a highly
electronegative atom, such as nitrogen, oxygen, or fluorine.
OH+N
Compared to other intermolecular forces, hydrogen bonds are relatively strong; their energies are
of the order of 15 to 40 kJ/mol. Hydrogen bonding is so strong that, in some cases, it survives
even in a vapor.
8-2-1 In gaseous hydrogen fluoride, many of the HF molecules are associated into (HF)6.
Draw the structure of this hexamer.
8-2-2 Draw a diagram showing the hydrogen-bonding interactions between two acetic acid
(CH3CO2H) molecules.
Part 3: Hydrogen-bonding in Living Matter
Some chemical reactions in living matter involve complex structures such as proteins and DNA,
and in these reactions certain bonds must be easily broken and reformed. Hydrogen bonding is
the only type of bonding with energies of just the right magnitude to allow this.
The key to DNAs functioning is its double-helical structure with complementary bases on the two
strands. The bases form hydrogen bonds to each other.
N
N
N
N
N
N
H
O
OR
H
H3C
NH
H
H
R
H
Thymine (T)
Adenine (A)
N
N
N
N
N
N
N H
H
OR
H
H
H
O
NH
H
R
H
Cytosine (C)
Guanine (G)
The organic bases found in DNA
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8-3 There are two kinds of hydrogen-bonded base pairs, T-A and G-C, in DNA. Draw these
two base pairs, showing the hydrogen-bonding interactions.
Problem 9: Crystal Packing
There are three cubic unit cells for the atomic solids, namely, simple cubic, body-centered cubic
and face-centered cubic. They are illustrated in the following figures:
9-1 How many nearest neighbor atoms are in each packing, respectively?
9-2 In each packing, the packing efficiency is defined by
cellunittheofvolume
cellunitin thespheresbyoccupiedvolumefv =
What is the value of fvin each type of packing, respectively?
9-3 Silver crystallizes in a cubic closest packed structure, i.e. face-centered cubic. The radius
of a silver atom is 144 pm. Calculate the density of silver.
9-4 X-ray diffraction is commonly used for the determination of crystal structures. In one such
determination, the emitted X rays were diffracted by a LiF crystal (d = 201 pm), and the
first-order diffraction was detected at an angle of 34.68o. Calculate the wavelength of the
X-ray emitted by the metal.
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Problem 10: Applications of Transition Metals
The transition metal elements are widely distributed in the Earths crust. Many of these elements
find uses in everyday objects: iron pipes, copper wiring, chromium auto parts, etc.
Part 1: Properties of Chromium
Chromium is a silvery-white, lustrous metal, whose name (from the Greek chroma, meaning color)
alludes to its many colorful compounds. The bright colors of chromium (VI) compounds lead to
their use in pigments for artists paints and ceramic glazes.
10-1-1 In an acidic solution, the yellow chromate ion (CrO42-
) changes into the orange
dichromate ion (Cr2O72-
). Write the equation for the reaction.
10-1-2 What is the oxidation state of each metal center in the chromate ion and the dichromate
ion?
10-1-3 Is this a redox reaction? Explain.
10-1-4 What is the main factor that controls the equilibrium position?
10-1-5 Draw the three-dimensional structures of CrO42- and Cr2O72-.
Part 2: Uses of Chromium
An antique automobile bumper is to be chrome plated. The bumper is dipped into an acidic
Cr2O72-
solution where it serves as the cathode of an electrolytic cell. (The atomic mass of Cr is
51.996; 1 F = 96,485 C.)
10-2-1 Given that oxidation of H2O occurs at the anode, write equation for the two
half-reactions and the overall cell reaction.
10-2-2 How many moles of oxygen gas will be evolved for every 52.0 g of chromium
deposited?
10-2-3 If the current is 10.0 amperes, how long will it take to deposit 52.0 g of chromium onto
the bumper?
10-2-4 What is the chemical reason that chromium is so useful for decorative plating on
metals?
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Problem 11: Electrochemistry of Inorganic Compounds
Some inorganic compounds exhibit a variety of oxidation states, for example, many Mn
compounds are known with oxidation states ranging from 0 to +7. The standard reduction
potential of a half reaction is measured against the hydrogen electrode. In this problem, the
reduction Mn2+
+ 2 e-Mn, E= -1.18V is expressed as Mn
2+ (-1.18) Mn. For Mn in acidic
solution the reduction series: Mn3+
Mn2+
Mn can be represented as follows:
Mn3+
(1.5) Mn2+
(-1.18) Mn
A redox reaction takes place spontaneously if the redox potential is positive. A Frost diagram, a
plot of nE(n is the number of electron transferred in the half reaction) of the reduction couple
X(N) / X(0) against the oxidation number, N, of the element, is used to indicate the most stable
species of the compounds in different oxidation states. The Frost diagram of Mn3+
/ Mn2+
/ Mn is
shown below.
11-1 The reduction potential depends on the concentration of the species in solution. The Ksp
of MnCO3 is 1.810-11
. Use the Nernst equation to determine the potential at 25C for
the voltaic cell consisting of Mn(s) | Mn2+
(aq) (1M) || Mn2+
(aq) / MnCO3 | Mn(s), if the
concentration of Mn2+
in the right hand side of the cell is 1.0 10-8
M.
11-2 For oxygen, the standard reduction potential in acidic solution can be represented as:
O2 (0.70) H2O2 (1.76) H2O. Construct the Frost diagram for oxygen, and use the
information contained in the diagram to calculate the reduction potential of the half
reaction for reduction of O2 to H2O. Could H2O2 undergo disproportionation
spontaneously?
Xenon difluoride can be made by placing a vigorously dried flask containing xenon gas and
fluorine gas in the sunlight. The half-reaction for the reduction of XeF2is shown below:
XeF2(aq)+ 2H
+
(aq)+ 2e
-
Xe(g)+ 2HF(aq) E= 2.32V
11-3 Use the VSEPR model to predict the number of electron-pairs and molecular geometry of
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XeF2. Show that XeF2decomposes in aqueous solution, producing O2, and calculate the
Eofor the reaction. Would you expect this decomposition to be favored in an acidic or a
basic solution ? Explain.
2 H2O
O2+ 2H
+
+ 4e
-
E
o
= -1.23V
Problem 12: Metal Carbonyl Compounds
Carbon monoxide, as a two electron donor ligand, coordinates to transition metals to form metal
carbonyl compounds. For example, iron forms the pentacarbonyl metal complex, Fe(CO)5.
Nickel tetracarbonyl, Ni(CO)4, has been used for the purification of Ni metal in the Mond process.
Electron counts of these metal carbonyl complexes show that they obey the 18-electron rule.
Cobalt and manganese react with CO to form dinuclear complexes Co2(CO)8 and Mn2(CO)10,
respectively. (Electronic configuration of Mn is [Ar](3d)5(4s)
2) A metal-metal bond between the
metal centers is considered essential in order for the compounds to obey the 18 electron rule.
The cyclopentadienyl anion C5H5- has also been widely used as a
5-ligand. For example,
ferrocene (C5H5)2Fe, a classical compound, obeys the 18 electron rule.
The reaction of W(CO)6with sodium cyclopentadienide NaC5H5yields an air sensitive compoundA. Oxidation of Awith FeSO4 yields compound B. Compound A can also be prepared from
the reaction of B with Na/Hg, a strong reducing agent. In the 1600-2300 cm-1
region of the IR
spectrum, Ashows absorption bands at 1744 and 1894 cm-1
and Babsorption bands at 1904,
and 2010 cm-1
. Compound A is a strong nucleophile and a good starting material for the
synthesis of organometallic compounds containing metalcarbon bonds. The reaction ofAwith
propargyl bromide (HCCCH2Br) gives compound Ccontaining a metal-carbon -bond. At room
temperature compound Cundergoes a transformation to yield compound D. The same chemical
composition was found for compounds C and D. The chemical shifts () of the CH2 and CH
resonances and coupling constants JH-Hof propargyl bromide, Cand Din the respective1H NMR
spectra are listed in the following table.
1H NMR HCCCH2Br C D
(CH2) 3.86 1.90 4.16
(CH) 2.51 1.99 5.49
JH-H(Hz) 2.7 2.8 6.7
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W(CO)6
NaC5H5
CCH2Br
A B
C D
FeSO4
Na/Hg
HC
metal
migration
12-1 Explain the differences in the IR spectra ofAand B.
12-2 Draw chemical structures forA, B, Cand D.
12-3 The transformation of C to D involves a migration of the metal on the propargyl ligand.
If DCCCH2Br is used for the synthesis of C, draw the structures of Cand D.
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Problem 13: Carbocations and Aromaticity
Carbocations are reactive intermediates having a charge of +1 on the central carbon atom, with
three groups attached. The carbocation center is electron deficient and lies in the same plane ofthe three attached atoms. Proton NMR is one of the primary instrumental methods applied to
determine the structure and properties of carbocations. In a superacid media, such as SbF5,
stable carbocations can be generated and directly observed by NMR. SbF5 is a strong Lewis
acid that complexes with a weak base such as F-to form SbF6
-.
13-1 What is the productAin the following reaction?
H3CH3C
CH3
FSbF5
A
13-2 Two proton NMR spectra of (CH3)3CF were obtained using neat (CH3)3CF and (CH3)3CF
in SbF5, respectively. One spectrum, denoted as spectrum I, showed a singlet at 4.35,
and the other, spectrum II, revealed a doublet at 1.30 with a coupling constant J= 20 Hz.
Which spectrum was obtained from (CH3)3CF in SbF5?
13-3 Tropylium ion B is one of the most stable carbocations. How many electrons are there
in the tropylium ion?
+H
H H
H
HH
H
B
13-4 Is tropylium ion Ban aromatic structure? Explain.
13-5 The chemical shift of benzene in the1H NMR spectrum is 7.27. What does the proton
NMR spectrum of Blook like?
(a) A singlet at 9.17.
(b) A singlet at 5.37
(c) A triplet at 9.17.
(d) A Triplet at 5.37.
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13-6 4-Isopropyltropolone Cwas the first example of a non-benzenoid aromatic compound. It
was isolated from cypress trees in Taiwan by Professor T. Nozoe at the National Taiwan
University in 1938. Draw resonance structure(s) to illustrate the aromaticity of C.
O
OH
C
13-7 The proton of the OH group in tropolone is acidic. Three moles of tropolone Ccan react
with one mole of tris(2,4-pentanedionato)iron(III) (Fe(acac)3) to form a red complex D.
What is the structure of D?
Problem 14: Photochemical Ring Closure and Opening
1,3,5-Hexatriene is known to undergo light-induced cyclization to give 1,3-cyclohexadiene. The
photochemical reaction is reversible and stereospecific. Thus, irradiation of (2E,4Z,6E)-octatriene
(A) with UV-light gives cyclohexadiene (B). The choice of the wavelength of light depends on
the absorption maximum of the compound to be irradiated, and the absorption maximum is
related to the number of conjugated double bonds in a chain.
irradiation
CH3H3C H3C CH3
A B
14-1 What is the chemical name of the starting triene (C) for the related reaction shown below?
irradiation
H3C CH3
C
D
A similar reaction mechanism is involved in the synthesis of biologically active molecules. For
example, in the presence of sunlight, 7-dehydrocholesterol (E) undergoes an electrocyclic ring
opening reaction to give provitamin D3 (F), which can be further transformed through a
[1,7]-hydrogen shift to yield vitamin D3(G).
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H3C
HO
H3C
H3C(CH2)3
HH
7-dehydrocholesterol (E)
provitamin D3 (F)
vitamin D3(G)
sunlight
H3C
H3C
H
HO
[1,7] H-shift
CH3
CH3
(CH2)3CH3
CH3
14-2 Of the two compounds 7-dehydrocholesterol (E) and vitamin D3 (G), which would you
expect to absorb light with the higher energy? (Eor G)
14-3 What is the chemical structure of F?
This principle has been elaborated to develop photochromic materials. For example, irradiation
of colorless compound Hwith UV light gives colored compound I. The color change is reversed
upon exposure to visible light.
14-4 Give the structure of colored compoundI.
O
CH3 CH3H3C
O
O UV light
visible light
colorless
H
coloredcompound
I
Aromatic hydrocarbons are usually highly fluorescent. However, a neighboring aminosubstituent may quench the fluorescence. This quenching mechanism is due to Photoinduced
Electron Transfer (PET), which can be clearly illustrated by the molecular orbital diagrams shown
below. Upon irradiation with a light of suitable wavelength (step 1), the initial aromatic
chromophore (state a) will pump an electron from the highest occupied molecular orbital (HOMO)
up to the lowest unoccupied molecular orbital (LUMO) (state b). In the presence of a
neighboring amino group, one of the lone-pair electrons at the nitrogen atom moves to the HOMO
of the excited chromophore (step 2), and thus blocks the normal fluorescent pathway (state c).
Coordination of the amine lone-pair electrons to proton or metal ions efficiently inhibits the PET
process, and retrieves the fluorescence of the aromatic chromophore (step 3).
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LUMO
HOMO
aminelone-pairelectrons
(a)
h
(1)
LUMO
HOMO
(b)
PET
(2)
LUMO
HOMO
(c)
no fluorescenceN
LUMO
HOMO
(d)
(3)M+
NM Many interesting and sensitive proton or metal ions fluorescent sensors have been developed
based on the manipulation of the PET process. For example, compound J is used as a
pH-sensor.
N
Cl
J
14-5 Do you expect that compound Jis fluorescent in an alkaline solution (pH = 10.0)?
Problem 15: Stereochemistry
A simple two-dimensional representation for showing the three-dimensional arrangement of
groups bonded to a carbon center is called a Fischer projection. In this molecular
representation, the intersection point of two perpendicular lines represents an sp 3 center. The
horizontal lines connecting B and D to the central carbon atom represent the bonds that are out of
plane relative to the observer. The vertical lines connecting A and C to the central carbon atom
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represent the bonds that are directed away from the observer into the plane of the page.
D B
A
C
D B
A
C
into plane
out of plane
15-1 ChiraPhos was developed by Prof. Kagan and has found useful applications in
asymmetric synthesis. Using the Fischer projection shown below, assign the absolute
configuration of the chiral centers of ChiraPhos in terms of the R/Snotation according to
the Cahn-Ingold-Prelog sequence rule.
H PPh2
CH3
Ph2P H
CH3
ChiraPhos
2
3
15-2 One of the stereoisomers of ChiraPhos is a mesocompound. What are the identities of
XandY in the Fischer projection shown below?
X Y
H
H3C PPh2
H
meso-ChiraPhos
2
3
It is very useful and common to use Fischer projections for the stereo representation of
carbohydrates. For example, the following Fischer projection represents the structure of
D-glucose. It is interesting to note that the open-chain glucose can be interconverted with cyclic
structures through the hemiacetal formation between the C5-OH and the C1-aldehyde group.
H OH
CH
HO H
OHH
CH2OH
OHH
O
2
3
4
5
(cyclic structures)
D-glucose
H OH
C
HO H
OH
CH2OH
OHH
OH
H
H OH
C
HO H
OH
CH2OH
OHH
H
HO
or
-anomer -anomer(open chain)
The hemiacetal formation generates two stereoisomers, which are called anomers. The pure
-anomer of D-glucose has a specific rotation of +112.2o, whereas the pure -anomer has a
specific rotation of +18.7o. In water, either one of the two anomers gives an equilibrium mixture
with a specific rotation of +52.6o.
15-3 Calculate percentage of-anomer in the equilibrium mixture of D-glucose in water.
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15-4 Which is the more stable anomer in water? (or )
15-5 Draw the chair conformation of the -anomer.
15-6 What is the common intermediate for the interconvertion between the - and -anomers?
The addition reaction of HCN to an aldehyde generates a cyanohydrin, which can be further
reduced to form an -hydroxyaldehyde.
R H
OHCN
R CN
OH
R
OH
O
Hreduction
cyanohydrin
High homologs of carbohydrates, such as D-talose, can be synthesized from D-glyceraldehyde byrepeating the same reaction conditions three times as shown below.
H OH
CHO
CH2OH
1. HCN
2. reduction
HO H
CHO
H OH
CH2OH
HO H
H OH
CH2OH
HO H
HO H
CHO
D-glyceraldehyde stereoisomer
D-talose+ stereoisomers
15-7 How many pairs of enantiomers will appear in the final product mixture?
Enzymes are remarkable biological catalysts that control the pattern of chemical transformations
in living organisms. Because of their striking catalytic power and specificity, applying enzymes in
organic synthesis has become one of the fastest growing areas for the development of new
synthetic methodology. Following are the data for the yeast-mediated kinetic resolution of
racemic 2-substituted cyclohexanone via Baeyer Villiger reactions (Table 1).
Table 1. Yeast-mediated kinetic resolution of racemic 2-substituted cyclohexanone via Baeyer
Villiger reactions
O
Ryeast
O
O
R
O
R+
racemic mixture
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O
O
R
O
R
Entry R Yield (%) ee% Yield (%) ee%
1 Et 79 95 69 98
2 n-Pr 54 97 66 92
3 Allyl 59 98 58 98
ee: enantiomeric excess
15-8 What is the ratio of (R)/(S) isomers of 6-allylcaprolactone in entry 3?
15-9 MCPBA (meta-chloroperbenzoic acid) is a common oxidizing agent for Baeyer Villiger
reactions. Using MCPBA as an oxidizing agent, instead of yeast, for the above reaction,
what will be the ee% of the caprolactone product?
Problem 16: Organic Synthesis
One of the primary demands for the development of organic light emitting diodes (OLEDs) is the
search for highly efficient luminescent materials which can be either small molecules or polymers.
For example, fluorene, a methylene-bridged biphenyl, exhibits a higher quantum yield of
fluorescence than biphenyl.
Fluorene Biphenyl
1
2
3456
7
8
9
Many fluorene derivatives have been developed that have subsequently found promising
applications in flat-panel-display technology. In order to avoid intermolecular interactions, bulky
substituents have been introduced at the C9 position of fluorene. One example of this is
compound C, an interesting and useful building block in the development of a highly efficient blue
light emitting material, the synthesis of which is shown in the following scheme.
O
NH2 1) NaNO2, HCl
0-5 oC
2) KI
A
1) Mg, Et2O
2)
BHOAc, HCl
refluxC (C25H16)
3) H2O
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16-1 Draw the structures ofA, B, and C.
Liquid crystals have become a part of our daily life, from wristwatches, pocket calculators, to full
color flat-panel displays. Liquid crystal molecules usually contain a rigid core with a flexible
terminal alkyl chain as shown in the example below.
CN
Rigid coreFlexibleterminalalkyl chain
Biphenyl and terphenyl are common basic skeletons for the rigid core of liquid crystals. This
kind of structure can be effectively synthesized through palladium catalyzed coupling of an aryl
bromide or iodide with arylboronic acid, known as the Suzuki coupling reaction.
Terphenyl
A typical example of a Suzuki coupling reaction is shown below. Bromobenzene reacts with
phenylboronic acid in the presence of a palladium catalyst to give biphenyl.
Br B(OH)2+Pd(0) catalyst
The following is a synthetic scheme for the preparation of two liquid crystal molecules,
4-cyano-4-pentylbiphenyl and G.
Br2D
C4H9COCl
AlCl3
ENH2NH2
KOH, heatF
CuCNDMF
NC C5H11
C8H17O B( 2
F F
Pd(PPh3)4Na2CO3
MeOCH2CH2OMe, H2O
G
OH)
16-2 What are the structures of D, E, F, and G?
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Problem 17: Spectroscopy and Polymer Chemistry
Organic polymers have had a great impact on our daily lives. Millions of tons of different kinds of
polymers are produced every year. Synthetic organic polymers have a variety of uses, from
textiles to computer chips, and to the life saving artificial heart valve. They are widely used as
plastics, adhesives, engineering materials, biodegradable plastics, and paints. Poly(vinyl alcohol)
(PVA) is an important example of a water-soluble polymer. One synthetic route to PVA is
summarized in Scheme 1.
MonomerApolymerization
PolymerB Poly(vinyl alcohol) (PVA)
Scheme 1
Polymer B shown above is also a major component in chewing gum. Elemental analysis of A
suggests a ratio of C:H:O = 56:7:37. In addition, elemental analysis of B gives an almost
identical composition of C, H, and O. The following IR and 1H NMR spectra were recorded for
MonomerA.
1H NMR spectrum of MonomerA
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4000 3500 3000 2500 2000 1500 1000
30
40
50
60
70
80
90
100
110
977849
876951
1021
1138
1217
1295
1434
1372
1648
1761
30943503
Transmittance(%T)
-1wavenumber cm
IR Spectrum of MonomerA
17-1 What is the molecular formula ofA?
17-2 Which functional group would give an IR absorption band at 1761 cm-1?
17-3 What is the chemical structure ofA?
17-4 Draw a portion of polymer B. Show at least three repeat units.
17-5 Provide a method for the transformation of Bto PVA.
17-6 How many pairs of enantiomers would be obtained from polymer B with a molecular
weight of 8600, assuming that the polymer is terminated by hydrogen abstraction and the
mass of the terminal groups can be ignored?
17-7 Compound C, an isomer ofA, is also an important monomer for the synthesis of polymers.
On the basis of its 1H NMR and IR spectra provided below, deduce the chemical structure
of C.
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1H NMR spectrum of Monomer C
4000 3500 3000 2500 2000 1500 1000
20
40
60
80
100
662
812
854
988
1069
1205
12791404
1439
1634
1731
194525872697
20622856
2955
2999
3107
34453553
3632
Tra
nsmittance(%T)
wavenumber (cm-1)
IR Spectrum of Monomer C
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Polymer D is an acid sensitive macromolecule. On treatment of Dwith a protic acid, gases E
and F are released, and a new polymer G is formed. Gas E turns an aqueous solution of
Ca(OH)2into a turbid solution while gas Freacts with bromine to give a colorless solution of H.
E + F + GH
+
aqueous
Ca(OH)2
turbidsolution
H (colorless)
Br2
O
O
O
n
D
17-8 Draw the chemical structures of E, F, Gand H?
Polymer D has been used to formulate a photo-imaging material by mixing it with a photo
acid-generator (PAG). After being coated onto a substrate and exposed to light, protons are
generated from the PAG, catalyzing a chemical reaction within the polymer matrix. Sometimes
baking after exposure is necessary to accelerate the acid catalyzed reaction. If light is applied
through a mask (Figure 1), a latent image of the mask is formed in the polymer matrix. After
baking and using an aqueous basic developer to wash away the acidic materials, a patterned
substrate Iis obtained.
SubstratePolymer D+ PAG
Light
Patterned mask
Figure 1
17-9 Which of the following diagrams best illustrates the patterned structure of substrate I?
(a) (b) (c) (d)
The dark areas represent a polymeric coating that is structurally different from the original one.
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Problem 18: Crown Ether and Molecular Recognition
The discovery of crown ethers was made by Charles Pederson in 1967. He was rewarded with
a share of the 1987 Nobel Prize for chemistry with Jean-Marie Lehn and Donald Cram for their
contributions to supramolecular chemistry.
The following schematic diagram shows a synthetic route to the linear diolA. However, because
of the presence of catechol in the starting material, the resulting product was a mixture of Aand
the minor product B.
OH
O O
Cl
O
Cl1) NaOH
2) H3O+
O
OH HO
O
O
+
Contaminatedwith catecholshown below
+
A
B
OH
OH
Catechol
The molecular weight of Bwas found to be 360.1 and it had an elemental composition of C:H:O =
66.5:6.7:26.6. The
1
H NMR spectrum of Bshowed four sets of proton signals. Two of whichwere observed at 7.0-7.5 and the other two at 3.7-4.2. The integration ratio of the four sets
of signals was 1:1:2:2. Compound Bstrongly binds with the potassium ion. A striking example
is the use of Bto assist the dissolution of KMnO4in benzene to give a purple coloration.
18-1 What is the chemical structure of B?
18-2 What is the major function of H3O+in the above reaction?
(a) To activate ClCH2CH2OCH2CH2Cl.
(b) To neutralize NaOH.
(c) To remove the tetrahydropyran group.
(d) To act as a buffer to control the pH of the solution.
The following is the synthetic route to [2.2.2]cryptand:
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OH
O O
HO
OONH2
O O
H2NE
1, B2H6
2. H2O
high dilution
O O
N
OO
NO O
[2.2.2]Cryptand
SOCl2C D
LiAlH4
CF
18-3 Draw the structures of C-F.
18-4 Why are high dilution conditions required in the synthesis of Dfrom C?
(a) Since the reaction between C and the diamine is highly exothermic, a high dilution
condition is used to dissipate the heat released from the reaction.
(b) A high dilution condition is employed in order to inhibit oligomer or polymer formation.
(c) Thermal equilibrium is favored to give Din higher yield under high dilution conditions.
(d) The solubility of the starting material is low.
The affinity of a metal cation is controlled by several factors such as size matching between the
host cavity of the crown ether and the guest cation, and the number of donor atoms of the host.
Table 1 shows the radii of different alkali metal cations and the diameters of the cavities of several
crown ethers.
O
O
O
O
O
OO O
OO
O O
OO
O
O O
OO
OOO
12-C-4 15-C-5 18-C-6 21-C-7
Cavity
Table 1. Radii of different alkali metal cations and diameters of the cavities of crown ethers.
Cation (radius, pm) Cavity of the crown ether (diameter, pm)
Li+ (68) 12-C-4 (120-150)Na+ (98) 15-C-5 (170-220)K+ (133) 18-C-6 (260-320)Cs
+ (165) 21-C-7 (340-430)
18-5 On the basis of the above data, match the experimental curves I-III in Figure 1 with
appropriate cyclohexyl crown ethers G-I.
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1.0
2.0
3.0
4.0
5.0
6.0
Na K Cs
I
II
III
O
O
O
O
O
OOO
O
O
O
O
O
O
O
G H
I
Cation Radius
log Kf
Figure 1. Complexation of Crown Ethers with Cations in Methanol
Problem 19: Enzyme Catalysis
In biological systems, oxidases catalyze the following reaction
O2 + 4H
+
+ 4e
-
2H2O
The reaction is the key to respiration in living systems. The electrons come from Cytchrome c,
which contains an iron center. The half reaction is
FeIIcyt c Fe
IIIcyt c + e
-
The extinction coefficients of FeIIcyt c and FeIIIcyt c at 550 nm are 27.7 and 9.2 mM cm-1
;
respectively.
The absorbance of cyt cat 550 nm was observed to decrease at a rate of 0.1 A/sec in a 5 mL
solution containing 2.7 x 10-9
M oxidase, and sufficient cyt c and oxygen.
19-1 How many moles of cyt cwere oxidized each second?
19-2 How many moles of oxygen were consumed each second?
19-3 What is the turnover number for oxidase? (Turnover number: the number of product
produced by one catalyst per second)
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Problem 20: Work in Thermodynamics
Given 10 liters of an ideal gas at C and 10 atm, calculate the final volume and work done,
under the following three sets of condition, to a final pressure of 1 atm
0
20-1 Isothermal reversible expansion
20-2 Adiabatic reversible expansion
20-3 Irreversible adiabatic expansion carried out as follows: Assume the pressure is suddenly
released to 1 atm and the gas expands adiabatically at constant pressure.
[Note that the molar heat capacity at constant volume is given by the relation: RC2
3v= , where R
is the gas constant.]
Problem 21: Kinetics Atmospheric Chemistry
The following second-order reaction is important in air pollution.
22 22 ONONO +
21-1 Derive an integrated relationship between the total pressures in the reaction vessel,
originally containing pure NO2, at the time t.
21-2 It was found that when a 2 liter vessel is filled with NO2at a pressure of 600 mm of Hg and
a temperature of 600C, the reaction is 50% complete after 3 min. Calculate the rate
constant.
Problem 22: Kinetics and Thermodynamics
The concept of kinetic versus thermodynamic control of reaction products has frequently been
employed in organic synthesis to direct product formation, for example, in sulfonation, Diels-Alder,
isomerization and addition reactions. Here the interconversion of two different products can be
achieved competitively by controlling the reaction conditions. It is normally represented as a
concurrent reaction scheme, as shown below for the case where the reaction of A proceeds
competitively toward products B and C.
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B A C,
1
1
k
k
2
2
k
k
The energy profile for the reaction is depicted in the Figure below.
22-1 Given the rate constants k1=1, k-1=0.01, k2=0.1, and k-2=0.0005 min-1, estimate the product
ratio B/C in the first 4 min of the reaction.
22-2 Using the same rate constants, estimate the product ratio B/C when the reaction time
exceeds 4 days.
22-3 B is called the kinetic-controlled product, while C is called the thermodynamic-controlled
product. When the temperature of the system increases, which reaction process is
favored?
Problem 23: Phase Diagram
The phase diagram is a convenient way to indicate the phases of a substance as a function of
temperature and pressure. Answer the following questions based on the phase diagram of water
given below:
23-1 What phases are present at A, B, and C?
23-2 Why does ice not sink in its own liquid?
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particle motion in one dimension, are given in the following.
24-1 The distribution of speeds of gaseous molecules at a fixed temperature can be described
by the following probability density, called the Maxwell-Boltzmann distribution,
=
RTM
RTMF
2vexp
2v4)v(
22/3
2
where v is the speed of molecule, M is the mass of molecule, T is the temperature in Kelvin,
and R is the gas constant. Calculate the average speed, , and the standard deviation,
v, of the distribution of speeds of the O2molecules at 300 K. (O2 = 32 g/mol, R = 8.31 J
K-1
mol-1
)
24-2 Suppose a particle moving in the x direction has a normalized wavefunction,
2/12 )]2/exp()2/1[( x= ; x ,
Calculate the average position, , and the standard deviation,x
, of the position
distribution of the particle after a large number of measurements of x.
24-3 In quantum mechanics, momentum for one dimension can be expressed by an operator,
i.e., p=dx2
dih
, where h is the Plancks constant. Calculate the average momentum,
, and the standard deviation, p, for the particle with the same wavefunction described
in part 2.
24-4 Calculate the uncertainty product of position and momentum, xp, for the above quantum
mechanical example.
Some useful integrals are given below:
++
=0
2/1
121
22
2
)12(531)exp(
nn
n
a
ndxaxx
++ =
0 1
212
2
!)exp(
n
n
a
ndxaxx where n = 0,1,2,3
Problem 25: A Particle in a 2-D Box Quantum Mechanics
The electrons of the iron-heme of a hemoglobin molecule can be visualized as a system of freeelectrons moving in a two-dimensional box. According to this model, the energy of the electron is
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limited to the values
where h=6.63 x 10-34J s is the Planck constant; nxand nyare the principal quantum numbers;
me=9.11 x10-31
kg is the electron mass; L is the length of the box.
25-1 Construct an energy level diagram showing the relative ordering of the lowest 17 orbitals.
25-2 Given the molecule contains 26 electrons, determine the electron population of the highest
occupied orbitals in the ground state.
25-3 Assuming Hund's rule can be applied to this system, predict whether or not this system is
paramagnetic.
25-4 Light is absorbed only when the condition h= E is satisfied. If the length L for this 2D
box is 1 nm, what is the longest wavelength of light that can lead to excitation? Express
your result in nm. [The speed of light, c = 3.00 x108m/s]
Problem 26: Spectral Analyzer
The configuration of the distributed feedback dye laser (DFDL) system is shown in Fig. 1, and
consists of an oscillator and a preamplifier.
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