ch-4 control ppt webpage ac motors
TRANSCRIPT
![Page 1: Ch-4 Control Ppt Webpage AC Motors](https://reader030.vdocuments.net/reader030/viewer/2022013102/544a9469b1af9f884f8b4989/html5/thumbnails/1.jpg)
Chapter 4
Control System
Components
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DC Control Components
• potentiometer
• tachogenerator
• dc servo motor
• dc amplifier
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amplification of
slowly varying
signals is
difficult -
hence....
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ac / carrier
control
Systems
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ac control system components
• synchro pair
• ac tachogenerator
• ac amplifier
• ac servo motor
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ac servo motor
• special induction motor
• 2 - phase electric
supply
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Torque speed
curve of an
induction motorfollows....
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vr
vcRotor Load
J, B
vr = V cos ωωωωct
vc = e sin ωωωωct
Two phase servo motor
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1.0 0C
BTmax
Torque
Tst
slip
sTmax
A
maxTs
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Portion AB - unstable
Portion BC - stable
sTmax = R2 / X2
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1.0 0
C
BTmax
Torque
Tst
slip
sTmax
A
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1.0 0
C
BTmax
Torque
Tst
slip
sTmax i
A
R i
R i i
sTmax ii
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R ii > R i
sTmax ii > sTmax i
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1.0 slip
C
B
Make X2 = R2
sTmax = 1
0
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Portion BC
extended for
the full speed
range.
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Salient features of ac servo motor
•Rotor with high resistance
•Low inertia
•Two phase operation
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vr
vcRotor Load
J, B
vr = V cos ωωωωct
vc = e sin ωωωωct
Two phase servo motor
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Torque
speed
E1
E2E3
E1 > E2 > E3
Eo
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Tm
= f ( E, ωωωω )
Using Taylor series,
Tm
= Tmo
+ --------
∂∂∂∂ E E = E0
ωωωω=
ωωωω0
∂∂∂∂ Tm (E- E0) ∂∂∂∂ Tm
-------∂∂∂∂ ωωωω
+
(ωωωω - ωωωω0)
E = E0
ωωωω = ωωωω0
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Tm
- Tmo
= K1
( E - E 0)
- K2(ωωωω - ωωωω0)
∆∆∆∆ Tm = K1 ∆∆∆∆ E
- K2 ∆∆∆∆ ωωωω
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= ( J s + B ) ∆∆∆∆ ωωωω
∆∆∆∆ ωωωω K1
------ = ------------
∆∆∆∆ E K2 + Js + B
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For position control,
the operating
point is Tm0
= 0,
ωωωω0 = 0 and
E0 = 0
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To evaluate K1 & K2
Torque rated voltage
speed
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At ωωωω = 0,
T = stall Torque
At T = 0,
ωωωω = no load speed
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Torque rated voltage
speed
To evaluate K1
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K 1 =
stall Torque ( rated voltage )
rated control phase voltage
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K2
Torque rated voltage
speed
To evaluate
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K 2 =
stall Torque ( rated voltage )
no load speed ( rated voltage )
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Since the slope of torque speed curve reduces
as rated voltage reduces .......
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We take
K 2 =
1 stall torque ( rated voltage)
2 no load speed ( rated voltage)
for position control,
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vr
vtRotor
AC Tacho generator
vr = v cos ωωωωct
vt = Kt ωωωωm
sin ωωωωct
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vr = v cos ωωωωct
vt = Kt ωωωωm sin ωωωωct
vt is the output whose amplitude
is proportional to the speed.
Vt is an amplitude Modulated
waveform
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Synchro pairs
- position error detectors
Synchro transmitter
Synchro control transformer
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vr
Synchro
Transmitter
a
bc
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Synchro
Control
e
transformer
a
bc
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vres1
s2
s3
θθθθ αααα
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vr
= Vr
sin ωωωωct
vs1n
= k Vrcos(θθθθ + 120°°°°) sin ωωωωc
t
vs2n
= k Vr
cos θθθθ sin ωωωωct
vs3n
= k Vr
cos(θθθθ + 240°°°°) sin ωωωωct
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vr erotor
( Transmitter )
rotor
(Control Transformer)
Amplitude of e is maximum
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vr erotor
(Control Transformer)
rotor
( transmitter )
Amplitude of e = 0
i.e. Amplitude of e is proportional
to cosine of the angle difference
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Angle difference
= 90 + αααα - θθθθ
= 90 - ( θθθθ - αααα )
θθθθ αααα
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e = k’ Vr cos (90 - (θθθθ - αααα)) sin ωωωωct
= k’ Vr sin (θθθθ-αααα) sin ωωωωct
= k’ Vr ( θθθθ - αααα ) sin ωωωωct
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Stepper Motor
• permanent magnet
• variable reluctance
• hybrid Motor
Stepper motors provide a means for precise positioning and speed
control without the use of feedback sensors. The basic operation of a
stepper motor allows the shaft to move a precise number of degrees
each time a pulse of electricity is sent to the motor. Since the shaft of
the motor moves only the number of degrees that it was designed for
when each pulse is delivered, you can control the pulses that are sent
and control the positioning and speed. The rotor of the motor
produces torque from the interaction between the magnetic field in the
stator and rotor..
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permanent magnet
N
S
Rotor
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permanent magnet
A B
Stator
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A B
N S
A ON B OFF
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A B
N SS N
A ON B OFF
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N
S
C
D
C ON D OFF
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N
S
N
S
C
D
C ON D OFF
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Switching Table
N
S
NS
NS
A B C D
1 0 1 0
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Switching Table
N
NS
S
0 1 1 0
1 0 1 0
A B C D
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Switching Table
N
SNS
N
S
0 1 1 0
1 0 1 0
A B C D 90 °°°° CW
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Switching Table
S
NS
N
A B C D
0 1 0 1
1 0 1 0
0 1 1 0
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Switching Table
S
SNS
N
N
A B C D
0 1 0 1
1 0 1 0
0 1 1 0
90 °°°° CW
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Switching Table
S
SN
N
A B C D
1 0 0 1
1 0 1 0
0 1 1 0
0 1 0 1
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Switching Table
S
SSN
N
N
A B C D
1 0 0 1
1 0 1 0
0 1 1 0
0 1 0 1
90 °°°° CW
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Switching Table
N
NSN
S
S
A B C D 90 °°°° CW
1 0 1 0
0 1 1 0
0 1 0 1
1 0 0 1
1 0 1 0
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Switching Table
1 0 1 00 1 1 00 1 0 1
1 0 0 11 0 1 0
A B C D
CW
CC
W
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Variable Reluctance
A1
B1
C1
A2B
2
C2 1
2
3
4
A ON
1 opp A1
3 opp A2
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A1
B1
C1
A2B
2
C2 1
2
3
4
A OFF B ON : 2 opp B1 and 4 opp B2
30°°°° CCW
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A1
B1
C1
A2B
2
C2 1
2
3
4
B OFF C ON : 3 opp C1 and 4 opp C2
30°°°° CCW
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A1
B1
C1
A2B
2
C2 1
2
3
4
C OFF A ON : 4 opp A2 and 2 opp A1
30°°°° CCW
for CW
operation
switching
sequence ?
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S = no. of stator slots
R = no. of rotor slots
θθθθ = 360°°°° (1/R - 1/S)
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Multistack arrangement
Multistack stepper motors can produce smaller step sizes because
the motor is divided along its axial length into magnetically isolated
sections, or stacks. Each of these sections is excited by a separate
winding, or phase. In this type of motor, each stack corresponds to a
phase, and the stator and rotor have the same tooth pitch.
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Rotor
StatorA
B
C
air gap
θθθθ = 360 / ( n ×××× T ) degrees; n = no. of stacks T = no. of teeth