chapters 6, 7 energy

40
Chapters 6, 7 Energy

Upload: kris

Post on 05-Jan-2016

210 views

Category:

Documents


0 download

DESCRIPTION

Chapters 6, 7 Energy. Energy What is energy? Energy - is a fundamental, basic notion in physics Energy is a scalar , describing state of an object or a system Description of a system in ‘energy language’ is equivalent to a description in ‘force language’ - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: Chapters 6, 7 Energy

Chapters 6, 7

Energy

Page 2: Chapters 6, 7 Energy

Energy

• What is energy?

• Energy - is a fundamental, basic notion in physics

• Energy is a scalar, describing state of an object or a system

• Description of a system in ‘energy language’ is equivalent to a description in ‘force language’

• Energy approach is more general and more effective than the force approach

• Equations of motion of an object (system) can be derived from the energy equations

Page 3: Chapters 6, 7 Energy

Scalar product of two vectors

• The result of the scalar (dot) multiplication of two vectors is a scalar

• Scalar products of unit vectors

cosABBA

ii ˆˆ 1ˆˆ jj

ji ˆˆ

1ˆˆ kk

0ˆˆ ki 0ˆˆ kj

0cos11 1

90cos11 0

Page 4: Chapters 6, 7 Energy

Scalar product of two vectors

• The result of the scalar (dot) multiplication of two vectors is a scalar

• Scalar product via unit vectors

)ˆˆˆ)(ˆˆˆ( kBjBiBkAjAiABA zyxzyx

zzyyxx BABABABA

cosABBA

Page 5: Chapters 6, 7 Energy

Some calculus

• In 1D case

dt

dxv

dt

dva

dt

dx

dx

dv

dx

vdv

dx

vd

2

2

dx

mvd

Fma net

2

2

2

2mvddxFnet

Page 6: Chapters 6, 7 Energy

Some calculus

• In 1D case

• In 3D case, similar derivations yield

• K – kinetic energy

2

2mvddxFnet

2

2mvdrdFnet

Kd

2

2mvK

Page 7: Chapters 6, 7 Energy

Kinetic energy

• K = mv2/2

• SI unit: kg*m2/s2 = J (Joule)

• Kinetic energy describes object’s ‘state of motion’

• Kinetic energy is a scalar

James Prescott Joule(1818 - 1889)

Page 8: Chapters 6, 7 Energy

Work-kinetic energy theorem

• Wnet – work (net)

• Work is a scalar

• Work is equal to the change in kinetic energy, i.e. work is required to produce a change in kinetic energy

• Work is done on the object by a force

dKmv

drdFnet

2

2

f

i

r

r netif rdFKK

netW

Page 9: Chapters 6, 7 Energy

Work: graphical representation

• 1D case: Graphically - work is the area under the curve Fx(x)

f

i

x

x xdxFW

f

i

x

xx

xxF

0lim

Page 10: Chapters 6, 7 Energy

Chapter 6Problem 52

A force with magnitude F = a√x acts in the x-direction, where a = 9.5 N/m1/2. Calculate the work this force does as it acts on an object moving from (a) x = 0 to x = 3.0 m; (b) 3.0 m to 6.0 m; and (c) 6.0 m to 9.0 m.

Page 11: Chapters 6, 7 Energy

Net work vs. net force

• We can consider a system, with several forces acting on it

• Each force acting on the system, considered separately, produces its own work

• Since

f

i

r

r kk rdFW

) ( sumvectorFFk

knet

) ( sumscalarWWk

knet

f

i

r

r netnet rdFW

f

i

r

rk

k rdF

k

r

r k

f

i

rdF

Page 12: Chapters 6, 7 Energy

Work done by a constant force

• If a force is constant

• If the displacement and the constant force are not parallel

f

i

r

rrdFW

f

i

r

rrdF

rF

coscos FdrFrFW

Page 13: Chapters 6, 7 Energy

Work done by a constant force

coscos FdrFrFW

Page 14: Chapters 6, 7 Energy

Work done by a spring force

• Hooke’s law in 1D

• From the definition of work

kxFs

f

i

x

x ss dxFW f

i

x

xkxdx

22

22fi

kxkx

Page 15: Chapters 6, 7 Energy

Work done by the gravitational force

• Gravity force is ~ constant near the surface of the Earth

• If the displacement is vertically up

• In this case the gravity force does a negative work (against the direction of motion)

cosmgdWg

180cosmgdWgmgd

Page 16: Chapters 6, 7 Energy

Lifting an object

• We apply a force F to lift an object

• Force F does a positive work Wa

• The net work done

• If in the initial and final states the object is at rest, then the net work done is zero, and the work done by the force F is

mgdWW ga

gaifnet WWKKKW

Page 17: Chapters 6, 7 Energy

Power

• Average power

• Instantaneous power – the rate of doing work

• SI unit: J/s = kg*m2/s3 = W (Watt)

t

WPavg

dt

dWP

James Watt(1736-1819)

dt

dWP

dt

rdF

vF

cosFvP

Page 18: Chapters 6, 7 Energy

Chapter 6Problem 36

A 75-kg long-jumper takes 3.1 s to reach a prejump speed of 10 m/s. What’s his power output?

Page 19: Chapters 6, 7 Energy

Conservative forces

• The net work done by a conservative force on a particle moving around any closed path is zero

• The net work done by a conservative force on a particle moving between two points does not depend on the path taken by the particle

02,1, baab WW

2,1, baab WW

2,2, baab WW

2,1, abab WW

Page 20: Chapters 6, 7 Energy

Conservative forces: examples

• Gravity force

• Spring force

0 downup mghmgh

022

22

leftright kxkx

Page 21: Chapters 6, 7 Energy

Potential energy

• For conservative forces we introduce a definition of potential energy U

• The change in potential energy of an object is being defined as being equal to the negative of the work done by conservative forces on the object

• Potential energy is associated with the arrangement of the system subject to conservative forces

WU

Page 22: Chapters 6, 7 Energy

Potential energy

• For 1D case

• A conservative force is associated with a potential energy

• There is a freedom in defining a potential energy: adding or subtracting a constant does not change the force

• In 3D

if UUU

CdxxFxU )()(dx

xdUxF

)()(

kz

zyxUj

y

zyxUi

x

zyxUzyxF ˆ),,(ˆ),,(ˆ),,(),,(

f

i

x

xdxxFW )(

Page 23: Chapters 6, 7 Energy

Gravitational potential energy

• For an upward direction the y axis

f

i

y

ydymgyU )()( ymgmgymgy if

mgyyU g )(

Page 24: Chapters 6, 7 Energy

Gravitational potential energy

mgyyU g )(

Page 25: Chapters 6, 7 Energy

Elastic potential energy

• For a spring obeying the Hooke’s law

f

i

x

xdxkxxU )()(

22

22

if kxkx

2)(

2kxxU s

Page 26: Chapters 6, 7 Energy

Chapter 7Problem 37

A particle moves along the x-axis under the influence of a force F = ax2 + b, where a and b are constants. Find its potential energy as a function of position, taking U = 0 at x = 0.

Page 27: Chapters 6, 7 Energy

Conservation of mechanical energy

• Mechanical energy of an object is

• When a conservative force does work on the object

• In an isolated system, where only conservative forces cause energy changes, the kinetic and potential energies can change, but the mechanical energy cannot change

UKEmec

WK WU UK )( ifif UUKK

iiff UKUK imecfmec EE ,,

Page 28: Chapters 6, 7 Energy

Conservation of mechanical energy

• From the work-kinetic energy theorem

• When both conservative a nonconservative forces do work on the object

netWK

nccnet WWW ncWU K

ncWUK

Page 29: Chapters 6, 7 Energy

Internal energy

• The energy associated with an object’s temperature is called its internal energy, Eint

• In this example, the friction does work and increases the internal energy of the surface

Page 30: Chapters 6, 7 Energy

Chapter 7Problem 53

A spring of constant k = 340 N/m is used to launch a 1.5-kg block along a horizontal surface whose coefficient of sliding friction is 0.27. If the spring is compressed 18 cm, how far does the block slide?

Page 31: Chapters 6, 7 Energy

Conservation of mechanical

energy: pendulum

Page 32: Chapters 6, 7 Energy

Potential energy curve

dx

xdUxF

)()(

Page 33: Chapters 6, 7 Energy

Potential energy curve: equilibrium points

Unstable equilibrium

Neutral equilibrium

Stable equilibrium

Page 34: Chapters 6, 7 Energy

Questions?

Page 35: Chapters 6, 7 Energy

Answers to the even-numbered problems

Chapter 6

Problem 14:

9.6 × 106 J

Page 36: Chapters 6, 7 Energy

Answers to the even-numbered problems

Chapter 6

Problem 40:

The hair dryer consumes more energy.

Page 37: Chapters 6, 7 Energy

Answers to the even-numbered problems

Chapter 6

Problem 50:

360 J

Page 38: Chapters 6, 7 Energy

Answers to the even-numbered problems

Chapter 7

Problem 14:

(a) 7.0 MJ (b) 1.0 MJ

Page 39: Chapters 6, 7 Energy

Answers to the even-numbered problems

Chapter 7

Problem 24:

(a) ± 4.9 m/s (b) ± 7.0 m/s(c) ≈ 11 m

Page 40: Chapters 6, 7 Energy

Answers to the even-numbered problems

Chapter 7

Problem 38:

95 m