lecture - plastic hinging and moment redistribution

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  • 7/25/2019 Lecture - Plastic Hinging and Moment Redistribution

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    CVG 5144 AdvancedReinforced Concrete

    Plastic Hinging, PlasticLoad Capacity and Moment

    Redistribution

    Plastic Hinging and

    Moment Redistribution In continuous members the failure does not occur

    immediately after a section reaches its ultimate capacity.

    Upon reaching the ultimate moment capacity, the section

    develops a plastic hinge. As the hinge rotates under

    constant moment (equal to moment capacity), the

    member can sustain additional loads.

    Redistribution of moments occur under increased loads

    until others hinges form at other locations. The redistribution continues until the collapse

    mechanism if formed.

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    Plastic Hinging andMoment Redistribution

    Redistribution occurs only if plastic hinging regions have

    sufficient ductility.

    M

    Ductile Behaviour

    Brittle Behaviour

    Plastic Hinging andMoment Redistribution

    Consider the following two-span beam with a concentrated

    load at each mid-span:

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    Plastic Hinging andMoment Redistribution

    Plastic Hinging andMoment Redistribution

    Plastic Capacity

    If

    If

    IfFirst yielding takes place

    over supports

    First yielding takes place atmid-span

    Both supports and mid-

    span yield simultaneously

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    Plastic Hinging and MomentRedistribution

    If the section where the first yield occurs has sufficientductility, then the plastic hinge forms and the hinge start

    rotating, as moments and stresses are distributed towards

    elastic regions until other sections start yielding.

    Collapse occurs when sufficient number of hinges develop

    along the length of the member and the member becomes

    unstable, resulting in the collapse mechanism.

    Plastic hinges must have sufficient ductility to allow

    redistribution. Otherwise, the failure of the hinging region

    occurs prior to developing other hinges.

    Ductility of a Plastic Hinge In the previous example, how much does the negative

    moment hinge rotate before yielding takes place in the

    positive moment region?

    This can be computed. The rotation required to form

    moment redistribution is called Rotation Demand.

    A convenient way to compute the Rotation Demand is to

    use the Moment Area Theorem.

    The Moment Area Theorem can be applied by consideringelastic and plastic components separately.

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    Ductility of a Plastic Hinge

    Just before the collapse mechanism has formed

    (all hinges have formed)

    If the load was placed on a simplysupported beam:

    Rotation = Area under the M/EI

    diagram between two tangents

    Ductility of a Plastic HingeWhen the negative moment is applied

    on a simply supported beam:

    Rotation = Deflection between twotangents divided by the distancebetween the tangents.

    Deflection= Moment of the area underM/EI diagram between two tangents

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    Ductility of a Plastic Hinge

    Rotational demand to form thecollapse mechanism

    Plastic Rotation Capacity

    Plastic rotation

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    Available Ductility

    Available Rotation =

    Ductile MemberIf

    Brittle MemberIf

    For ductile behaviour

    Progressive CollapseA progressive collapse is a chain reaction of failureof building members to an extent disproportionate tothe original localized damage. Such damage mayresult in upper floors of a building collapsing ontolower floors.

    DoD 2005

    Progressive collapse is a situation where local failure

    of a primary structural component leads to thecollapse of adjoining members which, in turn, leads toadditional collapse. Hence the total damage isdisproportionate to the original cause.

    GSA 2003

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    Progressive Collapse

    Progressive collapse is defined as the spread ofan initial local failure from element to element,eventually resulting in the collapse of an entirestructure or disproportionately large part of it

    ASCE7-05

    Progressive collapse can be triggered by a varietyof events. Bomb blast is a typical overload that

    may lead to progressive collapse.

    Accidental Explosion

    Ronan Point Apartment Building London, England

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    Accidental Explosion

    Ronan Point Apartment Building London, England

    Blast Shock Wave

    Murrah Building Oklahoma City

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    Blast Shock Wave

    Khobar Building - Saudi Arabia

    Blast Shock Wave

    The building was ableto redistribute itsloads.

    No progressivecollapse.

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    Blast Pressures

    Typical Impulse

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    Structural Response to Blast

    Seismic versus Blast

    Progressive Collapse Analysis andDesign

    Alternate Load Path: Arrange structural elements toprovide stability to the entire structural system bytransferring loads from any locally damaged region toadjacent regions.

    Provide;

    Continuity and ductility

    Redundancy in lateral and vertical load paths

    Capacity for load reversals

    Increase shear capacity for ductility

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    Potential

    loss of acolumn

    Column Removal

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    Beam Longitudinal Reinforcement

    Earthquake Resistant Design Good for Blast Resistance

    Beam Transverse Reinforcement

    l

    4/ds1

    mm300s1

    bar.longb1 )d(8s

    hoopb1 )d(24s

    Hoops shall be provided through entire beam length

    Earthquake Resistant Design Good for Blast Resistance

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    GSA Progressive

    Collapse Analysis

    GSA

    Progressive

    Collapse

    Analysis

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    GSA Progressive Collapse Analysis

    Loading for static analysis:

    Load = 2(DL + 0.25LL)

    Demand/Capacity Ratio DCR:

    DCR = QD/QC

    QD = Force demand (moment, axial force, shear)QC = Unfactored capacity (may be increased by

    using 1.25 fy)

    GSA Progressive Collapse Analysis

    If sufficientlyductile sections toallowredistribution

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    GSA Progressive Collapse Analysis

    If sufficientlyductile sections toallowredistribution

    GSA Progressive Collapse Analysis

    Acceptance Criteria:

    DCR 2.0 for typical structural configurations

    DCR 1.5 for atypical structural configurations

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    Progressive Collapse Example

    Consider the removal

    of an interior column

    due to blast damage

    and assess different

    scenarios.

    W = 60 kN/m W = 60 kN/m

    57.6 kN.m 57.6 kN.m

    115 kN.m 115 kN.m

    250 kN.m

    500 kN.m 500 kN.m

    W = 60 kN/m W = 60 kN/m

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    W = 60 kN/mW = 60 kN/m

    Capacity

    Capacity

    500

    250 kN.m

    200

    600550

    Required (Demand)

    Progressive Collapse Example

    Progressive Collapse ExampleLoad carried at the formation of hinge at mid-span

    (3/8) l

    Mc

    Load carried after the formation

    of the hinge at mid-spanw2

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    Progressive Collapse Example

    Mc = 19.4 kN.m for EI = 4.3 x 1013 N.mm2

    (p)d= 0.00054 radw2

    uy

    e

    Capacity

    (p)cap = (u y) lp

    = (2 x 10-5 0.5 x 10-5) 500

    = 0.0075 rad

    Therefore, the beam hassufficient ductility