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Lecture 01 Chemical Equilibrium
1週次 日期 單元主題第 1週 2/26, 28 Chemical Equilibrium & Gravimetric Analysis (Ch 6 & 7) 第 2週 3/05, 07 Activity & Systematic Treatment of Equilibrium (Ch 12)第 3週 3/12, 14 Buffers & Acid-Base Titrations (Ch 8~10) 第 4週 3/19, 21 Polyprotic Acids & Bases (Ch 11) & EDTA Titrations (Ch 13)第 5週 3/26, 28 EDTA Titrations (Ch 13) & Experimental Error (Ch 3)
第 6週 4/024/04
第一次期中考 (佔學期總成績 30%)Statistics (I) (Ch 4)
第 7週 4/09, 11 Statistics (II) (Ch 4)
第 8週 4/164/18
Quality Assurance and Calibration Method (Ch 5)Fundamentals of Electrochemistry (Ch 14)
第 9週 4/23, 25 Electrodes, ISE, and Redox Titrations (Ch 15 & 16)第 10週 4/30, 5/02 Instrumental Methods in Electrochemistry (Ch 17)
第 11週 5/07, 09 Instrumental Methods in Electrochemistry (Ch 17)
第 12週
5/14,5/16
第二次期中考 (佔學期總成績 30%)Basics of Spectroscopy (Ch 18)
第 13週 5/21, 23 Spectrophotometry: Instruments (Ch 19)
第 14週 5/28, 30 Atomic Spectroscopy (Ch 20)
第 15週 6/04, 06 Principles of Chromatography (Ch 21)
第 16週 6/11, 13 GC & LC (Ch 22)
第 17週 6/18, 20 Electrophoresis (Ch 23)
第 18週 6/25 期末考 (佔學期總成績 40%)
Lecture 01 Chemical Equilibrium
2
Chemical EquilibriumaA + bB ⇌ cC + dD
at equilibrium
_____________
K =[C]c[D]d
[A]a[B]b concentration ratio:([A] or PA) ÷ (standard state,
i.e., M or bar)
the law ofmass action rateforward
= ratereverse
K, equilibrium const
solution: M or mol/Lgas: bar or atm
(1 bar~ 0.987 atm)
ex. pure liquidpure solidsolvent
pure materials: __
ex: ion-product const for water
solubility product const
standard state
2H2O ⇌ H3O+ + OH– K =[H3O+][OH–]
[H2O]2 [H2O]2K = [H3O+][OH–]
[H2O]: enormous concw.r.t. [H3O+] or [OH–]
= [H3O+][OH–]as if [H2O] → 1
Ba(IO3)2(s) ⇌ Ba2+(aq) + 2IO3–(aq)
K =[Ba2+][IO3
–]2
[Ba(IO3)2(s)] [Ba(IO3)2(s)]K = [Ba2+][IO3
–]
= [Ba2+][IO3–]
Lecture 01 Chemical Equilibrium
3
dimensionless
K, equilibrium const
standard state
= e–Go/RT
Chemical EquilibriumaA + bB ⇌ cC + dD
K =[C]c[D]d
[A]a[B]b
Keq = f(, , )
= e–(Ho – TSo)/RT
= e–Ho/RT + So/R
Le Chaterlier's Principle
Go < 0 Keq
[products]standard state [reactants]
standard state spontaneous rxn (i.e., rxn direction: ___)
Keq = f(T)
Ho or So rxn direction: ___
Ho >< 0 when T e–Ho/RT Keq
Q: favored rxn direction when T ?A: it _________ whether the rxn is
____thermic or ___thermic
Q: rxn quotient predicting the rxn direction (p 99) Q >< Keq
favored rxn direction
K, equilibrium const
the position of a rxn shifts toward the directionthat relieves the effects of the disturbance
heat/temperature: treated as if reactant/product
Lecture 01 Chemical Equilibrium
4
important equilibria in analytical chemistry
name ofequil constion-productconst
solubilityproduct
dissociationconst
formationconst
redoxconst
distributionconst
Skoog 8th edp 235, Table 9-2
Lecture 01 Chemical Equilibrium
5
Harris Fig 10-11 (7th ed)
Ka & Kb
acids/bases
http://web.jjay.cuny.edu/~acarpi/NSC/7-ph.htm
http://www.science.uwaterloo.ca/
~cchieh/cact/c123/stacids.html
Arrhenius
Brnsted-Lowry
Lewis
acid/base notes
_________
______ donorsacceptors
__ acceptorsdonors
limited to _______ soln
applicable to ___aqueous soln
more generalized;applicable to
organometallicsQ: Regarding the rxn:NH3(g) + HCl(g) ⇌ NH4Cl(s)is HCl an Arrhenius acid?
A: ___
Q: advantage of the concept ofBrnsted-Lowry acids/basesin titrimetry?
A: leveling effect (11.8) Ka of HClO4 & HCl
in water? leveling solvent differentiating solvent ex: titration in Me-C(O)-i-Bu
(methyl isobutyl ketone)w/ Bu4N+OH– (TBAOH)
acidity: HClO4 HClBF3 + NH3 ⇌Ni2+ + 6NH3 ⇌ Ni(NH3)6
2+
examples of Lewis acids/bases
Lecture 01 Chemical Equilibrium
6
Ka & Kb (section 6.5~6.7)
proton/hydronium ion (hydroxonium)
H2O + H2O ⇌ H3O+ + OH– Kw = [H+][OH−] = 1.0 x 10−14
proton does not exist by itself in water.
autoprotolysis
cluster ingas phase
in aqueoussolution
ion-dipoleattraction
protic/aprotic solvent protic: chemistry involving proton transfer
from one molecule to another protic solvent: having a reactive H+
aprotic solvent:no acidic H+, eg. CH2Cl2
NH3 + NH3 ⇌ NH4+ + NH2
–
AcOH + AcOH ⇌ AcOH2+ + AcO–
temp-dependent
oC pKw0 14.938
25 13.99550 12.265
pH pH = –logAH+ ≈ –log[H+]
Q: is there such a thing as Pure Water?
pH ≈ –log[H+], an approximation
Q: find pH of neutral soln at 50 oCA: pH ~
pH = 7.0 for neutral soln:true ____ at 25 oC
activity = conc x act. coeffAC = [C]C eq 8-4
A: no, if no precaution for___ + H2O ⇌ HCO3
– + __
Lecture 01 Chemical Equilibrium
7
dative/coordinate covalent bond: a bond betweena Lewis acid & a Lewis base
n or Ki
complex formation Lewis acid + Lewis base ⇌
formation constant n: _______ Ki: _______
formation constant
n = K1 x K2 x ... x Kn
ex: Pb2+ + 4I– ⇌ PbI42–
Pb2+ + I– ⇌ PbI+
PbI+ + I– ⇌ PbI2(aq)
PbI2(aq)+ I– ⇌ PbI3–
PbI3– + I– ⇌ PbI4
2–
K1
K4
K3
K2
=[PbI+]
[Pb2+][I–]
= [PbI42–]
[PbI3–][I–]
4 = K1 x K2 x K3 x K4
= [PbI2(aq)][PbI+][I–]
[PbI3–]
[PbI2][I–][PbI4
2–][PbI3
–][I–]
[PbI+][Pb2+][I–]
=[PbI4
2–][Pb2+][I–]4
rxns Keq = n
= K1 x K2 x ... x Kn
Lecture 01 Chemical Equilibrium
8
Ksp
to find ion conc (if the conc of the other(s) is(are) known)
common ion effect:____ soluble for a salt when one of its constituents already present
ex: given that Hg2Cl2(s) ⇌ Hg22+ + 2Cl–
MXn(s) ⇌ Mp+(aq) + nXq–(aq) Ksp = [Mp+][Xq–]n
Q: find (1) [Cl–] in pure water(2) solubility of Hg2Cl2 in pure water(3) solubility of Hg2Cl2 in 0.10 M KCl soln
Ksp = [Hg22+][Cl–]2 = 1.2 x 10–18
ex: given that solubility for KCl is 3.7 M(i.e., Ksp ≈ ___ x ___ = 13.7)explain the different behaviorsbetween the two test tubes (p 102)
6 M 12 M
1 volume sat'd KCl(aq)
w/o precipitant
homo-geneoussoln
KCl(s)
add 1 volumeof HCl(aq) ex: SCaSO4
= f(dissolved CaCl2)
Harris Fig 6-1, 7th ed
Lecture 01 Chemical Equilibrium
9
Harris Fig 6-1, 7th ed
ex: SCaSO4
= f(dissolved CaCl2)
Ksp
to find ion conc (if the conc of the other(s) is(are) known)
MXn(s) ⇌ Mp+(aq) + nXq–(aq) Ksp = [Mp+][Xq–]n
common ion effect
ex: for a soln containing 0.010 M Pb2+ & 0.010 M Hg22+
given that Hg2I2(s) ⇌ Hg22+ + 2I– Ksp = [Hg2
2+][I–]2 = 1.1 x 10–28
PbI2(s) ⇌ Pb2+ + 2I– Ksp = [Pb2+][I–]2 = 7.9 x 10–9
Can [I–] be used to precipitate 99.99% Hg22+
and to keep Pb2+ soluble in soln?
simple cases: no rxns other than Ksp involved
A: [Hg22+] = S; [I–] = __
Ksp = [Hg22+][I–]2 =
S =
separation by precipitation
solubility of salts
ex: find solubility of Hg2I2 in pure watergiven that Hg2I2(s) ⇌ Hg2
2+ + 2I–
Ksp = [Hg22+][I–]2 = 1.1 x 10–28
complicated cases:other rxns also taking place,such as hydrolysis, disproportionation,
ion pairs, complex formation, redox, ... ...
= [Ca2+] + [CaSO4(aq)]
Hg22+ + H2O
⇌ Hg2OH+ + H+
Hg22+ ⇌ Hg2+ + Hg()
Lecture 01 Chemical Equilibrium
10
solubility solubility of salts
MXn(s) ⇌ Mp+(aq) + nXq–(aq) Ksp = [Mp+][Xq–]n
complicated cases: when [Xq–] precipitate MXn may redissolve as MXij–
ex: Pb2+ + 4I– ⇌ PbI42–
Pb2+ + I– ⇌ PbI+
PbI+ + I– ⇌ PbI2(aq)
PbI2(aq)+ I– ⇌ PbI3–
PbI3– + I– ⇌ PbI4
2–
K1
K4
K3
K2
=[PbI+]
[Pb2+][I–]
= [PbI42–]
[PbI3–][I–]
2=[PbI2(aq)][Pb2+][I–]2
Q: write solubility of PbI2(s) = f([I–])A: S = [Pb2+] + [PbI+] + [PbI2(aq)] + [PbI3
–] + [PbI42–]
i.e., find [Pb2+], [PbI+], ... ... , [PbI42–] = f( )
[Pb2+] = Ksp/[I–]2
[PbI+] = K1[Pb2+][I–]
[PbI2(aq)] = K2[PbI+][I–]= __________
[PbI3–] = K3K2K1[Pb2+][I–]3 = 3[Pb2+][I–]3
[PbI4–] = K4K3K2K1[Pb2+][I–]4 = 4[Pb2+][I–]4
= K2_____[I–]2
Pb2+ + 2I– ⇌ PbI2(aq)
Q: find solubility of PbI2(s)when [I–] = (a) 1.0 mM, (b) 1.0 M
A: S = [Pb2+] + [PbI+]+ [PbI2(aq)]+ [PbI3
–] + [PbI42–]
put the #s into the eqns straightforward
Q: which formdominate the solubility?
A:
Lecture 01 Chemical Equilibrium
11
solubility (Ksp, ion pairs, charged complexes)
solubility of salts complicated cases: when [Xq–] precipitate MXn may redissolve as MXi
j–
Harris Fig 6-3
A: S = [Pb2+] + [PbI+] + [PbI2(aq)]+ [PbI3
–] + [PbI42–]
[Pb2+] = Ksp/[I–]2
[PbI+] = K1[Pb2+][I–][PbI2(aq)] = 2[Pb2+][I–]2
[PbI3–] = 3[Pb2+][I–]3
[PbI4–] = 4[Pb2+][I–]4
ex: solubility of PbI2(s) at 1.0 mM & 1.0 M
7.9 x 10–3
[I–] = 1.0 mM & 1.0 M
7.9 x 10–4
1.1 x 10–5
6.6 x 10–8
2.4 x 10–10
7.9 x 10–9
7.9 x 10–7
1.1 x 10–5
6.6 x 10–5
2.4 x 10–4
Solubility = 8.7 x 10–3
+
3.2 x 10–4
Q: why do complex formsdominate solubility when [I–] ?
Q: why does [PbI2(aq)] ≠ f([I–])?A: [PbI2(aq)] = 2[Pb2+][I–]2
Lecture 01 Chemical Equilibrium
12
Skoog Fig 11-2
solubility (Ksp, ion pairs, charged complexes)
solubility of salts complicated cases: when [Xq–] precipitate MXn may redissolve as MXi
j–
ex: solubility of AgCl(s) is cKCl–dependent
Q: why does[AgCl(aq)] ≠ f([Cl–])?
Q: why docomplex formsdominate solubilitywhen [Cl–] ?
AgCl ⇌ Ag+ + Cl– Ksp = [Ag+][Cl–]= 1.8 x 10–10
A: S = [Ag+] + [AgCl(aq)] + [AgCl2–] + [AgCl3
2–]
Lecture 01 Chemical Equilibrium
13
precipitate gravimetric analysis (Chapter 7)
general concept
A: introduce ______ Ag+ collect & weigh AgCl(s) calculate mole of precipitate calculate [Cl–]
ex: how to find [Cl–] in an aqueous soln AgCl ⇌ Ag+ + Cl– Ksp = [Ag+][Cl–]= 1.8 x 10–10
ex: find [Cl–] in a 10.00-mL aqueous solngiven that treatment with excess AgNO3
resulting in precipitate of 0.4368 g of AgClA: mol of Cl– = mole of AgCl(s)
= [wt of AgCl(s)]/[(formal mass of AgCl)]= 0.4368/143.321= 3.048 x 10–3 mol
[Cl–] = (3.048 x 10–3 mol)/(10.00 mL) = 0.3048 M
( selective (not specific)–Table 27.1Ksp, AgCl: sufficiently small Ag+: precipitant for Cl–)
Q: how good is the result?what may cause false results
—heavier/lighter than the theoretical wtdesired properties of precipitate
for gravimetric analysis?
A: very pure, easily filterable, known composition math: easy; good precipitate: difficult
ideal precipitate: large & crystalline
Ci−
excessAg+
AgCl
Harris Fig 6-3
Q: disadvantages ofsmall particles of precipitate?
A: colloidal suspension ___ precipitating
________ filter passing filter false resultslarge ________ impurity
adsorption
Lecture 01 Chemical Equilibrium
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determination of [Cl–] in soln (Skoog 37B-1)
Lecture 01 Chemical Equilibrium
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Gravimetric Determination [Cl–] in a soluble sample
Harris Fig 2-12
Lecture 01 Chemical Equilibrium
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Gravimetric Determination [Cl–] in a soluble sample
HarrisFigs 2–14
17
Lecture 01 Chemical Equilibrium
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Gravimetric Determination [Cl–] in a soluble sample
http://www.harpercollege.edu/tm-ps/chm/100/dgodambe/thedisk/labtech/trans2.jpg
Lecture 01 Chemical Equilibrium
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Gravimetric Determination [Cl–] in a soluble sample
http://www.harpercollege.edu/tm-ps/chm/100/dgodambe/thedisk/labtech/filter3.htm
place & wetthe filter paper
Lecture 01 Chemical Equilibrium
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relative supersat'n
mech of precipitate formation & expt'l strategies general concept
ideal precipitate: large & crystalline mech of crystal growth mixing reagents → nucleation & particle growth
expt'l strategies Q term:
as few as 4~5 nuclei form stable clusters
& ads on dusts/contaminants super-saturation
relativesupersat'n
mixing analytew/ precipitant
nucleation
furthernucleation
particlegrowth
=
Q: Csolute at ___ instantS: ________ at equilibrium
S term:
dilution Csolute ______ adding precipitant
T S
______ while adding precipitant
adjusting soln pH for those w/ S = f(pH)
Harris Fig 6-3
Cl–
excessAg+
AgCl
Lecture 01 Chemical Equilibrium
20
NO3–
NO3–
NO3–
NO3–
NO3–
NO3–
NO3–
NO3–
NO3–
NO3–
NO3–
NO3–NO3
–
NO3–
NO3–
NO3–
NO3–
NO3–
H+
H+
H+
H+
H+
2d2
2d1
particle counter-ionlayer
effect of electrolyte on precipitation & expt'l strategies electrical double layer of a colloid
expt'l strategies Q term: S term:
excess precipitant Qads dctr-ion layer
primary adsorption layer originated from bonding forces for crystal growth resulting in excess/___ surface ______
counter-ion layer driven by electroneutrality excess # of counter ions
preventing colloidsfrom colliding/precipitation
strength of chemisorption: Agads > Hads
bond strength: Ag−Cl > H−Cl
repulsion/stability of colloids= f(dcounter-ion layer)
Celectrolyte densityctr ion dctr-ion layer
Celectrolyte:
d: thickness ofcounter ion layer
heating adsorbility Qads
stirring Ek overcome Erepulsion
heating stirring Skoog Fig 12-1~3Harris Fig 7-2
Lecture 01 Chemical Equilibrium
21
coprecipitation
types of coprecipitation
—introducing contaminants/impurity coprecipitation errors
—species that should be _______is precipitated along with the desired product
soln ____ ______________ forms
a process thata coagulated colloid______ _____
losing weakly bound water ______ solid/smaller surf area easier to filter
digestion
washing
reprecipitation
surface adsorption mixed-crystal formation: lattice sites occupied by
impurities w/ properties similar to those of analyte
occlusion: ions in the counter-ion layerare _______ in the ______ formed during particle growth
methods to remove impurities/improve purity
precipitate is heated (w/o stirring) for ~1 hr in mother liquor
a process after filtration to remove impurity washed w/ pure water dctr-ion layer peptization washed w/ soln containing ________ electrolyte
ex: washing AgCl(s) w/ diluted HCl which evaporates later upon drying (high T)
redissolve the filtered solid & reprecipitate it
effective (but )redissolved soln: ____ contaminants
ex: SrSO4 in BaSO4MnS in CdS
Lecture 01 Chemical Equilibrium
22
homogeneous precipitation
drying & ignition of precipitates
—precipitating agent:homogeneously & slowlygenerated throughout the soln
aluminum hydroxide
NH4OH (H2N)2COex:
Q – SS
very small __ in ________ ______Skoog Fig 12-5
(Harris p 137 & Table 7-3)
1~2 hrs
const mass& known compositionex:
removal of solvent, volatile species decomposition
purpose: to obtain the weighing form
Harris Fig 7-3