math 1 lec 02: function instructor: dr. nguyen quoc lan (october, 2007)
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HUT – DEPARTMENT OF MATH. APPLIED --------------------------------------------------------------------------------------------------------. MATH 1 LEC 02: FUNCTION Instructor: Dr. Nguyen Quoc Lan (October, 2007). - PowerPoint PPT PresentationTRANSCRIPT
HUT – DEPARTMENT OF MATH. APPLIED
--------------------------------------------------------------------------------------------------------
MATH 1
LEC 02: FUNCTION
Instructor: Dr. Nguyen Quoc Lan (October, 2007)
NOTION OF FUNCTION ---------------------------------------------------------------------------------------------------------------
--------------------
Some quantity A changes and depends on
another quantity B Function: A = f(B).
Example: The human pouplation depends
on the timeYear Population (million)
1910 1750
1920 1860
1930 2070
1940 2300
1950 2560
1960 3040
HISTORY ---------------------------------------------------------------------------------------------------------------
--------------------
Mid – eighteenth
century, Euler: By
alphabet y = f(x)
1786,
Scotland: The
Commercial
an Political
Atlas,
Playfair.
Graph used
to compare
exports,
imports by
England to
Denmark …
f Function
x Input Computer y Output
MATHEMATICAL DEFINITION ---------------------------------------------------------------------------------------------------------------
--------------------RX
RY A function y = f(x): X R Y
R: Rule associates each x
X unique output (exactly
one) y Y. Variable x,
function (value) y.One x Two
different y: It’s not a
function Vertical
test (for a graph)
Domain D = {x| f(x)
defined}Range Imf: y =f(x),
xDf y = sinx D= R, Imf =
[–1, 1]
THE VERTICAL LINE TEST ---------------------------------------------------------------------------------------------------------------
--------------------
The Vertical Line Test: a curve in the xy-
plane is the graph of a function of x if and
only if no vertical line intersects the curve
more than once
(a,b)
x=a
a
(a,b)
(a,c)
a
x=a
This is the
graph of a
function of x
This is not the graph
of a function of x
GIVE A FUNCTION: TABLE OF ITS VALUE ---------------------------------------------------------------------------------------------------------------
--------------------
Verbally and table of it values: The natural
way to represent the function C(w)
expressing the cost of mailling first class
letter is using a table of valuesw (ounces) C(w) (dollars)
0<w1 0.34
1 <w2 0.56
2 <w3 0.78
3 <w4 1.00
4 <w5 1.22
…
GIVE A FUNCTION: GRAPH ---------------------------------------------------------------------------------------------------------------
--------------------
Plot a picture (graph): For the function P(t)
expressing the dependence of human
population in time, one can express it by
table of values, then construct a graphP(t)
0
1000
2000
3000
4000
5000
6000
7000
1880 1900 1920 1940 1960 1980 2000 2020
P(t)
The
graph
of this
function
is a
scatter
plot
FUNCTION DEFINED BY ALGEBRAIC FORMULA --------------------------------------------------------------------------------------------------------------------
-----------------------
Explicit form: y =
f(x)Example: y = x2, elementary
functions
tyy
txx:form Parametric
Example: x = 1 + t, y = 1 – t
Line
: 1 t 1 (x,
y)
Example: x = acost, y = asint
Circle
Implicit form F(x, y) = 0 y
= f(x)Example: x2 + y2 –
4 = 0,
01916
22
yx
Formul
a:
MAPLE ---------------------------------------------------------------------------------------------------------------
--------------------
(Declare a function) p := x^3 +
x^2 + 1; (Evalue its value)
subs(x=1, p); (Evalue its limit) limit(
sin(2*x)/x, x = 0) ; (Evalue its derivative) diff(p, x) ; (2nd order)
diff(p,x$2) (Graph) plot(sin(x), x = 0..Pi); (Many graphs)
plot( [sin(x),cos(x)],x = 0..2*Pi, color =
[red,blue]); (Parametric curve) plot( [31*cos(t)-
7*cos(31*t/7), 31*sin(t)-7*sin(31*t/7), t =
0..14*Pi] ); plot( [17*cos(t)+7*cos(17*t/7), 17*sin(t)- …, t
= 0..14*Pi] );
MATHEMATICAL MODEL: RADIOACTIVE DECAY -----------------------------------------------------------------------------------------------------------------
---------------
Radioactive elements disintegrate continuously
in a process called radioactive decay.
Experimentation has shown that the rate of
disintegration is proportional to the amount of
the element present. Find the rule of the
radioactive decay processSolution: Suppose that m = m(t): the amount at
time t The rate of disintegration is dm/dt. The
assumption above gives: minus issign the,:m(t) As constant. positive :k kmdtdm
00.lnln mCtCetmCktmkdtmdm kt
MATHEMATICAL MODEL: RADIOACTIVE DECAY -----------------------------------------------------------------------------------------------------------------
---------------
By the expression of m(t), all radioactive
elements have a common special property: after
some constant period of time, its original amount
will reduce by half the half – life. Every
radioactive element has a specific half – life, and
it depends only on decay rate, not on the initial
amountThe half – life of radioactive carbon C – 14 is
about 5730 years. Find the expression m(t) of C
– 14?Solution: T – the half – life The amount: m0/2
at time T: T
kkTeRR kT 2ln
2ln2 0
0 teRtRT 000121.005730
THE SHROUD OF TURIN -----------------------------------------------------------------------------------------------------------------
---------------
In 1988 the Vatican authorized the British
Museum to date a cloth relic called the Shroud
of Turin, possibly the burial shroud of Jesus of
Nazareth. This cloth founded in 1356 and
contains the negative image of a human body.
From the British Museum: the fibers in the cloth
contained between 92% and 93% of their
original carbon C – 14. Conclusion?Solution:
From
teRtR 000121.0
0
0
ln000121.0
1RtR
t
R/R0: 0.92 0.93
60093.0ln&68992.0ln 21 tt
The test: 1988 The shroud was between 600 –
688 years old!