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Recruitment Examination- 2017

Post: Executive Officer (Morning)

(Mathematics)

1. Find the greatest number that will divide

43, 91 and 183 so as to leave the same

remainder in each case. (indiabix.com)

[A]. 4

[B]. 7

[C]. 9

[D]. 13

Answer: Option A

Explanation:

Required number = H.C.F. of (91 - 43), (183 -

91) and (183 - 43)

= H.C.F. of 48, 92 and 140 = 4.

2. In a business, A and C invested amounts in the

ratio 2:1, whereas the ratio between amounts

invested by A and B was 3:2. If Rs. 1,57,300 was

their profit, how much amount did B receive ?

(sawaal.com)

A) 48400 B) 54200

C) 64000 D) 74000

Answer: A) 48400

Explanation:

A : B = 3 : 2 => B : A = 2 : 3 = 4 : 6 and A : C = 2 : 1

= 6 : 3.

So, B : A : C = 4 : 6 : 3 or A : B : C = 6 : 4 : 3.

B's share = Rs. (157300 x 4/13 ) = Rs. 48400.

3. Which one of the following is not a prime

number? (indiabix)A. 31

B.61

C.71

D. 91

Answer: Option D

Explanation:

91 is divisible by 7. So, it is not a prime number.

4. (0.04)-1.5 = ? (indiabix)A. 25

B.125

C.250

D. 625

Answer: Option B

Explanation:

(0.04)-1.5 = 4

-1.5 100

= 1

-(3/2) 25

= (25)(3/2)

= (52)(3/2)

= (5)2 x (3/2)

= 53

= 125.

5. A sum of money is borrowed and paid back in

two annual instalments of Rs. 882 each allowing

5% compound interest. The sum borrowed was:

A.

182

0

B. 1640

C.

126

0

D. 1440

Here is the answer and explanation

Answer : Option B

Explanation :

Present worth of Rs. x due T years hence is given by

Present Worth (PW) = x(1+R100)T

The sum borrowed

= Present Worth of Rs.882 due 1 year hence +

Present Worth of Rs.882 due 2 year hence

=882(1+5100)1+882(1+5100)2=882(105100)+882(1

05100)2=882(2120)+882(2120)2=8822021+8822

0202121=4220+42202021=840+22020=84

0+800=1640

i.e., The sum borrowed = Rs.1640

6. What is the unit digit in the product (684 x 759

x 413 x 676)?

A. 4

B. 12

C. 8

D. 16

Sol. Unit digit in the given product

= unit digit in the product (4x 9 x3 x6) = 8.

7. A certain number of men can finish a piece of

work in 100 days. If there were 10 men less, it

would take 10 days more for the work to be

finished. How many men were there originally?

(sawaal.com)

A) 75 B) 82

C) 100 D) 110

Answer: D) 110

Explanation:

Originally let there be x men.

Less men, More days (Indirect Proportion)

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(x-10) : x :: 100

:110 10x= 1100 x=

110

8. One year ago, Pinky was four times as old as

her daughter Soma. Six years hence, Pinkys age

will exceed her daughter's age by 9 years. The

ratio of the present ages of Pinky and her

daughter is:

A. 9 : 2 B. 11 : 3 C. 13 : 4 D. 12 : 5

9. The ratio between the perimeter and the

breadth of a rectangle is 5 : 1. If the area of the

rectangle is 216 sq. cm, what is the length of the

rectangle? (indiabix)

A. 16 cm

B. 18 cm

C. 24 cm

D. Data inadequate

E. None of these

Answer: Option B

Explanation:

2(l + b) =

5

b 1

2l + 2b = 5b

3b = 2l

b = 2 l

3

Then, Area = 216 cm2

l x b = 216

l x 2 l = 216

3

l2 = 324

l = 18 cm.

10. (87 X 87 + 61 X 61 -2 X 87 X 61) =?

A. 198 B. 196 C. 296 D. 298

Ans: 676

11. A is faster than B. A and Beach walk 24 km.

The sum of their speeds is 7 km/hr and the sum of

times taken by them is 14 hours. Then, A;s speed

is equal to:

(jake runs faster than paul.jake and paul each

walk 24kms.the sum of the speeds is 7km/hr and

the sum of the time taken by them is 14 hrs.then

jake's speed is?)

ANS:

sol: 24/7-j + 24/j =14

24j + 24(7-j)/ (7-j)j

here j is jack speed n 7-j is paul

on solving we get a eqn

14j^2-98j+168=0

solving we get j=4 n 3

but jack is faster hence ans is 4 km/hr..!!

-------------------------

Say speed of Jake is J and Speed of Paul is P.

Given J + P = 7 . (Eq.1)

Time = Distance/speed.

Time taken by Jake to cover 24 km = 24/J hours

Time taken by Paul to cover 24 km = 24/P hours Given, sum of times = 24 hours.

(24/J) + (24/P) = 14 (1/J) + (1/P) = 7/12 Using Eq.1,

(J + P)/(JP) = 7/12 J P = 12 (J P)2 = (J + P)2 4JP = 72 4 12 = 1 (J P) = 1 . (Eq.2) Eq.1 + Eq.2

2J = 8 J = 4 km/h

12. How many times in a day, the hands of a

clock are straight? (indiabix)

[A]. 22

[B]. 24

[C]. 44

[D]. 48

Answer: Option C

Explanation:

In 12 hours, the hands coincide or are in opposite

direction 22 times.

In 24 hours, the hands coincide or are in

opposite direction 44 times a day.

13. Sum of two numbers is 40 and their difference

is 4. The ratio of the numbers is

10:3

5:9

11:9

13:9

Answer: Option C

Explanation:

Let first number is m and second number is n.

Then m + n = 40 ---------[1]

And m n = 4 -------------[2]

Adding eq. 1 and eq. 2

We get, 2m = 44 m = 22 Putting value of m in eq. (1), we get n = 18

m : n = 22 : 18 m : n = 11 : 9

14. Two trains are running in opposite directions

with the same speed. If the length of each train is

120 metres and they cross each other in 12

seconds, then the speed of each train (in km/hr) is:

(indiabix)

A. 10

B. 18

C. 36

D. 72

Answer: Option C

Explanation:

Let the speed of each train be x m/sec.

Then, relative speed of the two trains = 2x m/sec.

So, 2x = (120 + 120)

12

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2x = 20

x = 10.

Speed of each train = 10

m/sec =

10

x

18

km/hr = 36

km/hr.

15. The average of first 50 non-zero positive

integers is (algebra.com)

A. 11.5 B. 25.5 C. 22.5 D. 25

Answer :(B)

25.5

Description :

Sum of first n non-zero positive integers n(n + 1)/2

So, average of first n non-zero positive integers n(n +

1)/2n = (n + 1)/2

=> (50 + 1)/2 = 25.5

16. In an election a candidate who gets 84% of the

votes is elected by a majority of 476 votes. What is

the total number of votes polled. (Hotel

Management, 2003)

A) 300

B) 700

C) 749

D) 848

Explanation:

17. The square root of (7 + 35) (7 - 35) is (indiabix)

18. A sum of money lent out at simple interest

amounts to 720 Rs. after 2 years and to 1020

Rs. after a further period of 5 years. The sum

is

: [A]500 Rs. [B]600 Rs. [C]700 Rs. [D]710 Rs.

600 Rs.

Principal + SI for 2 years = 720 Rs. (I)

Principal + SI for 7 years = 1020 Rs. (II)

Subtracting equation (I) from (II),

S.I. for 5 years = (1020 720) = 300 Rs.

S.I. for 2 years = 300\times \frac{2}{5} = 120 Rs.

Principal = (720 120) = 600 Rs. (Description :

S.I. for 5 year = Rs.(1020 - 720)

= Rs. 300.

S.I. for 2 year = Rs.(300/52)

= Rs. 120.

Principal = Rs. (720 - 120)

= Rs. 600.)

20. 138.009 + 341.981 - 146.305 = 123.6 + ? (sawaal.com)

A) 120.o85 B) 199.57

C) 295.05 D) None of these

Answer: D) None of these

Explanation:

Let 138.009 + 341.981 - 146.305 = 123.6 + z

Then, z = (138.09+341.981) - (146.305+123.6)=

479.99 - 269.905 = 210.085

19. In a certain store, the profit is 320% of the

cost. If the cost increases by 25% but the

selling price remains constant, approximately

what percentage of the selling price is the

profit? (indiabix)

[A]. 30%

[B]. 70%

[C]. 100%

[D]. 250%

Answer: Option B

Explanation:

Let C.P.= Rs. 100. Then, Profit = Rs. 320, S.P. =

Rs. 420.

New C.P. = 125% of Rs. 100 = Rs. 125

New S.P. = Rs. 420.

Profit = Rs. (420 - 125) = Rs. 295.

Required

percentage =

295 x

100 %

=

1475 % = 70%

(approximately). 420 21

Let the total number of votes polled be x. Then, votes polled by other candidate

= (100 - 84) % of x = 16% of x

http://skillgun.com/question/4170/arithmetic/averages/the-average-of-first-50-nonzero-positive-integers-ishttp://skillgun.com/question/4170/arithmetic/averages/the-average-of-first-50-nonzero-positive-integers-is

Today's Janata Bank Executive

Officer Exam(2nd shift)

Math solution

1.

2+3+7+9+11= 28

2.

2x+3y = 39

3x+2y = 36

x = 6

y = 9

ans- 9

3.

100% = 120

125% = 120*125/100

= 150

again

110% = 198

100% = 198*100/110

= 180

pofit = 180-150 = 30

% = 30*100/150

= 20%

4.

x*15*12 = 10*6*18

x = 6

5.

122.5% = 392

100% = 392*100/122.5

= 320

profit = 72

6.

100.....increase 2

600...................12

for 4yr =12*4 = 48

720+48 = 768

7.

(17+3)*5 = 100

17*6 = 102

ans 2yrs

8.

20+10 = 30

20-10 = 10

10*3 = 30

ans : 20

9.

Total = 100

A = 30

remaining = 70

B = 60%

remaining = 40%

now, 40% of 70 = 28

diff= 30-28 = 2

2% = 1200

100% = 1200*100/2

= 60000

10.

3140000

solved by

Md. Ashraful Islam

11.

75/10x - 75/15x = 12.5

1/x(7.5-5) = 12.5

x= 1/5 km/min

so, 10*60*1/5 = 120 km/hr

12.

3(x+3) - 3(x-3)

= 18

13.

2q+1 = 1-q

q= 0

14.

24+8*2 = 40

15.

A+B = 5*20/5+20

= 4 hrs

1/4 - 1/C = 1/4.5

C = 36 hrs

16.

-20% - 10% + (-20)*(-10)/100 %

= -28%

17.

10*root(125-25)*5 = 500

18.

(root2)^n = root(2)^ 12

n = 12

19.

let,

6-x/7-x = 16/21

x= 2.8

as least

so ans : 3

6-3/7-3 = 3/4 = 3*5/4*5 = 15/20 <

16/21

20.

50ab = 75bc

c = 2a/3 = 0.67a

Solved by

Md. Ashraful Islam

=============

Solution of English Part (

Afternoon) ( Janata Bank..EO 2017 )

1. Laudable

2. Generosity

3. Criticise

4. Failure

5. Correct Manners

6. C

7. D

8. C

9. C

10. A

11. Revolutionary

12. Bookworm

13. Regicide

14. Heresy

15.Geologist

16. Deceives

17. To spend lavishly

18. Final outcome

19. A sudden idea

20. Do a mild business to keep busy

21. Dolorous

22. Sedate

23. Suggest

24. Canine

25. Jovial

()

=================================

. --

. --

. --

. --

.

--

. Dhaka

. --

. --

--

. --

.

. --

. --

.

. --

.

. --

.

. --

. --

=

)

-

) ,

-

) -

) -

) -

) -

) - ,

) - -

) -

) -

) -

)

)Notification

-

)

-

) -

) -

===============

Part-1

Fill in the black

1. Increase, populist

2. Several, behaves

3. Offender, details

4. Carelessness, nullify

5. Difficult, perseverance

.

Part-2

Best replaces:

1. sets the fire on the bus--set the bus on fire

2. being cordially-- being cordial to

3. for keep up the city clean -- to keep the city

clean

4. take place around-- taking place around

5. so much similar in-- so different in

.

Part-3

SYNONYMS:

1. MOROSEdepressed

2. SUNDRYVarious

3. AGILITYquickness

4. OSTENTATIONShowy

5. LATENT--- Concealed

.

Part-4

Similar or Opposite:

1. Transit-Permanent-B(1-3)

2. Ambience-Atmosphere-A(1-3)

3. Vivacious-Fanatical-D(3-4)

4. Poor-Sterling-B(3-4)

5. Benevolent-Charitable-D(1-3)

.

Part-5

Spelling:

1. Acquaintance

2. Accommodate

3. Occurred

4. Erroneously

5. Demurrage

============

Computer Part:

================

1. FTP = file transfer Protocol

2. insted of binary machine code = Symbolic code

3. Excel file into a word document = Placed in a

word table

4. Processor use RISC technology = power pc

5. Keyboard = Input

6. Plotter accuracy = Resolution

7. First electronic computer = ENIAC

8. FORTRAN = Formula Translation

9. Spelling Check = F7

10. Cybernetics = Control and communication

=====================

Math solution

1.( 87-61)^2 = 26^2 = 676

2. 4*9= 6

6*3 = 8

8*6= 8

3. 91

4. 43 4 , 40+3 remainder=3

914, 88+3 r= 3

1834 = 180+3 r =3

ans-4

5. 210.085

6. root[( 7)^2 -(3root5)^2]

=root 4 = 2

7. 50*51/2*50 = 25.5

8. x+y = 40

x-y = 4

x= 22

y = 18

ratio = 11:9

10. 13-4 = 9

(13-1)3 = 4

13:4

Solved by

Md. Ashraful Islam

11. 1/(0.04^1)* (0.04^0.5)

= 1/0.04*root0.04

= 1/0.04*0.2 = 100*10/8

= 125

12. ( 84-16)% = 476

100% = 476*100/68 =700

13. initial cost price = 100

sell price = 420

at 25% increase CP = 125

Profit = 295

% = 295*100/420 = 70%

14.

A:C = ( 2:1)*3= 6:3

A:B = (3:2)*2 =6:4

B gets = 157300*4/13 = 48400

15.

x*100 = 110(x-10)

x= 110

16.

x+y = 7

24/x + 24/y = 14

24(x+y/xy) = 14

xy = 12

so, x=4

y = 3

Ans = 4

17.

(120+120)/12 = 20 m/s

20/2 = 10m/s = 36 km/h

18.

7yr sum+profit = 1020

2 yr sum+profit = 720

5 yr = 300

2 yr profit = 300*2/5 = 120

sum = 720-120 = 600

19.

5:1 = 10:2

Br = 2x

Ln = 10x/2 -2x = 3x

now, 3x*2x = 216

x= 6

3x = 18 cm

20.

Ans: 44

Solved by

Computer Part:

1. FTP = file transfer Protocol 2. insted of binary machine code = Symbolic code 3. Excel file into a word document

= Placed in a word table 4. Processor use RISC technology = power pc 5. Keyboard = Input 6. Plotter accuracy =

Resolution 7. First electronic computer = ENIAC 8. FORTRAN = Formula Translation 9. Spelling Check = F7 10.

Cybernetics = Control and communication

SOURCE:

Khairuls Basic Math

& Khairuls Bank Math:

[Janata Bank (EO)-2017(Afternoon)]

1. The sum of two numbers is equal to thrice their difference. If the smaller of the number is

10.find the other number [Janata Bank (EO)-2017 (afternoon)]

a.15 b.20 c.40 d.None of these

Solution: (b)Let the larger number is x

ATQ, x+10 = 3(x-10) or, x+10 = 3x-30 or, -2x=-40 so, x = 20 Ans: 20

2. The average age of 8 men is increased by 2 years when one of them whose age is 24 years

is replaced by a woman. What is the age of the woman [Janata Bank (EO)-2017

(afternoon)]

a.35years b.28years c.32 years d.40years

Solution: (d)8 Rbi eqm 2 eQi Ki evoj gvU evoe 82 = 16 eQi| A_vr bZzb Avmv gwnjvwU Pj hvIqv 24 eQi

eqmx jvKi Pq 16 eQi eo| myZivs gwnjvi eqm = 24+16 = 40 eQi|

3. 50% of a% of b is 75% of b% of C. Which of the following is C ? [Janata Bank (EO)-

2017 (afternoon)]

a.1.5a b.0.667a c.0.5a d.1.25a

Solution: (b)

50% of a% of b = b100

a

100

50 =

200

ab

Again 75% of b% of C = C100

b

100

75 =

400

3bC

Now, 200

ab =

400

3bC or, a =

2

3Cor 3C = 2a or C =

3

2a = 0.667a

4. A makes an article for TK.120 and sells it to B at a profit of 25% . B sells it to C who sells

it for TK.195 making a profit of 10%. What profit percent did B make ? [Janata Bank

(EO)-2017 (afternoon)]

a.25% b.20% c.16.66% d.15%

Solution: (b)A's sp= 125% of 120=150

B's sp is not given

but C sell it 198 tk which make 10% profit

so, C's cost= 110% = 198, 1% = 110

100198 =180

finally B purchased it for 150 and sell it to C 180tk So, Bs profit percent =

%20150

10030=

5. A sum of TK.600 amounts to TK.720 in 4 years at simple interest. What will it amount to if

the rate of interest is increased by 2% ? [Janata Bank (EO)-2017 (afternoon)]

a.TK.648 b.TK.768 c.TK.726 d.TK.792

Solution: (b)

# :

720-600=120

120/4=30 per year interest

30*100/600=5% per year rate of interest

after increasing, it will shape (5+2)=7%

600*7%*4=168

total=600+168=768

( 2% )

gyL gyL mgvavb Kivi Rb Gfve fveyb:

gyL gyL mgvavb Kivi Rb Gfve fveyb:GKeQi 100 UvKvZ 2 UvKv AwZwi cj 600 UvKvZ AwZwi cve 62 = 12 UvKv, Ges 4 eQi AwZwicve 124 = 48 UvKv| myZivs bZzb my`vmj ne 720+48 = 768UvKv|

6. The sum of first five prime number is : [Janata Bank (EO)-2017 (afternoon)]

a.11 b.18 c.26 d.28

Solution: (d)c_g 5wU gwjK msLv njv, 2, 3, 5, 7Ges 11 myZivs G`i hvMdj = 2+3+5+7+11 = 28

7. What is the following is equal to 3.14610 ? [Janata Bank (EO)-2017 (afternoon)]

a.314 b.3140 c.3140000 d.None of these

Solution: (c)3.14106

= 1000000100

314 = 31410000 =3140000(Ans)

8. If x=1 - q and y = 2q+1 , then for what value of q. x is equal to y ? [Janata Bank (EO)-2017(afternoon)]

a.-1 b.0 c.0.5 d.2

Solution: (b)hnZz x = y evbvZ ne| Zvnj jLv hvq, 1 q = 2q+1 or, -3q = 0 So, q = 0 (ans)Avevi Ackb aiI cgvY Kiv hvq q = o emvj x Ges y Dfqi gvbB mgvb nq|

9. If y =5 , then what is thr value of 10y 23 yy ? [Janata Bank (EO)-2017 (afternoon)]

a.50 2 b.100 c.200 5 d.500

Solution: (d)

hnZz y = 5 myZivs 10y 23 yy = 10.5 23 55 = 50 52125 = 50 001

=5010=500

10. 3 years ago , the average age of a family of 5 members was 17 years . A baby having been

born , the average age of the family is the same today. The present age of the baby is :[Janata Bank (EO)-2017 (afternoon)]

a.1year b.1year 6months c.2years d.3years

Solution: (c)3 eQi AvM 5Rbi eqmi Mo 17 eQi nj eZgvb Mo 17+3 = 20 Ges eZgvb gvU eqm = 205 = 100Avevi bZzb GKRb hvM `qvq 6 Rbi eZgvb Mo 17 Ges gvU eqm = 176 = 102 myZivs wkwUi eqm = 102-100 = 2 eQi|

11. There are two numbers such that the sum of twice the first and thrice the second is 39, while

the sum of thrice the first and twice the second is 36. The largest of the two is : [Janata Bank(EO)-2017 (afternoon)]

a.6 b.8 c.9 d.12

Solution: (c)Let, the first number is x and second number is y

For first condition, 2x+3y = 39 and for 2nd

condition 3x+2y = 36

By solving the equation we get x = 6 and y = 9, So, largest number is 9

12. A person was asked to state his age in years .His reply was , take my age three years hence

, multiple is by 3 and then subtract three times my age three years ago and you will know

how old I am What was the age of person ? [Janata Bank (EO)-2017 (afternoon)]

a.18years b.20years c.24years d.32years

Solution: (a)eZgvb eqm K nj 3 eQi ci K+3 Ges 3w`q Y Kij ne 3(K+3) Avevi GB eqm _K weqvM KiZ newZbeQi AvMi eqm K -3 Gi 3Y = 3(K-3) Zvnj eZgvb eqm cvIqv hve| ck gZ, 3(K+3) -3(K-3) = K ev, 3K+9 -3K +9 = K myZivs K = 18 A_vr jvKwUi eqm 18 eQi|

13. If n2 = 64 , then the value of n is : [Janata Bank (EO)-2017 (afternoon)]

a.2 b.4 c.6 d.12

Solution: (d)n2 = 64 or, n2 = 2

6 or, 2

n = 2

12 So, n=12 A

14. In an election, 30% of the voters voted for candidate A whereas 60% of the remaining voted

for candidate B . The remaining voters did not vote. If the difference between those who

voted for candidate A and those who did not vote was 1200, how many individuals were

eligible for casting vote in the election ? [Janata Bank (EO)-2017 (afternoon)]

a.10,000 b.45,000 c.60,000 d.72,000

Solution: (c)Candidate A got = 30% So, Remaining = 100-30 =70%

Candidate B got = 60% of 70 = 42% SO, voters did not vote = 70-42 = 28%

Difference of A and did not vote is 30-28 = 2%

Now 2% = 1200 then 1% = 600 SO, 100% = 60,000

15. A shopkeeper expects a gain of 22.5% on his cost price . If in a week his sale was of

TK.392 , what was his profit ? [Janata Bank (EO)-2017 (afternoon)]

a.TK.18.20 b.TK.70 c.TK.72 d.TK.88.25

Solution: (c)CP = 100% and gain = 22.5%

So, 122.5% = 392 so, 1% = 5.122

392, Then, profit 22.5% = 72

5.122

5.22392=

16. The least whole number which when subtracted from both the terms of the ratio 6:7 gives a

ratio less then 16:21 is : [Janata Bank (EO)-2017 (afternoon)]

a.2 b.3 c.4 d.6

Solution: (b)Option test or, or,6-x:7-x = 16:21 x= 14/5 x =3

! 16:21 "

17. 10 men working 6 hours a day can complete a week in 18 days .how many hours a day must

15 men work to complete the same work in 12 days ? [Janata Bank (EO)-2017 (afternoon)]

a.6 b.10 c.12 d.15

Solution: (a)10Rb 18 w`b KiZ jvM 6 NUv| Zvnj 1 RbK ewk mgq Ges 1w`b Kij Aviv ewk mgq jvMe A_vr61018 GLb 15Rb gvbyl 12 w`b A_vr jvK Ges w`b Kgvi KviY hw` Y nq Zvnj evovi KviY fvM ne ZvB Di ( 6*10*18)/(15*12) = 6NUv|

18. Two taps A and B can fill a tank in 5 hours and 20 hours respectively . If both the taps are

open then due to leakage , it took 30 minutes more to fill the tank . If the tank is full , how

long will it take for the leakage alone to empty the tank ? [Janata Bank (EO)-2017(afternoon)]

a.4.5hrs b.7hrs c.18hrs d.36hrs

Solution: (d)A+B = 1/5+1/20 = 1/4 or 4 hours.

Due to leakage time taken 4.5 hours

So, Power of the leakage is = (4*4.5)/ 4.5-4 = 18/.5 = 36hrs

19. A train can travel 50% faster than a car. Both start from point A at the same time and reach

point B 75kms away from A at the same time . On the way , however , the train lost about

12.5 minutes while stopping at the station . The speed of the car is : [Janata Bank (EO)-2017(afternoon)]

a.100Kmph b.110Kmph c.120Kmph d.130Kmph

Solution: (c)Speed ratio of Train and Car = 3:2

So, Time ratio of train and car = 2:3

their time difference is 3-2 = 1 part = 12.5 min so Car taken 3*12.5 = 37.5min

So, Speed of the car in 1 min is 75/37.5 = 2km and in 60min or 1 hour is 2*/60 = 120km

20. A towel , when balanced was found to have

The percentage of decrease in area is :

a.10%

Solution: (d)c_g 20% Kg 80 nq| Gici 80 Gi 10% A_vr 8 Kg| Zvnj gvU Kgjv 20+8 = 2

A towel , when balanced was found to have lost 20% of its length and 10% of its breadth .

e in area is : [Janata Bank (EO)-2017 (afternoon)]

b.10.08% c.20%

c_g 20% Kg 80 nq| Gici 80 Gi 10% A_vr 8 Kg| Zvnj gvU Kgjv 20+8 = 28%|

lost 20% of its length and 10% of its breadth .

d.28%

8%|

[Janata Bank (EO)-2017 (Morning)]

1. Find the greatest number that will divide 43, 91 , and 183 so as to leave the same remainder

in each case. [Janata Bank (EO)-2017 (Morning)] a.7 b.9 c.3 d.4

Solution: (d) GLvb 43, 91 Ges 183 K Ggb GKwU msLv w`q fvM KiZ ne hvZ cwZevi GKB fvMkl _vK| Ackb _K cwZwU msLv _K 4 w`q fvM KiZ Mj 43, 91 Ges 183 K fvM Kivi mgq cwZevi 3 Aewk _vK| ZvB Di: 4|

2. In a business , A and C invested amount in the ratio 2:1 , whereas the ratio between

amounts invested by A and B was 3:2 . If TK.1,57,300 was their profit , how much amount

did B receive ? [Janata Bank (EO)-2017 (Morning)] a.TK.24,200 b.TK.36,300 c.TK.72,600 d.TK.48,400

Solution: (b) Invest of A and C = 2:1 or 6:3

invest of A and B =3:2 of 6:4

So, Invest of A:B:C = 6:3:4

Now, total profit = 157300

So B, received = 15730013

3= 36300

3. Which one of the following is not prime number ? [Janata Bank (EO)-2017 (Morning)]

a.31 b.61 c.91 d.71

Solution: (b) Here all the numbers are prime except 91, Because 91 = 137

4. (0.04)-1.5

= ? [Janata Bank (EO)-2017 (Morning)] a.25 b.250 c.125 d.625

Solution: (b)

(0.04)-1.5

= (.2)2(-1.5)

= (.2)-3

= 1258

1000

2

10

10

233

==

=

5. A sum of money is borrowed and paid back in two annual installments of TK.882 each

allowing 5% compound interest . The sum borrowed was : [Janata Bank (EO)-2017 (Morning)] a.Tk.1620 b.TK.1680 c.TK.1640 d.TK.1700

Solution: (c)

evrmwiK 882 UvKv Ki 2 eQi wKw w`j gvU my`vmj 882+882 = 1764 UvKv| GLvb Pew my`i nvi 5% Ges mgq y eQi|

wK yeQi GKmv_ wnme Kiv hve bv| KviY c_g eQii c wKwZ 1 eQii my`v hy nqQ wK wZxq eQii wKw Z `y eQii my` hy nqQ|

ZvB c_g wKwvi Avmj awi, x UvKv|

ckgZ, x Gi 105% = 882 ev x = 882105

100= 840 UvKv|

Avevi, wZxq eQii c wKw Z Avmj x aij,

ck gZ, x Gi 105% Gi 105% = 882 ev, x = 882105

100

105

100 = 882

21

20

21

20=800

myZivs megvU gyjab: = 840+800 = 1640UvKv|

6. What is the unit digit in the product (684759413676) ? [Janata Bank (EO)-2017(Morning)]

a.4 b.12 c.8 d.16

Solution: (c)ay kli wWwRU jv Y Ki cvB 49 = 36 Gici 36 Gi 63 = 18 Gici 18 Gi 8 Gi mv_ 86 = 48Zvnj mejv msLvi YdjwU hZ eoB nvK bv Kb kl 8 _vKe| Di: 8|

7. A certain number of men can finish a piece of work in 100 days . If , there were 10 men less

, it would take 10 days more for the work to be finished. How many men were there

originally ? [Janata Bank (EO)-2017 (Morning)]

a.75 b.82 c.110 d.100

Solution: (c)Originally let there be x men.

Then x man need =100days 1 = 100x days x-10 =10x

x100

days

ATQ , 10x

x100

=110 or 100x = 110x-1100 or 10x = 1100 x=110

8. One year ago , Pinky was four times as old as her daughter Soma. Six years hence , pinkys

age will exceed her daughters age by 9 years. The ratio of the present age of Pinky and her

daughter is : [Janata Bank (EO)-2017 (Morning)]

a.9:2 b.11:3 c.13:4 d.12:5

Solution: (c)

Let, one year ago, Soma was x years and Pinky was 4x years old

Their present age is x+1 and 4x+1 and ages after 6 years will be = x+7 and 4x+7

ATQ, x+7=4x+7-9 or, -3x = -9 So, x = 3

So, age of soma was 3 and Pinky was 43 = 12

Ratio of their present age is 12+1:3+1 = 13:4

9. The ratio between the perimeter and the breadth of rectangle is 5:1 . If the area of rectangle

is 216sq. cm , what is the length of the rectangle ? (AvqZi cwimxgv I ci AbycvZ 5 : 1| AvqZi dj 216 eM m.wg. nj `N KZ?) [Janata Bank (EO)-2017 (Morning)] a.16cm b.24cm c.20cm d.18cm

Solution: (d) Let the perimeter is = 5x and the breadth is = x

So, the length is x2

x5 =

2

x2x5 =

2

x3

Now the area is 2

x3 x =

2

x3 2

ATQ

2

x3 2= 216 3x2= 432 x2 = 144 x=12 So length is

2

123=18cm

10. (8787+6161-28761) = ? [Janata Bank (EO)-2017 (Morning)]

a.198 b.196 c.296 d.298

Solution: (none) Let 87 = a and 61 = b

So, aa+bb -2ab Or, a

2+b

2-2ab

Or (a-b)2 now putting the Value of a and b

(87-61)2 = 26

2 = 676

11. A is faster then B. A and B each walk 24km. The sum of their speeds is 7 Km/hr and the

sum of times taken by them is 14 hours. Then, A;s speed is equal to : [Janata Bank (EO)-2017 (Morning)] a.3 Km/hr b.5 Km/hr c.4 Km/hr d.7 Km/hr

Solution:(c) Let the speed of A = xkm/hr So, Speed of B = 7-x

ATQ, x7

24

x

24

+ =14

By, Solving the equation we get x = 4 or 3

Since A is Faster So As Speed x = 4km/hr

gyL gyL mgvavb Kivi Rb Gfve fveyb: GLvb MwZeMi A>B Avevi Zv`i MwZeMi hvMdj hnZz 7 Zvnj 4+3 A_ev 5+2 A_ev 6+1 nZ cvi| GLb yRb hnZz 24 wKwg nuUQ Zvnj jwRKvwj Ggb msLv wbZ ne hv w`q 24 K fvM Kiv hvq| Ges mgq `ywUi hvMdj 14 NUv nq| GLb A Gi MwZeM 4 Ges B Gi MwZeM 3 aij A K mgq jvMe 244 = 6 NUv Ges B K mgq jvMe 243 = 8 NUv| Zvnj yRbK gvU mgq jvMjv 8+6 = 14 NUv| cki mv_ wgj hvIqvq Di A Gi MwZeM 4wKwg/NUv|

Similar question: 1. Jake is faster than Paul. Jake and Paul each walk 40 km. The sum of their speeds is 13

km/h and the sum of time taken by them is 13 hours. Then Jakes speed is equal to :

a.7Kmph b. 8Kmph c.13Kmph d. 9Kmph

12. How many times in a day , the hands of a clock are straight ? [Janata Bank (EO)-2017

(Morning)] a.22 b.24 c.48 d.44

Solution:(d) In 12 hours, the hands coincide or are in opposite

direction 22 times.

In 24 hours, the hands coincide or are in

opposite direction 44 times a day.

13. The sum of two numbers is 40 and their difference is 4. The ratio of numbers is : [Janata Bank (EO)-2017 (Morning)] a.22:9 b.11:9 c.11:18 d.21:19

Solution:(b) Let first number is m and second number is n.

Then m + n = 40 --------[1]

And m n = 4 ----------[2]

Adding eq. 1 and eq. 2

We get, 2m = 44 m = 22 Putting value of m in eq. (1), we get n = 18

m : n = 22 : 18 m : n = 11 : 9

#, - . #( - ,

! $% & %' & %' 2 ( $%! & %' 2 " $%! &

* $ $: ( $% (40+4)/2 = 22 " $% (40-4)/2 = 18 : 22 : 18 11 : 9

14. Two trains are running in opposite directions with the same speed. If the length of each train

is 120 meters and they cross each other in 12 second , then the speed of each train (in

Kh/hr) is : [Janata Bank (EO)-2017 (Morning)] a.10 b.18 c.72 d.36

Solution:(d) Let,the speed of each train be x kmph.

So,relative speed=x+x=2x

Length =RS (5/18) Sec => (120+120)=2s*(5/18)*12

=>240=2S(5/18)*12 =>2S=72 =>S=72/2 =36(Ans)

mnR fve Kivi Rb Gfve fveyb: Ub `ywUi `Ni hvMdj 120+120 = 240wgUvi hvq 12 mK| Zvnj cwZ mKi MwZeM 24012 = 20wg/m. GLb 1 mK 20wg, Mj 3600 mK hvq 203600 = 72000wgUvi ev 72wKwg| GLb ywU Ub wecixZ w`K _K Avmvq Ges Zv`i MwZeM mgvb nIqvq Ub ywUi cZKwUi MwZeM ne 722 = 36wKwg/ NUv|

15. The average of first 50 natural numbers is : [Janata Bank (EO)-2017 (Morning)] a.12.25 b.21.25 c.25.5 d.25

Solution:(c) Natural number i nq 1 w`q | ZvB 1 _K 50 ch Natural number gvU 50wU| GLb Mo ei Kivi wbqg njv c_g c` I klc` hvM Ki 2w`q fvM KiZ ne| ZvB Mo 50+1 = 512 = 25.5|

16. In an election a candidate who gets 84% of the votes is elected by a majority of 476 votes.

What is the total number of votes polled ? (GKwU wbevPb GKRb cv_x 84% fvU cq 476 wU AwZwi fvU wbevwPZ nj| gvU fvUi cwigvY KZ?) [Janata Bank (EO)-2017 (Morning)] (BB AD) a.672 b.749 c.700 d.848

Solution:(b)Total vote = 100%

Winnig candidate got = 84% So, other candidate got = 100-84 = 16%

Difference in % is = 84% - 16% = 68%

Difference in votes is = 476

So, 68% = 476 1% =68

476 So, 100% =

68

100476 = 700

17. The square root of )537( + ( 7- 53 ) is : [Janata Bank (EO)-2017 (Morning)]

a. 5 b.4 c.2 d. 53

Solution: (c)

)537( + ( 7- 53 ) = 72 - ( )253 =49-45 = 4 So, Square root is 24 = Ans: 18. A sum of money lent out at simple interest amount to TK.720 after 2 years and to TK.1020

after a further period of 5 years . The sum is : [Janata Bank (EO)-2017 (Morning)]

a.TK.600 b.TK.500 c.TK.700 d.TK.710

Solution: (c)Principal + SI for 2 years =720 Tk. ......(I)

Principal + SI for 7 years = 1020 Tk. ......(II)

Subtracting equation (I) from (II),

S.I. for 5 years = (1020 720) = 300 Tk

S.I. for 1 year is 3005 = 60TK and for 2 years = 602 = 120TK.\Principal = (720 - 120) = 600 Tk

19. In a certain store , the profit is 320% of the cost . If the cost increased by 25% but, the

selling price remains constant , approximately what percentage of the selling price is the

profit ? [Janata Bank (EO)-2017 (Morning)]

a.30% b.100% c.250% d.70%

Solution: (d)Let C.P.= Tk. 100. Then, Profit = Tk. 320, S.P. = Tk. 420.

New C.P. = 125% of Tk. 100 = Tk. 125

New S.P. = Tk.. 420. So, Profit = Tk. (420 -125) = Tk. 295.

Required percentage = =

420

100295 70% (approximately)

20. 138.009+341.981-146.305=123.6+? [Janata Bank (EO)-2017 (Morning)]

a.120.85 b.120.085 c.220.085 d.None of these

Solution: (d)Let 138.009 + 341.981 -146.305 = 123.6 + z

Then, z = (138.09+341.981) -(146.305+123.6)= 479.99 -269.905 = 210.085

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