mfb partial differentation

Upload: mziabd

Post on 04-Apr-2018

222 views

Category:

Documents


0 download

TRANSCRIPT

  • 7/30/2019 MFB Partial Differentation

    1/15

    Partial Differentiation

  • 7/30/2019 MFB Partial Differentation

    2/15

    The ordinary derivative of a function ofone variable can be carried out

    because everything else in the function is a constant and does not

    affect the process of differentiation.

    When there is more than one variable in a function it is often useful

    to examine the variation of the function with respect to one of the

    variables with all the other variables constrained to stay constant.

    This is the purpose of a partial derivative.

    For example, given the polynomial in variables x and y,

    the partial derivative with respect to x is written

    and the partial derivative with respect to y is written

    The Partial Derivative

    http://hyperphysics.phy-astr.gsu.edu/Hbase/deriv.htmlhttp://hyperphysics.phy-astr.gsu.edu/Hbase/deriv.html
  • 7/30/2019 MFB Partial Differentation

    3/15

    The ordinary derivative of a function of several variables with

    respect to one of the independent variables, keeping all other

    independent variables constant, is called the partial derivativeof the function.

    Partial derivatives off(x,y) with respect to x and y are denoted by

    x

    f

    y

    f

    By definitionx

    yxfyxxf

    x

    f

    x

    ),(),(lim

    0

    y

    yxfyyxf

    y

    f

    y

    ),(),(lim

    0

    When these limits exist

  • 7/30/2019 MFB Partial Differentation

    4/15

    Example:

    2332),( xyxyxf

    2236 yx

    x

    f

    If

    xyy

    f6

  • 7/30/2019 MFB Partial Differentation

    5/15

    Higher order partial derivatives

    Iff(x,y) has partial derivatives at each point (x.y) in a region, then and

    are themselves fuctions of x and y, which may also have partial derivatives. These

    second derivatives are denoted by

    xf / yf /

    2

    2

    x

    f

    x

    f

    x

    2

    2

    y

    f

    y

    f

    y

    2

    2

    z

    f

    z

    f

    z

  • 7/30/2019 MFB Partial Differentation

    6/15

    23

    ),(xy

    eyxyx findIf

    (a) (b) (c) (d)

    (e) (f)

    x

    y

    xx

    yy

    xy

    2

    yx

    2

    Example:

    Solution:

    (a) x

    2

    3 xy

    eyxx

    22

    .3

    2

    yeyxxy

    222

    3xy

    eyyx

    y

    23 xyeyxy

    xyex xy 2.

    23

    2

    .23 xy

    exyx (b)

  • 7/30/2019 MFB Partial Differentation

    7/15

  • 7/30/2019 MFB Partial Differentation

    8/15

    02

    2

    2

    2

    2

    2

    z

    U

    y

    U

    x

    U 2/1222,, zyxzyxUsuppose , show that

    0,0,0,, zyxWe asume here that Then,

    x

    U

    xzyx 2.2

    1 2/3222 2/3222 zyxx

    2

    2

    x

    U

    2/3222

    zyxx

    x

    1.2.2

    3 2/32222/5222

    zyxxzyxx

    2/5222222

    2/5222

    23

    zyx

    zyx

    zyx

    x

    2/5222222

    2

    zyx

    zyx

  • 7/30/2019 MFB Partial Differentation

    9/15

    2

    2

    y

    U

    2/5222222

    2

    zyx

    zxy

    2

    2

    z

    U

    2/5222222

    2

    zyx

    yxz

    2

    2

    2

    2

    2

    2

    z

    U

    y

    U

    x

    U

    Adding

    2/5222222

    2

    zyx

    zyx

    2/5222222

    2

    zyx

    zxy

    2/5222222

    2

    zyx

    yxz

    2/5222

    222222222222

    zyx

    yxzzxyzyx

    2/5222222222

    222222

    zyx

    zzyyxx

    0

  • 7/30/2019 MFB Partial Differentation

    10/15

  • 7/30/2019 MFB Partial Differentation

    11/15

  • 7/30/2019 MFB Partial Differentation

    12/15

  • 7/30/2019 MFB Partial Differentation

    13/15

  • 7/30/2019 MFB Partial Differentation

    14/15

  • 7/30/2019 MFB Partial Differentation

    15/15