partial dislocations

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Partial Dislocations Lauren Ayers 22.71

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Partial Dislocations. Lauren Ayers 22.71 . Outline. Partial Dislocations Why Partials? Stacking Faults Lomer-Cottrel Lock Force on a Dislocation Line Tension Model Dislocation Density. Partial Dislocations. Single unit dislocation can break down into two Shockley partials. b1. - PowerPoint PPT Presentation

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Page 1: Partial Dislocations

Partial Dislocations

Lauren Ayers

22.71

Page 2: Partial Dislocations

Outline• Partial Dislocations

– Why Partials?

– Stacking Faults

• Lomer-Cottrel Lock

• Force on a Dislocation

• Line Tension Model

• Dislocation Density

Page 3: Partial Dislocations

Partial Dislocations

b1

Single unit dislocation can break down into two Shockley partials

Page 4: Partial Dislocations

Partial Dislocations

b2

Single unit dislocation can break down into two Shockley partials b3

Page 5: Partial Dislocations

Why Partials?• Frank’s Rule:

|b1|2>|b2|2+|b3|2

• Energy of a dislocation is proportional to |b|2

• Partial dislocations decrease strain energy of the lattice

Page 6: Partial Dislocations

Stacking Faults

• Movement of partial dislocations generate discontinuity in stacking planes, ex: ABCAXCABC

• Two separated partials have smaller energy than a full dislocation

• Reduction in elastic energy proportional to:

• Equilibrium splitting distance

Page 7: Partial Dislocations

What does this mean?• Wide vs. narrow ribbon affects cross slip

– Cu, s = 2nm: high constriction energy barrier

– Al, s= 4 A: cross slip occurs more easily

Page 8: Partial Dislocations

Lomer-Cottrel Lock (LC)

• 2 Dislocations on primary slip planes combine

• Formed by:

• Slip by bLC creates a high energy stacking fault

• No {111} plane which the LC can move as an edge dislocation

• “Lock”: Once the state is formed, hard to leave

• Acts as a barrier against other dislocations

Page 9: Partial Dislocations

Force on a Dislocation

• Climb: “Non-conservative”

• Glide: “Conservative”

Page 10: Partial Dislocations

Line Tension Model

• Assume:

– Line tension η (total elastic energy per length) independent of line direction ξ

– Dislocations do not interact with each other elastically

• Local model

• From dF, derive critical external stress:

Page 11: Partial Dislocations

Dislocation Density• Total length of all dislocations in a unit volume of

material

• 1/m2 or m/m3

Page 12: Partial Dislocations

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