topic 19 red black treesblack trees - university of texas ...scottm/cs307/handouts/..."welcome...
TRANSCRIPT
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Topic 19Red Black TreesRed Black Trees
"People in every direction p yNo words exchanged No time to exchange And all the little ants are marching gRed and black antennas waving"
-Ants Marching, Dave Matthew's Band
"Welcome to L.A.'s Automated Traffic Surveillance and Control Operations Center. See, they use video feeds from intersections and specifically designed algorithms to predict traffic conditions, and thereby control traffic g g p , ylights. So all I did was come up with my own... kick ass algorithm to sneak in, and now we own the place."
-Lyle, the Napster, (Seth Green), The Italian Job
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y , p , ( ),
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Attendance Question 1882000 elements are inserted one at a time
into an initially empty binary search tree using the traditional algorithm. What is the maximum possible height of the resulting
?tree?A. 1B. 11C 1000C. 1000D. 1999E 4000E. 4000
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Binary Search Trees88Average case and worst case Big O for
– insertion– deletion– access
8Balance is important. Unbalanced trees give worse than log N times for the basic tree goperations8Can balance be guaranteed?Can balance be guaranteed?
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Red Black Trees88A BST with more complex algorithms to
ensure balance8Each node is labeled as Red or Black.8Path: A unique series of links (edges) at u que se es o s (edges)
traverses from the root to each node. – The number of edges (links) that must beThe number of edges (links) that must be
followed is the path length8In Red Black trees paths from the root toIn Red Black trees paths from the root to
elements with 0 or 1 child are of particular interest
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interest
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Paths to Single or Zero Child NodesNodes
8How many? 19
12 35
16 213 16 5621
11
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Red Black Tree Rules1. Every node is colored either Red
or black2. The root is black3 If d i d it hild t3. If a node is red its children must
be black. (a.k.a. the red rule)4. Every path from a node to a null
link must contain the samelink must contain the same number of black nodes (a.k.a. the path rule)
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the path rule)
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Example of a Red Black Tree
8The root of a Red Black tree is black8Every other node in the tree follows these rules:
– Rule 3: If a node is Red, all of its children are Black– Rule 4: The number of Black nodes must be the same in all pathsRule 4: The number of Black nodes must be the same in all paths
from the root node to null nodes
1919
12 35
3 16 5621
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Red Black Tree?19
12 3512
0 50
-10
5
75
135-5
-8
135
100
-6 80
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Attendance Question 288Is the tree on the previous slide a binary
search tree? Is it a red black tree?BST? Red-Black?
A. No NoB. No YesC Yes NoC. Yes NoD. Yes Yes
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Red Black Tree?
19
12 35
3 163 16
0
Perfect?F ll?Full?Complete?
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Attendance Question 388Is the tree on the previous slide a binary
search tree? Is it a red black tree?BST? Red-Black?
A. No NoB. No YesC Yes NoC. Yes NoD. Yes Yes
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Implications of the Rules88If a Red node has any children, it must have
two children and they must be Black. (Why?)8If a Black node has only one child that child
must be a Red leaf. (Why?)8Due to the rules there are limits on how
unbalanced a Red Black tree may become.u ba a ced a ed ac ee ay beco e– on the previous example may we hang a new
node off of the leaf node that contains 0?
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Properties of Red Black Trees88If a Red Black Tree is complete, with all
Black nodes except for Red leaves at the lowest level the height will be minimal, ~log N8To get the max height for N elements there
should be as many Red nodes as possible down one path and all other nodes are Black– This means the max height would be < 2 * log N– see example on next slidep
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Max Height Red Black Tree14
12 3512 35
562113 56
43 99
211 13
15 2515 25
80 100
70CS 307 Fundamentals of Computer Science Red Black Trees
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Maintaining the Red Black Properties in a TreeProperties in a Tree
8Insertions8Must maintain rules of Red Black Tree.8New Node always a leafNew Node always a leaf
– can't be black or we will violate rule 4– therefore the new leaf must be red– therefore the new leaf must be red– If parent is black, done (trivial case)
if parent red things get interesting because a red– if parent red, things get interesting because a redleaf with a red parent violates rule 3
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Insertions with Red Parent - ChildMust modify tree when insertion would result in Red Parent - Child pair using color changes and
30
Red Parent Child pair using color changes androtations.
15 70
856010 20
80 9050 655
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Case 188Suppose sibling of parent is Black.
– by convention null nodes are black8In the previous tree, true if we are inserting a
3 or an 8. – What about inserting a 99? Same case?
8Let X be the new leaf Node P be its RedLet X be the new leaf Node, P be its RedParent, S the Black sibling and G, P's and S's parent and X's grandparentS s parent and X s grandparent– What color is G?
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Case 1 - The Picture
G
P S
EDX C
A B
Relative to G X could be an inside or outside nodeRelative to G, X could be an inside or outside node.Outside -> left left or right right movesInside -> left right or right left moves
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g g
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Fixing the Problem
G
P S
EDX C
A B If X is an outside node a single rotation between P and G fixes the problem.pA rotation is an exchange of roles between a parentand child node. So P becomes G's parent. Also must
l P d GCS 307 Fundamentals of Computer Science Red Black Trees
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Single Rotation
P
X G
SCA B
EDApparent rule violation?pp
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Case 288What if X is an inside node relative to G?
– a single rotation will not work8Must perform a double rotation
– rotate X and P– rotate X and G G
P SP S
EDXA EXA
B C
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After Double RotationX
P G
CA B SCA B
EDApparent rule violation?
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Case 3 Sibli i R d t Bl kSibling is Red, not Black
G
P SP S
EDX CX
B
C
A BA
Any problems?
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Fixing Tree when S is Red88Must perform single rotation between parent,
P and grandparent, G, and then make appropriate color changes
P
X G
CBA S
ED
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More on Insert8P bl Wh t if th i l8Problem: What if on the previous example
G's parent had been red?8E i t l t C 3 !8Easier to never let Case 3 ever occur!8On the way down the tree, if we see a node X that
has 2 Red children we make X Red and its twohas 2 Red children, we make X Red and its two children black.– if recolor the root, recolor it to black– the number of black nodes on paths below X remains
unchangedIf X's parent was Red then we have introduced 2– If X s parent was Red then we have introduced 2 consecutive Red nodes.(violation of rule)
– to fix, apply rotations to the tree, same as inserting node
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Example of Inserting Sorted Numbers881 2 3 4 5 6 7 8 9 10
Insert 1. A leaf so
1red. Realize it isroot so recolorto black.
1
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Insert 2
1make 2 red. Parentis black so done
2
is black so done.
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Insert 3
1Insert 3. Parent is red.
2
Insert 3. Parent is red. Parent's sibling is black(null) 3 is outside relative
3to grandparent. Rotateparent and grandparent
2
1 3
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Insert 4
2
On way down see2 with 2 red children. 2
1 3
Recolor 2 red andchildren black.Realize 2 is root 1Realize 2 is rootso color back to black
22
1 3When adding 4parent is black 1 3
4
parent is blackso done.
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4
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Insert 5
25's parent is red.Parent's sibling is
1 3Parent s sibling isblack (null). 5 isoutside relative to
4outside relative tograndparent (3) so rotateparent and grandparent then
5recolor
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Finish insert of 5
2
1 4
3 5
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Insert 6
2On way down see4 with 2 red
1 4children. Make4 red and childrenblack 4's parent is
3 5black. 4's parent isblack so no problem.
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Finishing insert of 6
26's parent is black
1 4so done.
3 5
6
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Insert 7
27's parent is red.
1 4Parent's sibling isblack (null). 7 isoutside relative to
3 5outside relative tograndparent (5) so rotate parent and
6rotate parent and grandparent then recolor
7
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Finish insert of 7
2
1 4
3 6
5 7
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Insert 8
2On way down see 6with 2 red children.
1 4Make 6 red andchildren black. This
t bl3 6
creates a problembecause 6's parent, 4, isalso red Must perform
5 7also red. Must performrotation.
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Still Inserting 8
2Recolored now
1 4
Recolored nowneed torotate
3 6
5 7
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Finish inserting 8
4Recolored now
2 6
Recolored nowneed torotate
3 5 71
8
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Insert 9
4
2 6
3 5 71
8On way down see 4 has two red childrenso recolor 4 red and children black.
9Realize 4 is the root so recolor black
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Finish Inserting 9
4
2 6
3 5 81
7 9After rotations and recoloringg
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Insert 10
4
2 6
3 5 81
7 9On way down see 8 has twored children so change 8 tored children so change 8 tored and children black 10
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Insert 11
4
2 6
3 5 81
7 9Again a rotation is
10
11
gneeded.
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11
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Finish inserting 11
4
2 6
3 5 81
7 10
9 11
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