version 001 – one dimensional motion – ramadoss – (1234) 1 · 2019. 7. 12. · motion 007...

Version 001 – One dimensional Motion – ramadoss – (1234) 1

This print-out should have 113 questions.Multiple-choice questions may continue onthe next column or page – find all choicesbefore answering.You will complete at least 80 percent of this

assignment depending on your learning needs.If you are confident of some these questions,you are allowed to skip. If you are not able tosolve any of these, it is your responsibility tosend me an email, see me or ask a friend.

Displacement and Distance001 (part 1 of 2) 10.0 points

A physics book is moved once around theperimeter of a table of dimensions 1 m by 3m.If the book ends up at its initial position,

what is the magnitude of its displacement?

1. 6 m

2. 4 m

3. 1 m

4. 7 m

5. 2 m

6. None of these

7. 0 m correct

8. 8 m

9. 5 m

10. 3 m

002 (part 2 of 2) 10.0 pointsWhat is the distance traveled?

1. 0 m

2. 2 m

3. 7 m

4. 4 m

5. 3 m

6. 6 m

7. 5 m

8. 1 m

9. 8 m correct

10. None of these

Mile Markers003 (part 1 of 2) 10.0 points

While John is traveling along an interstatehighway, he notices a 159 mi marker as hepasses through town. Later John passes a116 mi marker.What is the distance between town and

John’s current location?1. 42.02. 55.03. 40.04. 56.05. 37.06. 47.07. 52.08. 43.09. 38.010. 67.0

Correct answer: 43 mi.

004 (part 2 of 2) 10.0 pointsWhat is John’s current position?1. 100.02. 109.03. 113.04. 102.05. 120.06. 116.07. 118.08. 107.09. 111.010. 104.0

Correct answer: 116 mi.


More Mile Markers005 (part 1 of 2) 10.0 points

While John is traveling along a straight inter-state highway, he notices that the mile markerreads 242 km. John travels until he reachesthe 130 km marker and then retraces his pathto the 179 km marker.What is John’s resultant displacement from

the 242 km marker?1. -73.02. -85.03. -86.04. -88.05. -84.06. -71.07. -92.08. -54.09. -63.010. -74.0

Correct answer: −63 km.

006 (part 2 of 2) 10.0 pointsHow far has he traveled?1. 127.02. 120.03. 164.04. 111.05. 124.06. 161.07. 139.08. 108.09. 117.010. 137.0

Correct answer: 161 km.

Motion007 10.0 points

Which of the following are important in mea-suring motion?

1. distance, time, speed correct

2. velocity, acceleration, density

3. distance, volume, speed

4. acceleration, momentum, speed

Ant Race008 10.0 points

Two ants race across a table 57 cm long. Onetravels at 4.59 cm/s and the other at 3 cm/s.When the first one crosses the finish line,

how far behind is the second one?1. 35.78442. 27.92593. 9.598874. 19.74515. 25.47736. 31.6857. 32.47718. 39.05769. 38.25110. 21.7291

Correct answer: 19.7451 cm.

AP M 1998 MC 3009 10.0 points

The graph shows the velocity v as a functionof time t for an object moving in a straightline.

t

v

0 tQ t

RtS

tP

Which graph shows the corresponding dis-placement x as a function of time t for thesame time interval?

1. tx

0 tQ t

RtS

tP

2.

t

x

0 tQ t

RtS

tP

correct


3.

t

x

0 tQ t

RtS

tP

4. None of these graphs is correct.

5. tx

0 tQ t

RtS

tP

6.t

x

0 tQ t

RtS

tP

7.t

x

0 tQ t

RtS

tP

8.

t

x

0 tQ t

RtS

tP

9.tx

0 tQ t

RtS

tP

Bird and Runner010 (part 1 of 2) 10.0 points

A runner is jogging at a steady 3.6 km/hr.When the runner is 8.3 km from the finishline, a bird begins flying from the runner tothe finish line at 18 km/hr (5 times as fastas the runner). When the bird reaches thefinish line, it turns around and flies back tothe runner.

L

vb

vr

finishline

How far does the bird travel? Even thoughthe bird is a dodo, assume that it occupies

only one point in space (a “zero” length bird)and that it can turn without loss of speed.1. 4.642. 11.33333. 13.83334. 6.755. 4.333336. 7.27. 10.88. 3.159. 8.410. 6.33333

Correct answer: 13.8333 km.

011 (part 2 of 2) 10.0 pointsAfter this first encounter, the bird then turnsaround and flies from the runner back to thefinish line, turns around again and flies backto the runner. The bird repeats the back andforth trips until the runner reaches the finishline.How far does the bird travel from the be-

ginning (including the distance traveled to thefirst encounter)?1. 12.32. 14.03. 17.44. 16.85. 10.06. 33.07. 15.98. 41.59. 9.010. 12.0


Bug Laps012 (part 1 of 2) 10.0 points

A bug completes one lap along the edge of acircular planter of radius 13.7 cm in 17.79 s.How fast was it traveling?1. 7.279612. 6.065023. 16.24694. 4.838655. 9.709416. 11.6377


7. 4.337078. 9.535429. 5.5236810. 15.9896

Correct answer: 4.83865 cm/s.

013 (part 2 of 2) 10.0 pointsHow fast in m/s?1. 0.1160662. 0.1204283. 0.1319674. 0.06122835. 0.04754846. 0.1396437. 0.04838658. 0.1125769. 0.072634610. 0.0745949

Correct answer: 0.0483865 m/s.

Bug Laps 02014 (part 1 of 2) 10.0 points

A bug walking on the circular rim of a flowerpot completes one lap around the planter in8.824 s.If the radius of the planter is 10.6 cm, how

fast was it traveling?1. 5.246572. 7.54783. 5.564644. 4.642945. 7.470336. 9.476117. 4.741168. 10.93819. 5.9069210. 6.82229

Correct answer: 7.5478 cm/s.

015 (part 2 of 2) 10.0 pointsHow fast in m/s?1. 0.0754782. 0.07700993. 0.04299664. 0.1020095. 0.0623791

6. 0.0676577. 0.04116978. 0.08208289. 0.055408210. 0.0465816


Cars Leaving School016 (part 1 of 4) 10.0 points

Both car A and car B leave school at the sametime, traveling in the same direction. Car Atravels at a constant speed of 78 km/h, whilecar B travels at a constant speed of 89 km/h.How far is Car A from school 3 h later?1. 260.72. 197.53. 244.84. 134.35. 250.86. 138.77. 248.08. 165.09. 234.010. 170.4


017 (part 2 of 4) 10.0 pointsHow far is car B from school 3 h later?1. 160.22. 156.63. 186.04. 176.05. 154.86. 225.67. 269.78. 249.29. 300.310. 267.0


018 (part 3 of 4) 10.0 pointsHow long does it take car A to reach a gasstation a distance 211 km from the school?1. 2.169012. 3.088613. 3.18667


4. 2.6255. 2.316466. 2.987017. 3.58. 2.457149. 2.7051310. 2.34177

Correct answer: 2.70513 h.

019 (part 4 of 4) 10.0 pointsHow long does it take car B to reach the gasstation?1. 1.677422. 1.730343. 1.806454. 1.968095. 2.559146. 1.941867. 2.613648. 2.370799. 2.0543510. 2.82759

Correct answer: 2.37079 h.

Constant Velocity 01020 10.0 points

At 1:00 p.m. a car, traveling at a constantvelocity of 78 km/h toward the west, is 16 kmto the west of our school.How far from the school will it be at 3:30

p.m.?1. 230.02. 243.03. 222.04. 211.05. 260.06. 240.57. 278.58. 214.09. 256.510. 234.0


Displacement Curve 02021 (part 1 of 2) 10.0 points

Consider a moving object whose position x

is plotted as a function of the time t. Theobject moved in different ways during thetime intervals denoted I, II and III on thefigure.

2 4 6

2

4

6

t

x

I II III

During these three intervals, when was theobject’s speed highest? Do not confuse thespeed with the velocity.

1. During interval II

2. During interval III correct

3. During interval I

4. Same speed during intervals II and III

5. Same speed during each of the three in-tervals.

022 (part 2 of 2) 10.0 pointsDuring which interval(s) did the object’s ve-locity remain constant?

1. During interval I only

2. During interval III only

3. During each of the three intervals cor-rect

4. During interval II only

5. During none of the three intervals

Displacement vs Time 04023 (part 1 of 2) 10.0 points

Consider the following graph


0 2 4 6 8 10 12 14 16 18 20−10

−8

−6

−4

−2

0

2

4

6

8

10

displacement(m

)

time (s)

Displacement vs Time

What is the displacement at 10 s?

1. 2 m

2. Unable to determine

3. −3 m

4. None of these

5. 0 m

6. −1 m

7. −4 m correct

8. 1 m

9. 3 m

10. −2 m

024 (part 2 of 2) 10.0 pointsWhat is the velocity at 10 s?

1. −2 m/s

2. −1 m/s

3. 0 m/s correct

4. 3 m/s

5. 2 m/s

6. −3 m/s

7. None of these

8. 1 m/s


10. 4 m/s

Distance Time Graph 01 short025 (part 1 of 3) 10.0 points

Consider the following graph of motion.

0 1 2 3 4 50

10

20

30

40

50

Time (sec)

Dis

tanc

e (m

)How far did the object travel between 2 s

and 4 s?

1. 50 m

2. 20 m correct

3. 30 m

4. 10 m

5. 40 m

026 (part 2 of 3) 10.0 pointsThe graph indicates

1. constant position.

2. constant velocity. correct

3. increasing velocity.

4. no motion.


5. decreasing velocity.

027 (part 3 of 3) 10.0 pointsWhat is the speed from 2 s to 4 s?

1. 0 m/s

2. 20 m/s

3. 5 m/s

4. 10 m/s correct

5. 15 m/s

Distance Time Graph 02028 (part 1 of 3) 10.0 points


0 1 2 3 40

10

20

30

Time (hr)

Dis

tanc

e (k

m)

What distance was covered in the first 3hours?

1. 30 km

2. 20 km

3. 5 km

4. 10 km

5. 15 km correct

6. 25 km

029 (part 2 of 3) 10.0 pointsThe graph indicates

1. constant velocity.

2. changing velocity. correct

3. constant position.

4. no motion.

5. no acceleration.

030 (part 3 of 3) 10.0 pointsConsider the following graph of motion.

0 1 2 3 4 5 6 7 8 90

50

100

150

200

250

300

350

400

Time (sec)

Dis

tanc

e (m

)

The distance is

1. increasing.

2. decreasing. correct

3. constant.

Earthquake Transverse Waves031 10.0 points

The velocity of the transverse waves producedby an earthquake is 4.64 km/s, while that ofthe longitudinal waves is 8.0736 km/s. A seis-mograph records the arrival of the transversewaves 76.8 s after that of the longitudinalwaves.How far away was the earthquake?1. 671.3992. 464.6873. 709.4654. 421.2425. 897.9476. 1103.217. 812.8898. 837.9099. 587.15610. 743.937


Glacier Movement032 (part 1 of 2) 10.0 points

A glacier advances at 5.9× 10−6 cm/s.


How far will it move in 38000 s?1. 0.5762. 0.30783. 0.22424. 0.20525. 0.2526. 0.18047. 0.16348. 0.299. 0.415810. 0.4575


033 (part 2 of 2) 10.0 pointsHow far will it move in 3.8 y?1. 618.1062. 728.4823. 1097.454. 707.0375. 807.3226. 629.1437. 1251.358. 1174.099. 781.46210. 1311.27


Graphical Analysis 01034 (part 1 of 7) 10.0 points


0 10 20 30 40 500

20

40

60

80

100

Time (sec)

Dis

tanc

e (m

)

Swimmer

1

Swimmer 2

How many meters can Swimmer 1 cover in30 seconds?

1. 50 m

2. 70 m

3. 30 m

4. 40 m

5. 90 m

6. 100 m

7. 20 m

8. 80 m

9. 60 m correct

10. 10 m

035 (part 2 of 7) 10.0 pointsHow far can Swimmer 2 cover in 30 seconds?

1. 40 m

2. 90 m

3. 70 m

4. 80 m

5. 30 m correct

6. 20 m

7. 50 m

8. 100 m

9. 10 m

10. 60 m

036 (part 3 of 7) 10.0 pointsPredict the distance Swimmer 1 can go in 60seconds.

1. 90 m

2. 80 m

3. 120 m correct

4. 50 m


5. 70 m

6. 40 m

7. 130 m

8. 110 m

9. 100 m

10. 60 m

037 (part 4 of 7) 10.0 pointsPredict the distance Swimmer 2 can go in 60seconds.

1. 110 m

2. 130 m

3. 80 m

4. 40 m

5. 120 m

6. 100 m

7. 70 m

8. 50 m

9. 60 m correct

10. 90 m

038 (part 5 of 7) 10.0 pointsWhich swimmer has the greatest speed?

1. Unable to determine.

2. The speeds are the same.

3. Swimmer 1 correct

4. Swimmer 2

039 (part 6 of 7) 10.0 points

What is the speed of Swimmer 1?

1. None of these

2. 4 m/s

3. 1 m/s

4. 6 m/s

5. 8 m/s

6. 5 m/s

7. 3 m/s

8. 7 m/s

9. 2 m/s correct

040 (part 7 of 7) 10.0 pointsWhat is the speed of Swimmer 2?

1. 4 m/s

2. 8 m/s

3. 3 m/s

4. 6 m/s

5. 2 m/s

6. None of these

7. 7 m/s

8. 1 m/s correct

9. 5 m/s

Hewitt CP9 03 E01041 10.0 points

What is the impact speed when a car mov-ing at 200 km/h bumps into the rear of an-other car traveling in the same direction at87 km/h?1. 107.02. 230.0


3. 218.04. 113.05. 115.06. 40.07. 35.08. 30.09. 16.010. 18.0

Correct answer: 113 km/h.

Average Speed042 10.0 points

A car is moving at a constant speed of 15 m/swhen the driver presses down on the gas pedaland accelerates for 14 s with an accelerationof 1.8 m/s2.What is the average speed of the car during

the period?1. 18.252. 22.63. 27.64. 23.95. 21.66. 23.257. 23.08. 20.259. 19.2510. 26.9


Average Speed 04043 10.0 points

On a drive from your home to town, you wishto average 48 mph. The distance from yourhome to town is 94miles. However, at 47 miles(half way), you find you have averaged only36 mph.What average speed must you maintain in

the remaining distance in order to have anoverall average speed of 48 mph?1. 56.42. 96.03. 55.24. 49.85. 66.06. 78.07. 90.0

8. 72.09. 84.010. 50.4

Correct answer: 72 mph.

Average Speed on a Trip044 (part 1 of 2) 10.0 points

A person travels by car from one city to an-other. She drives for 29.7 min at 73.7 km/h,14.7 min at 110 km/h, 35.1 min at 31.7 km/h,and spends 17.8 min along the way eatinglunch and buying gas.Determine the distance between the cities

along this route.1. 75.77082. 77.33723. 104.1184. 81.9765. 83.3936. 79.6057. 100.2558. 94.58859. 71.486510. 92.0482


045 (part 2 of 2) 10.0 pointsDetermine the average speed for the trip.1. 42.39442. 60.04863. 44.31424. 51.41145. 50.55056. 53.03977. 53.74548. 55.68279. 49.148110. 47.6264

Correct answer: 50.5505 km/h.

Average Velocity on a Trip046 10.0 points

A car travels along a straight stretch of road.It proceeds for 10.4 mi at 53 mi/h, then 26 miat 47 mi/h, and finally 32.7 mi at 30.4 mi/h.What is the car’s average velocity during


the entire trip?1. 41.69442. 39.09893. 43.45084. 44.22585. 35.7776. 44.83527. 37.86148. 40.66869. 38.687710. 40.1034

Correct answer: 37.8614 mi/h.

Car and Checkpoints 01 v1047 10.0 points

Consider a car which is traveling along astraight road with constant acceleration a.There are two checkpoints A and B which area distance 101 m apart. The time it takes forthe car to travel from A to B is 5.82 s.

A B

5.83 m/s2

101 m

Find the velocity vB for the case where theacceleration is 5.83 m/s2.1. 31.20792. 31.7673. 38.34624. 34.31935. 40.52136. 35.43757. 36.8388. 24.5319. 38.888210. 39.8525


Car and Checkpoints 02048 (part 1 of 2) 10.0 points

Consider a car which is traveling alonga straight road with constant acceleration7.5 m/s2 . There are two checkpoints A and Bwhich are a distance 95.1 m apart. The timeit takes for the car to travel from A to B is4.71 s .

A B

7.5 m/s2

95.1 m

Find the velocity difference, ∆v = vB − vAbetween the two checkpoints.1. 32.38322. 21.67123. 42.41934. 22.67375. 35.3256. 24.25927. 20.03288. 31.95719. 29.667210. 12.8934


049 (part 2 of 2) 10.0 pointsFind the velocity vB .1. 35.59512. 34.69453. 37.85364. 30.97995. 40.28916. 24.1957. 24.86288. 28.90159. 32.81810. 31.4717


Average and Instantaneous V050 (part 1 of 2) 10.0 points

The position versus time for a certain objectmoving along the x-axis is shown. The ob-ject’s initial position is −7 m.


−10

−8

−6

−4

−2

0

2

4

6

0 1 2 3 4 5 6 7 8 9

b

b

b b

b

b

time (s)

position(m

)

Find the instantaneous velocity at 6.5 s.1. -3.52. -5.03. -2.666674. -12.05. -4.56. -7.57. -3.666678. -8.09. -4.010. -7.0

Correct answer: −3.66667 m/s.

051 (part 2 of 2) 10.0 pointsFind the average velocity over the whole timeshown.1. 0.7777782. 0.6666673. 1.111114. 1.05. 0.8888896. 1.222227. 0.1111118. 1.333339. 0.55555610. -0.111111


Calc Practice 03052 10.0 points

Suppose the position equation for a moving

object is given by

s(t) = 3 t2 + 2 t+ 5

where s is measured in meters and t is mea-sured in seconds.Find the velocity of the object when t = 2.

1. 14 m/sec correct

2. 6 m/sec

3. 13 m/sec

4. None of these

5. 10 m/sec

Calc Practice 05053 (part 1 of 3) 10.0 points

A particle moves along the x-axis so thatits velocity at any time t ≥ 0 is given byv(t) = 3t2 − 2t− 1. The position x(t) is 5 fort = 2.Find a polynomial expression for the posi-

tion of the particle at any time t ≥ 0.

1. t3 + t2 + 6t+ 3

2. t3 − t2 − t+ 3 correct

3. t3 + t2 − 3t+ 3

4. 2t3 − t2 − t− 3

5. 3t3 − 2t2 − t+ 3

054 (part 2 of 3) 10.0 pointsFor what values of t, 0 ≤ t ≤ 3, is the par-ticle’s instantaneous velocity the same as itsaverage velocity on the closed interval [0, 3]?

1. 2.813

2. 3.798

3. 3.296

4. 2.917

5. 1.786 correct


055 (part 3 of 3) 10.0 pointsFind the total distance traveled by the parti-cle from time t = 0 until time t = 3.

1. 17 correct

2. 18

3. 15

4. 14

5. 16

Calc Practice 07056 10.0 points

A particle moves in a straight line with veloc-ity

v(t) = 3t2 − 6t.

If it initially starts moving from 0 (wherex = 0), what is its position x(t)?

1. x(t) = t3 − 3t2 + 1

2. x(t) = 6t

3. x(t) = 6t− 6

4. x(t) = 6t− 3t2

5. x(t) = t3 − 3t2 correct


Consider the displacement curve OABC

0 1 2−2

−1

0

1

2

x(m

)

t (s)


O

A

B

C

What is the average velocity from point Oto A?

1. vOA

= +√3 m/s

2. vOA

= +2 m/s correct

3. vOA

= −√3 m/s

4. vOA

= 0 m/s

5. vOA

= −2 m/s

058 (part 2 of 5) 10.0 pointsWhat is the average velocity for the motionfrom point O to point B?

1. vOB

= −√3 m/s

2. vOB

= −2 m/s

3. vOB

= +2 m/s

4. vOB

= 0 m/s correct

5. vOB

= +√3 m/s

059 (part 3 of 5) 10.0 pointsWhat is the average speed for the motion frompoint O to point B?

1. sOB

= −2 m/s


2. sOB

= +√3 m/s

3. sOB

= −√3 m/s

4. sOB

= +2 m/s correct

5. sOB

= 0 m/s

060 (part 4 of 5) 10.0 pointsWhat is the instantaneous velocity at pointB?

1. vB= 0 m/s

2. vB= −

√3 m/s

3. vB= +2 m/s

4. vB= +

√3 m/s

5. vB= −2 m/s correct

061 (part 5 of 5) 10.0 pointsWhat is the instantaneous speed at point B?

1. sB= −2 m/s

2. sB= +2 m/s correct

3. sB= +

√3 m/s

4. sB= 0

5. sB= −

√3 m/s


Consider the displacement curve OABC

0 1 2 3 4 5−2

−1

0

1

2

x(m

)

t (s)


O

A

B

C

What is the average velocity from point Oto A?

1. vOA

= +1.33 m/s

2. vOA

= −1.0 m/s

3. vOA

= −2.0 m/s

4. vOA

= +1.0 m/s

5. vOA

= 0 m/s

6. vOA

= −1.33 m/s

7. vOA

= +2.0 m/s correct

063 (part 2 of 5) 10.0 pointsWhat is the average velocity for the motionfrom point O to point B?

1. vOA

= +1.0 m/s

2. vOA

= +2.0 m/s

3. vOA

= −1.0 m/s

4. vOA

= −1.33 m/s

5. vOA

= 0 m/s correct

6. vOA

= +1.33 m/s


7. vOA

= −2.0 m/s

064 (part 3 of 5) 10.0 pointsWhat is the average speed for the motion frompoint O to point B?

1. sOB

= 0 m/s

2. sOB

= +1.0 m/s

3. sOB

= +1.33 m/s correct

4. sOB

= +2.0 m/s

5. sOB

= −1.33 m/s

6. sOB

= −2.0 m/s

7. sOB

= −1.0 m/s

065 (part 4 of 5) 10.0 pointsWhat is the instantaneous velocity at pointB?

1. vB= +1.0 m/s

2. vB= +1.33 m/s

3. vB= −2.0 m/s

4. vB= 0 m/s

5. vB= −1.0 m/s correct

6. vB= −1.33 m/s

7. vB= +2.0 m/s

066 (part 5 of 5) 10.0 pointsWhat is the instantaneous speed at point B?

1. sB= −2.0 m/s

2. sB= 0 m/s

3. sB= +1.0 m/s correct

4. sB= +2.0 m/s

5. sB= −1.33 m/s

6. sB= −1.0 m/s

7. sB= +1.33 m/s

Serway CP 02 16067 (part 1 of 3) 10.0 points

A race car moves such that its position fitsthe relationship

x(t) = (5.4 m/s) t+ (0.98 m/s3) t3

where x is measured in meters and t in sec-onds.Approximate the instantaneous velocity at

2.6 s, using a centered time interval of 0.1 s.1. 26.82562. 11.65643. 37.29024. 22.58875. 38.32326. 9.907957. 10.58898. 9.151679. 25.276810. 36.8066


068 (part 2 of 3) 10.0 pointsUse a 0.2 s interval centered at 2.6 s to ap-proximate the instantaneous velocity at 2.6 s.1. 45.05362. 10.10523. 10.63764. 10.49385. 35.29326. 18.79567. 9.96068. 27.4889. 5.899310. 25.2842


069 (part 3 of 3) 10.0 pointsFind the average velocity during the 2.6 s.1. 7.212. 12.0248


3. 8.25284. 14.31995. 13.61786. 5.6257. 12.86858. 10.6489. 7.646410. 14.704


Serway CP 02 15070 (part 1 of 4) 10.0 points

The position versus time for a certain objectmoving along the x-axis is shown. The ob-ject’s initial position is −4 m.

−6

−4

−2

0

2

4

6

8

0 1 2 3 4 5 6 7 8 9

b

b

b b

b

b

time (s)

position(m

)

Find the instantaneous velocity at 0.5 s.1. 5.02. 11.03. 10.04. 7.05. 6.06. 12.07. 8.08. 4.09. 6.510. 3.5

Correct answer: 10 m/s.

071 (part 2 of 4) 10.0 pointsFind the instantaneous velocity at 2.5 s.1. -1.333332. -0.6666673. -5.0

4. -2.05. -2.56. -1.666677. -1.58. -4.09. -3.010. -1.0

Correct answer: −1 m/s.

072 (part 3 of 4) 10.0 pointsFind the instantaneous velocity at 4.5 s.


073 (part 4 of 4) 10.0 pointsFind the instantaneous velocity at 8 s.


Accelerating Object074 10.0 points

If the acceleration of an object is zero at someinstant in time, what can be said about itsvelocity at that time?

1. It is positive.

2. It is zero.


4. It is negative.

5. It is not changing at that time. correct

Acceleration075 10.0 points

A car travels in a straight line for 3.1 h at aconstant speed of 59 km/h .What is its acceleration?

Correct answer: 0 m/s2.

Acceleration vs Time 01076 (part 1 of 4) 10.0 points

Consider the plot below describing the accel-eration of a particle along a straight line withan initial position of 43 m and an initial ve-


locity of 9 m/s.

−1

0

1

2

3

4

5

6

0 1 2 3 4 5 6 7 8 9

time (s)

acceleration(m

/s2)

What is the velocity at 1 s?1. 5.02. 15.03. 9.04. 28.05. 21.06. -39.07. 22.08. 2.09. 14.010. 33.0


077 (part 2 of 4) 10.0 pointsWhat is the position at 1 s?1. -37.52. 36.03. 9.54. 2.05. -68.06. 54.57. 6.08. -31.09. -34.010. -18.5

Correct answer: 54.5 m.

078 (part 3 of 4) 10.0 pointsWhat is the velocity at 6 s?1. -18.02. -43.03. 34.0

4. 54.05. -5.06. 3.07. -23.08. -9.09. 24.010. 19.0


079 (part 4 of 4) 10.0 pointsWhat is the position at 6 s?1. -35.02. -60.03. -208.54. -4.55. 72.06. 117.07. 126.08. 47.59. -49.510. 184.5


Acceleration Time Graph 02080 10.0 points

Consider a toy car which moves to the right(positive direction) on a horizontal surfacealong a straight line.

carv

O +

Which acceleration-time graph correspondsto the motion of the car if it moves toward theright, while slowing down at a steady rate.

1. t

a

correct


2. t

a


4. t

a

5. t

a

6. t

a

7. t

a

8. t

a

Antilock Brakes081 10.0 points

The following acceleration vs time plots showdata gathered from an automobile fitted withan accelerometer. In each case the driver ac-celerated to cruising speed and then slammedon the brakes. In one case the car is equippedwith an antilock braking system (ABS), whilein the other the car is not. ABS tends toprevent skidding and did just that in this ex-

periment, allowing a more rapid deceleration.

0 2 4 6 8 10Time (seconds)

0

0 2 4 6 8 10Time (seconds)

0

A

A

Which data set, the upper or lower, morelikely came from the car equipped with ABS,and why?

1. Lower case, because of data between 2.5and 6.5 seconds

2. Upper case, because of data between 6.5and 9 seconds correct

3. Lower case, because of data in the first2.5 seconds

4. Upper case, because of data between 9and 10 seconds

5. Upper case, because of data between 2.5and 6.5 seconds

6. Lower case, because of data between 6.5and 9 seconds

7. Upper case, because of data in the first2.5 seconds

8. Lower case, because of data between 9and 10 seconds


Acceleration Time Graph 01082 (part 1 of 5) 10.0 points

Consider a toy car which can move to theright (positive direction) or left on a horizon-tal surface along a straight line.

car

v

O +

What is the acceleration-time graph if thecar moves toward the right (away from theorigin), speeding up at a steady rate?

1. t

a

correct

2. t

a


4. t

a

5. t

a

6. t

a

7. t

a

8. t

a

083 (part 2 of 5) 10.0 pointsWhat is the acceleration-time graph if the carmoves toward the right, slowing down at asteady rate?

1. t

a

2. t

a

3. t

a



5. t

a

6. t

a

correct

7. t

a

8. t

a

084 (part 3 of 5) 10.0 pointsWhat is the acceleration-time graph if the carmoves towards the left (toward the origin) ata constant velocity?

1. t

a

2. t

a

correct

3. t

a

4. t

a

5. t

a

6. t

a


8. t

a

085 (part 4 of 5) 10.0 pointsWhat is the acceleration-time graph if the carmoves toward the left, speeding up at a steadyrate?

1. t

a


2. t

a

correct

3. t

a


5. t

a

6. t

a

7. t

a

8. t

a

086 (part 5 of 5) 10.0 pointsWhat is the acceleration-time graph if the carmoves toward the right at a constant velocity?

1. t

a

2. t

a

3. t

a

4. t

a


6. t

a

7. t

a

8. t

a

correct

Average Acceleration087 10.0 points


An object travels 7 m in the first second oftravel, 7 m again during the second second oftravel, and 7 m again during the third second,all in the same direction.What is the approximate average accelera-

tion of the object during this time interval?

1. 8 m/s2

2. 6 m/s2

3. 5 m/s2

4. 0 m/s2 correct

5. 7 m/s2

6. 3 m/s2

7. 9 m/s2

8. 4 m/s2


Holt SF 02C 01088 10.0 points

A car accelerates uniformly from rest to aspeed of 23.9 km/h in 4.7 s.Find the distance it travels during this time.1. 19.71252. 15.83333. 24.9754. 15.60145. 20.32226. 14.8757. 17.34038. 22.48339. 20.533310. 21.3097



When Maggie applies the brakes of her car,the car slows uniformly from 14.7 m/s to 0m/s in 2.36 s.How far ahead of a stop sign must she apply

her brakes in order to stop at the sign?1. 17.3462. 18.4223. 17.13854. 16.0365. 18.76156. 17.7847. 15.3018. 16.5369. 16.774510. 19.422



A jet plane lands with a speed of 120 m/s andcan decelerate uniformly at a maximum rateof 5.1 m/s2 as it comes to rest.Can this plane land at an airport where

the runway is 0.85 km long? Answer this bycalculating.1. 1.12. 1.51253. 1.475614. 1.315225. 1.06146. 1.041677. 1.263168. 1.411769. 1.756110. 1.21



A driver in a car traveling at a speed of67 km/h sees a cat 124 m away on the road.How long will it take for the car to acceler-

ate uniformly to a stop in exactly 120 m?1. 10.49142. 11.7123. 10.75074. 9.378955. 12.3136. 10.33857. 10.96128. 12.6


9. 12.104310. 12.8955

Correct answer: 12.8955 s.


A car enters the freeway with a speed of 6.3m/s and accelerates uniformly for 3.2 km in2.9 min.How fast is the car moving after this time?1. 18.26192. 14.70543. 22.00744. 18.85765. 29.28526. 34.82567. 30.48168. 30.03229. 27.823810. 23.0474


Holt SF 02D 01093 (part 1 of 2) 10.0 points

A car with an initial speed of 23.1 km/h ac-celerates at a uniform rate of 0.99 m/s2 for 3.6s.Find the final speed of the car.1. 9.223562. 10.87173. 9.401674. 10.6155. 10.16. 8.437117. 9.105118. 9.655339. 9.8166710. 9.98067


094 (part 2 of 2) 10.0 pointsFind the displacement of the car after thattime.1. 0.02631052. 0.03837163. 0.0200911

4. 0.02983355. 0.03197786. 0.02808657. 0.02951528. 0.02421629. 0.025992510. 0.0377295


Particle Collision095 10.0 points

This time particle A starts from rest and ac-celerates to the right at 63.2 cm/s2. ParticleB starts 386 cm down the track and moves ata constant velocity of 50.8 cm/s to the left.When will they meet?1. 2.572512. 2.738853. 2.782474. 2.693815. 2.529976. 2.652587. 2.620068. 2.927379. 2.8162710. 2.87385


Paths Cross096 10.0 points

Runner A is initially 4.4 mi west of a flagpoleand is running with a constant velocity of5.9 mi/h due east. Runner B is initially 3.9 mieast of the flagpole and is running with aconstant velocity of 5.7 mi/h due west.How far are the runners from the flagpole

when they meet?1. 0.02. 0.08753. 0.1784484. 0.2309095. 0.05853666. 0.03035717. 0.520878. 0.2752149. 0.12711910. 0.504348


Correct answer: 0.178448 mi.

Speedboat097 (part 1 of 2) 10.0 points

A speedboat increases in speed from 18.9 m/sto 31.4 m/s in a distance 193 m.Find the magnitude of its acceleration.1. 1.284672. 1.271153. 1.628894. 1.758075. 1.604216. 1.028717. 1.510418. 1.218099. 1.980810. 0.997009

Correct answer: 1.62889 m/s2.

098 (part 2 of 2) 10.0 pointsFind the time it takes the boat to travel thisdistance.1. 6.804122. 7.380073. 8.223944. 9.511115. 7.673966. 7.023177. 8.662428. 7.821019. 7.2138210. 7.5514


Stopping car099 10.0 points

At time t = 0 a car moving along a straightline has a velocity of 16 m/s. It slows downwith a constant acceleration of −0.5 m/s2. Itstops at t =

1. 4 s

2. 32 s correct

3. 64 s

4. 16 s

5. 8 s

A Ball Hits the Ground100 (part 1 of 2) 10.0 points

A ball is dropped from the top of a tall build-ing of height h = 50 m .About how long does it take for the ball to

hit the ground? (Neglect air resistance.)

1. 5.2 s

2. 1 s

3. 3.1 s correct

4. 10 s

5. 2.4 s

101 (part 2 of 2) 10.0 pointsIf the ball has lost half the magnitude of itsimpact momentum immediately after it re-coils, to what height does the ball reach afterits first rebound?

1.h

4correct

2.h

2

3. 0

4.h

3

5. h

Acceleration 24102 10.0 points

If you drop an object, it will accelerate down-ward at a rate of g = 9.8 m/s2.If you throw it downward instead, its accel-

eration (in the absence of air resistance) willbe



2. greater than 9.8 m/s2.

3. less than 9.8 m/s2.

4. 9.8 m/s2 correct

Acceleration at the Top103 10.0 points

A stone is thrown straight upward and at thetop of its trajectory its velocity is momentar-ily zero.

What is its acceleration at this point?


2. 9.8 m/s2 up

3. Zero

4. 9.8 m/s2 down correct

Air Jordan104 10.0 points

A basketball player achieves a hang time of0.562 s in dunking the ball.What vertical height will he attain? The

acceleration of gravity is 9.8 m/s2 .1. 1.29962. 0.9856463. 0.8216824. 0.3869095. 0.4986296. 1.648367. 1.171698. 1.005529. 0.4846610. 1.4025


AP B 1993 MC 5105 10.0 points

An object is released from rest on a planetthat has no atmosphere. The object fallsfreely for 3 m in the first second.What is the magnitude of the acceleration

due to gravity on the planet?

1. 1.5 m/s2

2. 12.0 m/s2

3. 10.0 m/s2

4. 6.0 m/s2 correct

5. 3.0 m/s2

AP M 1993 MC 1106 10.0 points

In the absence of air friction, an objectdropped near the surface of the Earth ex-periences a constant acceleration of about 9.8m/s2.This means that the

1. speed of the object as it falls is 9.8 m/s.

2. speed of the object increases 9.8 m/s dur-ing each second. correct

3. object falls 9.8 meters during the firstsecond only.

4. derivative of the distance with respect totime for the object equals 9.8 m/s2.

5. object falls 9.8 meters during each sec-ond.

AP M 1993 MC 19107 10.0 points

An object is shot vertically upward into theair with a positive initial velocity.What correctly describes the velocity and

acceleration of the object at its maximumelevation?


Velocity Acceleration

1. positive negative

2. zero negative correct

3. zero zero

4. negative negative

5. positive positive

Average Speed of a Fall108 10.0 points

A ball is released from rest and falls a distanceh under the influence of gravity.What is its average speed during the fall?

1.1

2

√

g h

2. 2√

g h

3. 0

4.√

g h

5.√

2 g h

6.

√

1

2g h correct

Approaching Cars109 (part 1 of 3) 10.0 points

Two cars approach each other; both cars aremoving westward, one at 70 km/h, the otherat 65 km/h.What is the magnitude of the velocity of the

first car relative to (in the frame of referenceof) the second car?1. 26.02. 22.03. 18.04. 16.05. 8.06. 5.07. 19.08. 6.09. 24.010. 15.0

Correct answer: 5 km/h.

110 (part 2 of 3) 10.0 pointsWhat is the direction of the resultant veloc-ity?

1. Westward correct


3. Eastward

111 (part 3 of 3) 10.0 pointsAfter they pass, how will their relative veloc-ity change?

1. No change correct

2. Greater than before

3. Less than before


Motion 03112 10.0 points

Motion is

1. the stopping of an object relative to aframe of reference.

2. a change in position relative to a frame ofreference. correct

3. a decrease in the speed of an object.

4. an increase in the speed of an object.

Motion 11113 10.0 points

The most common frame of reference is

1. the sky.

2. the object you are observing.

3. you.


4. the Earth. correct

version 001 – one dimensional motion – ramadoss – (1234) 1 · 2019. 7. 12. · motion 007...

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