answers (lesson 11-1) · rationalizing the denominator ... pre-activity how are radical expressions...

21
© Glencoe/McGraw-Hill A2 Glencoe Algebra 1 Study Guide and Intervention Simplifying Radical Expressions NAME ______________________________________________ DATE ____________ PERIOD _____ 11-1 11-1 © Glencoe/McGraw-Hill 643 Glencoe Algebra 1 Lesson 11-1 Product Property of Square Roots The Product Property of Square Roots and prime factorization can be used to simplify expressions involving irrational square roots. When you simplify radical expressions with variables, use absolute value to ensure nonnegative results. Product Property of Square Roots For any numbers a and b, where a 0 and b 0, ab a b . Simplify 180 . 180 2 2 3 3 5 Prime factorization of 180 2 2 3 2 5 Product Property of Square Roots 2 3 5 Simplify. 65 Simplify. Simplify 120a 2 b 5 c 4 . 120a 2 b 5 c 4 2 3 3 5 a 2 b 5 c 4 2 2 2 3 5 a 2 b 4 b c 4 2 2 3 5 | a | b 2 b c 2 2 | a | b 2 c 2 30b Simplify. 1. 28 2. 68 3. 60 4. 75 27 217 215 53 5. 162 6. 3 6 7. 2 5 8. 5 10 92 32 10 52 9. 4a 2 10. 9x 4 11. 300a 4 12. 128c 6 2 | a | 3x 2 10a 2 3 8 | c 3 | 2 13. 410 36 14. 3x 2 33x 4 15. 20a 2 b 4 16. 100x 3 y 2415 9 | x 3 | 2 | a | b 2 5 10 | x | xy 17. 24a 4 b 2 18. 81x 4 y 2 19. 150a 2 b 2 c 2a 2 | b | 6 9x 2 | y | 5 | ab | 6c 20. 72a 6 b 3 c 2 21. 45x 2 y 5 z 8 22. 98x 4 y 6 z 2 6 | a 3 bc | 2b 3 | x | y 2 z 4 5y 7x 2 | y 3 z | 2 Example 1 Example 1 Example 2 Example 2 Exercises Exercises © Glencoe/McGraw-Hill 644 Glencoe Algebra 1 Quotient Property of Square Roots A fraction containing radicals is in simplest form if no radicals are left in the denominator. The Quotient Property of Square Roots and rationalizing the denominator can be used to simplify radical expressions that involve division. When you rationalize the denominator, you multiply the numerator and denominator by a radical expression that gives a rational number in the denominator. Quotient Property of Square Roots For any numbers a and b, where a 0 and b 0, . Simplify . Simplify the numerator and denominator. Multiply by to rationalize the denominator. Product Property of Square Roots Simplify. 1. 2. 3. 4. 5 5. 2 6. 7. 8. 9. 10. 11. 12. 13. 14. 42 26 15. 5 25 16. 45 14 33 8 27 410 5 2 5 8 2 3 3 5 2 4 3 5 5 | bc 3 | 3b | a | 75b 3 c 6 a 2 5a 2 6b 4 100a 4 144b 8 | x 3 | y 2 x 6 y 4 | a | 30 10 | b 3 | 3a 2 10b 6 14 7 2 5 5 7 30 4 5 2 3 4 23 5 6 5 2 5 82 28 75 3 10 11 100 121 3 3 8 24 2 2 9 18 270 15 5 5 5 5 214 35 2 14 3 5 4 14 9 5 56 45 56 45 a b a b Study Guide and Intervention (continued) Simplifying Radical Expressions NAME ______________________________________________ DATE ____________ PERIOD _____ 11-1 11-1 Example Example Exercises Exercises Answers (Lesson 11-1)

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Page 1: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A2 Glencoe Algebra 1

Stu

dy

Gu

ide

and I

nte

rven

tion

Sim

plify

ing

Rad

ical

Exp

ress

ions

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-1

11-1

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Lesson 11-1

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Answers (Lesson 11-1)

Page 2: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A3 Glencoe Algebra 1

Ans

wer

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11-1

11-1

Answers (Lesson 11-1)

Page 3: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A4 Glencoe Algebra 1

Rea

din

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11-1

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Lesson 11-1

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e if

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adic

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loca

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11-1

11-1

Exam

ple

Exam

ple

Answers (Lesson 11-1)

Page 4: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A5 Glencoe Algebra 1

Ans

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11-2

11-2

©G

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Lesson 11-2

Add

and

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trac

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dica

l Exp

ress

ions

Whe

n ad

ding

or

subt

ract

ing

radi

cal

expr

essi

ons,

use

the

Ass

ocia

tive

and

Dis

trib

utiv

e P

rope

rtie

s to

sim

plif

y th

e ex

pres

sion

s.If

radi

cal e

xpre

ssio

ns a

re n

ot in

sim

ples

t fo

rm,s

impl

ify

them

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pli

fy 1

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pli

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Mul

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wit

h di

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ent

radi

cand

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8").

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11-2

11-2

Exam

ple

Exam

ple

Exer

cises

Exer

cises

Answers (Lesson 11-2)

Page 5: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A6 Glencoe Algebra 1

Skil

ls P

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Ope

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ns w

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11-2

11-2

©G

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Lesson 11-2

Sim

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exp

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11-2

11-2

Answers (Lesson 11-2)

Page 6: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A7 Glencoe Algebra 1

Ans

wer

s

Rea

din

g t

o L

earn

Math

emati

csO

pera

tions

with

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ions

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____

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11-2

11-2

©G

lenc

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3G

lenc

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ra 1

Lesson 11-2

Pre-

Act

ivit

yH

ow c

an y

ou u

se r

adic

al e

xpre

ssio

ns

to d

eter

min

e h

ow f

ar a

per

son

can

see

?

Rea

d th

e in

trod

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on t

o L

esso

n 11

-2 a

t th

e to

p of

pag

e 59

3 in

you

r te

xtbo

ok.

Supp

ose

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subs

titu

te t

he h

eigh

ts o

f the

Sea

rs T

ower

and

the

Em

pire

Sta

teB

uild

ing

into

the

form

ula

to fi

nd h

ow fa

r yo

u ca

n se

e fr

om a

top

each

bui

ldin

g.W

hat

oper

atio

n sh

ould

you

the

n us

e to

det

erm

ine

how

muc

h fa

rthe

r yo

u ca

nse

e fr

om t

he S

ears

Tow

er t

han

from

the

Em

pire

Sta

te B

uild

ing?

subt

ract

ion

Read

ing

the

Less

on

1.In

dica

te w

heth

er t

he f

ollo

win

g ex

pres

sion

s ar

e in

sim

ples

t fo

rm.E

xpla

in y

our

answ

er.

a.6!

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No;

12 c

an b

e si

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ified

to

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b.12

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form

,the

radi

cand

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e di

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ent,

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ther

e ar

e no

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mon

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tors

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2.B

elow

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wor

ds F

irst

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ms,

Out

er t

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ner

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rite

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ou w

ould

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e ex

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(2!

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)(6!

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iffe

rent

num

bers

and

exp

ress

ions

usi

ng

geom

etri

c co

nstr

ucti

ons.

The

odor

us,a

Gre

ek p

hilo

soph

er w

ho li

ved

abou

t 42

5 B.C

.,is

sa

id t

o ha

ve d

isco

vere

d a

way

to

cons

truc

t th

e se

quen

ce

!1",

!2",

!3",

!4",

….

The

beg

inni

ng o

f hi

s co

nstr

ucti

on is

sho

wn.

You

star

t w

ith

anis

osce

les

righ

t tr

iang

le w

ith

side

s 1

unit

long

.

Use

th

e fi

gure

abo

ve.W

rite

eac

h l

engt

h a

s a

rad

ical

exp

ress

ion

in

sim

ple

st f

orm

.

1.lin

e se

gmen

t A

O!

1"2.

line

segm

ent

BO

!2"

3.lin

e se

gmen

t C

O!

3"4.

line

segm

ent

DO

!4"

5.D

escr

ibe

how

eac

h ne

w t

rian

gle

is a

dded

to

the

figu

re.

Dra

w a

new

sid

e of

leng

th 1

at r

ight

ang

les

to t

he la

st h

ypot

enus

e. T

hen

draw

the

new

hyp

oten

use.

6.T

he le

ngth

of

the

hypo

tenu

se o

f th

e fi

rst

tria

ngle

is !

2".Fo

r th

e se

cond

tri

angl

e,th

ele

ngth

is !

3".W

rite

an

expr

essi

on fo

r th

e le

ngth

of t

he h

ypot

enus

e of

the

nth

tri

angl

e.

!n

#1

"7.

Show

tha

t th

e m

etho

d of

con

stru

ctio

n w

ill a

lway

s pr

oduc

e th

e ne

xt n

umbe

r in

the

sequ

ence

.(H

int:

Fin

d an

exp

ress

ion

for

the

hypo

tenu

se o

f th

e (n

"1)

th t

rian

gle.

)

!(!

n")2

"#

(1)

"2 "o

r !

n#

1"

8.In

the

spa

ce b

elow

,con

stru

ct a

Whe

el o

f The

odor

us.S

tart

wit

h a

line

segm

ent

1ce

ntim

eter

long

.Whe

n do

es t

he W

heel

sta

rt t

o ov

erla

p?

afte

r le

ngth

!18"

1

1

1

1 OAB

CD

En

rich

men

t

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-2

11-2

Answers (Lesson 11-2)

Page 7: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A8 Glencoe Algebra 1

Stu

dy

Gu

ide

and I

nte

rven

tion

Rad

ical

Equ

atio

ns

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-3

11-3

©G

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5G

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lgeb

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Lesson 11-3

Radi

cal E

quat

ions

Equ

atio

ns c

onta

inin

g ra

dica

ls w

ith

vari

able

s in

the

rad

ican

d ar

eca

lled

rad

ical

equ

atio

ns.

The

se c

an b

e so

lved

by

firs

t us

ing

the

follo

win

g st

eps.

Ste

p 1

Isol

ate

the

radi

cal o

n on

e si

de o

f the

equ

atio

n.S

tep

2S

quar

e ea

ch s

ide

of th

e eq

uatio

n to

elim

inat

e th

e ra

dica

l.

Sol

ve 1

6 %

for

x.

16 "

Orig

inal

equ

atio

n

2(16

) "

2 %&

Mul

tiply

eac

h si

de b

y 2.

32 "

!x"

Sim

plify

.

(32)

2"

(!x")

2S

quar

e ea

ch s

ide.

1024

"x

Sim

plify

.

The

sol

utio

n is

102

4,w

hich

che

cks

in t

heor

igin

al e

quat

ion.

!x"

$2

!x"

$2

!x"

#2

Sol

ve !

4x"

"7"

$2

%7.

!4x

&7

"%

2 "

7O

rigin

al e

quat

ion

!4x

&7

"%

2 &

2 "

7 &

2S

ubtr

act 2

from

eac

h si

de.

!4x

&7

""

5S

impl

ify.

(!4x

&7

")2

"52

Squ

are

each

sid

e.

4x&

7 "

25S

impl

ify.

4x&

7 %

7 "

25 %

7A

dd 7

to e

ach

side

.

4x"

32S

impl

ify.

x"

8D

ivid

e ea

ch s

ide

by 4

.

The

sol

utio

n is

8,w

hich

che

cks

in t

he o

rigi

nal

equa

tion

.

Exam

ple1

Exam

ple1

Exam

ple2

Exam

ple2

Exer

cises

Exer

cises

Sol

ve e

ach

equ

atio

n.C

hec

k y

our

solu

tion

.

1.!

a""

864

2.!

a"%

6 "

3267

63.

2!x"

"8

16

4.7

"!

26 &

"n"

"23

5.!

&a

""

6"

366.

!3r

2"

"3

&!

3"

7.2!

3""

!y"

128.

2!3a"

&2

"7

69.

!x

&4

""

640

10.!

2c%

3"

"5

1111

.!3b

&"

2"%

19 "

249

12.!

4x&

1"

"3

13.!

3r%

2"

"2!

3"14

. #$"

15. #

$"4

128

16.!

6x2

%"

5x""

2,"

17. #

$%6

"8

1218

.2#$

%3

"11

262 # 3

3x $ 5x $ 3

4 # 31 # 2

x $ 81 # 2

1 $ 2x $ 2

10 # 3

5 # 2

3 # 4

©G

lenc

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6G

lenc

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Extr

aneo

us S

olut

ions

To s

olve

a r

adic

al e

quat

ion

wit

h a

vari

able

on

both

sid

es,y

oune

ed t

o sq

uare

eac

h si

de o

f th

e eq

uati

on.S

quar

ing

each

sid

e of

an

equa

tion

som

etim

espr

oduc

es e

xtra

neo

us

solu

tion

s,or

sol

utio

ns t

hat

are

not

solu

tion

s of

the

ori

gina

l equ

atio

n.T

here

fore

,it

is v

ery

impo

rtan

t th

at y

ou c

heck

eac

h so

luti

on.

Sol

ve !

x$

3"

%x

"3.

!x

%3

""

x&

3O

rigin

al e

quat

ion

(!x

%3

")2

"(x

&3)

2S

quar

e ea

ch s

ide.

x%

3 "

x2&

6x%

9S

impl

ify.

0 "

x2&

7x%

6S

ubtr

act x

and

3 fr

om e

ach

side

.

0 "

(x&

1)(x

&6)

Fac

tor.

x&

1 "

0or

x&

6 "

0Z

ero

Pro

duct

Pro

pert

y

x"

1x

"6

Sol

ve.

CH

ECK

!x

%3

""

x&

3!

x%

3"

"x

&3

!1

%3

"!

1 &

3!

6 %

3"

!6

&3

!4"

!&

2!

9"!

32

'&

23

"3

Sinc

e x

"1

does

not

sat

isfy

the

ori

gina

l equ

atio

n,x

"6

is t

he o

nly

solu

tion

.

Sol

ve e

ach

equ

atio

n.C

hec

k y

our

solu

tion

.

1.!

a""

a0,

12.

!a

%6

""

a3

3.2!

x""

x0,

4

4.n

"!

2 &

n"

15.

!&

a"

"a

06.

!10

&"

6k"%

3 "

k'

7.!

y&

1"

"y

&1

1,2

8.!

3a&

"2"

"a

1,2

9.!

x%

2"

"x

2

10.!

2c%

5"

"c

&5

1011

.!3b

%"

6""

b%

21

12.!

4x&

4"

"x

2

13.r

%!

2 &

r"

"2

1,2

14.!

x2%

1"

0x""

x%

48

15.&

2 #$"

15'

16.!

6x2

&"

4x""

x%

217

.!2y

2&

"64"

"y

18.!

3x2

%"

12x

%"

1""

x%

5

",2

8"

4,3

2 # 5

x $ 8

Stu

dy

Gu

ide

and I

nte

rven

tion

(c

onti

nued

)

Rad

ical

Equ

atio

ns

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-3

11-3

Exam

ple

Exam

ple

Exer

cises

Exer

cises

Answers (Lesson 11-3)

Page 8: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A9 Glencoe Algebra 1

Ans

wer

s

Skil

ls P

ract

ice

Rad

ical

Equ

atio

ns

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-3

11-3

©G

lenc

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w-H

ill65

7G

lenc

oe A

lgeb

ra 1

Lesson 11-3

Sol

ve e

ach

equ

atio

n.C

hec

k y

our

solu

tion

.

1.!

f""

749

2.!

&x

""

5"

25

3.!

5p""

1020

4.!

4y""

69

5.2!

2""

!u"

86.

3!5"

"!

&n

""

45

7.!

g"&

6 "

381

8.!

5a"%

2 "

0no

sol

utio

n

9.!

2c&

1"

"5

1310

.!3k

&"

2""

46

11.!

x%

4"

&2

"1

512

.!4x

&4

"&

4 "

05

13.

"4

144

14. #

$"3

27

15.x

"!

x%

2"

216

.d"

!12

&"

d"3

17.!

6x&

9"

"x

318

.!6p

&"

8""

p2,

4

19.!

x%

5"

"x

&1

420

.!8

&c

""

c&

88

21.!

r&

3"

%5

"r

722

.!y

&1

"%

3 "

y5

23.!

5n%

"4"

"n

%2

1,0

24.!

3z&

6"

"z

&2

5,2

m $ 3!

d"$

3

©G

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8G

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Sol

ve e

ach

equ

atio

n.C

hec

k y

our

solu

tion

.

1.!

&b

""

8"

642.

4!3"

"!

x"48

3.2!

4c"%

3 "

114

4.6

&!

2y""

&2

32

5.!

k%

2"

&3

"7

986.

!m

&5

""

4!3"

53

7.!

6t%

1"

2""

8!6"

628.

!3j

&1

"1"

%2

"9

20

9.!

2x%

1"

5"%

5 "

1877

10. #

$&4

"2

60

11.6#$

&3

"0

12.6

%#$

"&

2no

sol

utio

n

13.y

"!

y%

6"

314

.!15

&"

2x""

x3

15.!

w%

4"

"w

%4

"4,

"3

16.!

17 &

"k"

"k

&5

8

17.!

5m&

"16"

"m

&2

4,5

18.!

24 %

"8q"

"q

%3

"3,

5

19.!

4s%

1"

7"&

s&

3 "

02

20.4

&!

3m%

"28"

"m

"1

21.!

10p

%"

61"&

7 "

p"

6,2

22.!

2x2

&"

9""

x3

ELEC

TRIC

ITY

For

Exe

rcis

es 2

3 an

d 2

4,u

se t

he

foll

owin

g in

form

atio

n.

The

vol

tage

Vin

a c

ircu

it is

giv

en b

y V

"!

PR"

,whe

re P

is t

he p

ower

in w

atts

and

Ris

the

resi

stan

ce in

ohm

s.

23.I

f th

e vo

ltag

e in

a c

ircu

it is

120

vol

ts a

nd t

he c

ircu

it p

rodu

ces

1500

wat

ts o

f po

wer

,wha

tis

the

res

ista

nce

in t

he c

ircu

it?

9.6

ohm

s

24.S

uppo

se a

n el

ectr

icia

n de

sign

s a

circ

uit

wit

h 11

0 vo

lts

and

a re

sist

ance

of

10 o

hms.

How

muc

h po

wer

will

the

cir

cuit

pro

duce

?12

10 w

atts

FREE

FA

LLF

or E

xerc

ises

25

and

26,

use

th

e fo

llow

ing

info

rmat

ion

.A

ssum

ing

no a

ir r

esis

tanc

e,th

e ti

me

tin

sec

onds

tha

t it

tak

es a

n ob

ject

to

fall

hfe

et c

an b

e

dete

rmin

ed b

y th

e eq

uati

on t

".

25.I

f a

skyd

iver

jum

ps f

rom

an

airp

lane

and

fre

e fa

lls f

or 1

0 se

cond

s be

fore

ope

ning

the

para

chut

e,ho

w m

any

feet

doe

s th

e sk

ydiv

er f

all?

1600

ft

26.S

uppo

se a

sec

ond

skyd

iver

jum

ps a

nd f

ree

falls

for

6 s

econ

ds.H

ow m

any

feet

doe

s th

ese

cond

sky

dive

r fa

ll?57

6 ft

!h"

$4

5r $ 61 # 4

3x $ 3

3s $ 5

Pra

ctic

e (A

vera

ge)

Rad

ical

Equ

atio

ns

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-3

11-3

Answers (Lesson 11-3)

Page 9: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A10 Glencoe Algebra 1

Rea

din

g t

o L

earn

Math

emati

csR

adic

al E

quat

ions

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-3

11-3

©G

lenc

oe/M

cGra

w-H

ill65

9G

lenc

oe A

lgeb

ra 1

Lesson 11-3

Pre-

Act

ivit

yH

ow a

re r

adic

al e

quat

ion

s u

sed

to

fin

d f

ree-

fall

tim

es?

Rea

d th

e in

trod

ucti

on t

o L

esso

n 11

-3 a

t th

e to

p of

pag

e 59

8 in

you

r te

xtbo

ok.

How

can

you

isol

ate

!h"

on o

ne s

ide

of t

he e

quat

ion?

Mul

tiply

eac

h si

de o

f th

e eq

uatio

n by

4.

Read

ing

the

Less

on

1.To

sol

ve a

rad

ical

equ

atio

n,yo

u fi

rst

isol

ate

the

radi

cal o

n on

e si

de o

f th

e eq

uati

on.W

hydo

you

the

n sq

uare

eac

h si

de o

f th

e eq

uati

on?

to e

limin

ate

the

radi

cal

2.a.

Pro

vide

the

rea

son

for

each

ste

p in

the

sol

utio

n of

the

giv

en r

adic

al e

quat

ion.

!5x

&1

"&

4"

x&

3O

rigi

nal e

quat

ion

!5x

&1

""

x%

1A

dd 4

to

each

sid

e.(!

5x&

1"

)2"

(x%

1)2

Squ

are

each

sid

e.5x

&1

"x2

%2x

%1

Sim

plify

.0

"x2

&3x

%2

Sub

trac

t 5x

and

add

1 to

eac

h si

de.

0"

(x&

1)(x

&2)

Fact

or.

x&

1 "

0or

x&

2 "

0Ze

ro P

rodu

ct P

rope

rty

x"

1x

"2

Sol

ve.

b.To

be

sure

tha

t 1

and

2 ar

e th

e co

rrec

t so

luti

ons,

into

whi

ch e

quat

ion

shou

ld y

ousu

bsti

tute

to

chec

k?th

e or

igin

al e

quat

ion

3.a.

How

do

you

dete

rmin

e w

heth

er a

n eq

uati

on h

as a

n ex

tran

eous

sol

utio

n?

Sub

stitu

te t

he s

olut

ion(

s) in

to t

he o

rigi

nal e

quat

ion.

If a

solu

tion

does

not

satis

fy t

he o

rigi

nal e

quat

ion,

then

it is

an

extr

aneo

us s

olut

ion.

b.Is

it n

eces

sary

to

chec

k al

l sol

utio

ns t

o el

imin

ate

extr

aneo

us s

olut

ions

? E

xpla

in.

Yes;

sinc

e yo

u sq

uare

eac

h si

de o

f a

radi

cal e

quat

ion,

and

squa

ring

each

sid

e ca

n so

met

imes

pro

duce

an

extr

aneo

us s

olut

ion,

you

need

to

che

ck a

ll so

lutio

ns.T

he o

nly

way

to

be s

ure

that

a s

olut

ion

is n

otex

tran

eous

is t

o ch

eck

it in

the

ori

gina

l equ

atio

n.

Hel

ping

You

Rem

embe

r

4.H

ow c

an y

ou u

se t

he le

tter

s IS

C t

o re

mem

ber

the

thre

e st

eps

in s

olvi

ng a

rad

ical

equa

tion

?

Sam

ple

answ

er:I

sola

te t

he r

adic

al o

n on

e si

de o

f th

e eq

uatio

n,S

quar

eea

ch s

ide

to e

limin

ate

the

radi

cal,

and

Che

ck fo

r ex

tran

eous

sol

utio

ns.

©G

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0G

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lgeb

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Spe

cial

Pol

ynom

ial P

rodu

cts

Som

etim

es t

he p

rodu

ct o

f tw

o po

lyno

mia

ls c

an b

e fo

und

read

ily w

ith

the

use

of o

ne o

f th

e sp

ecia

l pro

duct

s of

bin

omia

ls.

For

exam

ple,

you

can

find

the

squ

are

of a

tri

nom

ial b

y re

calli

ng t

hesq

uare

of

a bi

nom

ial.

Fin

d (

x$

y$

z)2 .

(a%

b)2

"a2

%2

#a

#b

%b2

[(x

%y)

%z]

2"

(x%

y)2

%2(

x%

y)z

%z2

"x2

%2x

y%

y2%

2xz

%2y

z%

z2

Fin

d (

3t$

x$

1)(3

t"

x"

1).

(Hin

t:(3

t%

x%

1)(3

t&

x&

1) is

the

pro

duct

of

a su

m 3

t%

(x%

1)an

d a

diff

eren

ce 3

t&

(x%

1).)

(3t

%x

%1)

(3t

&x

&1)

"[3

t%

(x%

1)][

3t&

(x%

1)]

"9t

2&

(x%

1)2

"9t

2&

x2&

2x

&1

Use

a s

pec

ial

pro

du

ct o

f bi

nom

ials

to

fin

d e

ach

pro

du

ct.

1.(x

%y

&z)

22.

(r%

s%

5)2

x2$

2xy

"2x

z$

y2"

2yz

$z2

r2$

2rs

$s2

$10

r$

10s

$25

3.(b

&3

%d)

24.

(k&

m&

2)2

b2

"6b

$2b

d$

9 "

6d$

d2

k2"

2km

$m

2"

4k$

4m$

4

5.(x

%1

%2b

)(x

%1

&2b

)6.

(y&

2 %

x)(y

&2

&x)

x2$

2x$

1 "

4b2

y2"

4y$

4 "

x2

7.(5

%b

&x)

(5 %

b%

x)8.

(j&

5 &

f)(j

%5

%f)

25 $

10b

$b

2"

x2j2

"f2

"10

f"25

9.[(

x%

y) %

(z%

w)]

[(x

%y)

&(z

%w

)]10

.(2a

%1

%3b

&c)

(2a

%1

&3b

%c)

x2$

2xy

$y2

"z2

"2z

w"

w2

4a2

$4a

$1

"9b

2$

6bc

"c2

En

rich

men

t

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-3

11-3

Exam

ple1

Exam

ple1

Exam

ple2

Exam

ple2

Answers (Lesson 11-3)

Page 10: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A11 Glencoe Algebra 1

Ans

wer

s

Stu

dy

Gu

ide

an

d I

nte

rven

tion

The

Pyt

hago

rean

The

orem

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-4

11-4

©G

lenc

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cGra

w-H

ill66

1G

lenc

oe A

lgeb

ra 1

Lesson 11-4

The

Pyth

agor

ean

Theo

rem

The

sid

e op

posi

te t

he r

ight

ang

le in

a r

ight

tri

angl

e is

calle

d th

e h

ypot

enu

se.T

his

side

is a

lway

s th

e lo

nges

t si

de o

f a r

ight

tri

angl

e.T

he o

ther

two

side

s ar

e ca

lled

the

legs

of t

he t

rian

gle.

To f

ind

the

leng

th o

f an

y si

de o

f a

righ

ttr

iang

le,g

iven

the

leng

ths

of t

he o

ther

tw

o si

des,

you

can

use

the

Pyt

hag

orea

n T

heo

rem

.

Pyt

hago

rean

The

orem

If a

and

bar

e th

e m

easu

res

of th

e le

gs o

f a r

ight

tria

ngle

and

cis

the

mea

sure

of t

he h

ypot

enus

e, th

en c

2!

a2"

b2.

CB

Ab

ac

Fin

d t

he

len

gth

of

the

hyp

oten

use

of

a ri

ght

tria

ngl

e if

a!

5an

d b

!12

.

c2!

a2"

b2P

ytha

gore

an T

heor

em

c2!

52"

122

a!

5 an

d b

!12

c2!

169

Sim

plify

.

c!

!16

9"

Take

the

squa

re r

oot o

f eac

h si

de.

c!

13

The

leng

th o

f th

e hy

pote

nuse

is 1

3.

Fin

d t

he

len

gth

of

a le

gof

a r

igh

t tr

ian

gle

if a

!8

and

c!

10.

c2!

a2"

b2P

ytha

gore

an T

heor

em

102

!82

"b2

a!

8 an

d c

!10

100

!64

"b2

Sim

plify

.

36 !

b2S

ubtr

act 6

4 fr

om e

ach

side

.

b!

#!

36"Ta

ke th

e sq

uare

roo

t of e

ach

side

.

b!

#6

The

leng

th o

f th

e le

g is

6.

Exam

ple1

Exam

ple1

Exam

ple2

Exam

ple2

Exer

cises

Exer

cises

Fin

d t

he

len

gth

of

each

mis

sin

g si

de.

If n

eces

sary

,rou

nd

to

the

nea

rest

hu

nd

red

th.

1.2.

3.

5045

.83

35.3

6

If c

is t

he

mea

sure

of

the

hyp

oten

use

of

a ri

ght

tria

ngl

e,fi

nd

eac

h m

issi

ng

mea

sure

.If

nec

essa

ry,r

oun

d t

o th

e n

eare

st h

un

dre

dth

.

4.a

!10

,b!

12,c

!?

5.a

!9,

b!

12,c

!?

6.a

!12

,b!

?,c

!16

15.6

215

10.5

8

7.a

!?,

b!

6,c

!8

8.a

!?,

b!

!8",

c!

!18"

9.a

!!

5",b

!!

10",c

!?

5.29

3.16

3.87

25

25c

100

110

a

40

30c

©G

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2G

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Righ

t Tr

iang

les

If a

and

bar

e th

e m

easu

res

of t

he s

hort

er s

ides

of

a tr

iang

le,c

is t

hem

easu

re o

f th

e lo

nges

t si

de,a

nd c

2!

a2"

b2,t

hen

the

tria

ngle

is a

rig

ht t

rian

gle.

Det

erm

ine

wh

eth

er t

he

foll

owin

g si

de

mea

sure

s fo

rm r

igh

t tr

ian

gles

.

a.10

,12,

14Si

nce

the

mea

sure

of

the

long

est

side

is 1

4,le

t c

!14

,a!

10,a

nd b

!12

.

c2!

a2"

b2P

ytha

gore

an T

heor

em

142

!10

2"

122

a!

10, b

!12

, c!

14

196

!10

0 "

144

Mul

tiply

.

196

$24

4A

dd.

Sinc

e c2

$a2

"b2

,the

tri

angl

e is

not

a r

ight

tri

angl

e.

b.7,

24,2

5Si

nce

the

mea

sure

of

the

long

est

side

is 2

5,le

t c

!25

,a!

7,an

d b

!24

.

c2!

a2"

b2P

ytha

gore

an T

heor

em

252

!72

"24

2a

!7,

b!

24, c

!25

625

!49

"57

6M

ultip

ly.

625

!62

5A

dd.

Sinc

e c2

!a2

"b2

,the

tri

angl

e is

a r

ight

tri

angl

e.

Det

erm

ine

wh

eth

er t

he

foll

owin

g si

de

mea

sure

s fo

rm r

igh

t tr

ian

gles

.

1.14

,48,

50ye

s2.

6,8,

10ye

s3.

8,8,

10no

4.90

,120

,150

yes

5.15

,20,

25ye

s6.

4,8,

4!5"

yes

7.2,

2,!

8"ye

s8.

4,4,

!20"

no9.

25,3

0,35

no

10.2

4,36

,48

no11

.18,

80,8

2ye

s12

.150

,200

,25

0ye

s

13.1

00,2

00,3

00no

14.5

00,1

200,

1300

yes

15.7

00,1

000,

1300

no

Stu

dy

Gu

ide

and I

nte

rven

tion

(c

onti

nued

)

The

Pyt

hago

rean

The

orem

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-4

11-4

Exam

ple

Exam

ple

Exer

cises

Exer

cises

Answers (Lesson 11-4)

Page 11: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A12 Glencoe Algebra 1

Skil

ls P

ract

ice

The

Pyt

hago

rean

The

orem

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-4

11-4

©G

lenc

oe/M

cGra

w-H

ill66

3G

lenc

oe A

lgeb

ra 1

Lesson 11-4

Fin

d t

he

len

gth

of

each

mis

sin

g si

de.

If n

eces

sary

,rou

nd

to

the

nea

rest

hu

nd

red

th.

1.2.

3.

7536

30

4.5.

6.

15.7

59.

8570

If c

is t

he

mea

sure

of

the

hyp

oten

use

of

a ri

ght

tria

ngl

e,fi

nd

eac

h m

issi

ng

mea

sure

.If

nec

essa

ry,r

oun

d t

o th

e n

eare

st h

un

dre

dth

.

7.a

"21

,b"

28,c

"?

358.

a"

6,c

"10

,b"

?8

9.a

"15

,b"

36,c

"?

3910

.a"

16,c

"20

,b"

?12

11.a

"5,

b"

12,c

"?

1312

.b"

6,c

"12

,a"

?!

108

"%

10.3

9

13.a

"11

,b"

4,c

"?

!13

7"

%11

.70

14.a

"8,

b"

10,c

"?

!16

4"

%12

.81

15.a

"19

,b"

!39"

,c"

?20

16.a

"!

12",b

"6,

c"

?!

48"%

6.93

17.c

"!

130

",a

"7,

b"

?9

18.a

"!

6",b

"!

19",c

"?

5

Det

erm

ine

wh

eth

er t

he

foll

owin

g si

de

mea

sure

s fo

rm r

igh

t tr

ian

gles

.Ju

stif

y yo

ur

answ

er.

19.7

,24,

25Ye

s;72

$24

2%

252 .

20.1

5,30

,34

No;

152

$30

2(

342 .

21.1

6,28

,32

No;

162

$28

2(

322 .

22.1

8,24

,30

Yes;

182

$24

2%

302 .

23.1

5,36

,39

Yes;

152

$36

2%

392 .

24.5

,7,!

74"Ye

s;52

$72

%( !

74")2 .

25024

0

a4

9c29

33

b

1634

b

1539a

21

72c

©G

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w-H

ill66

4G

lenc

oe A

lgeb

ra 1

Fin

d t

he

len

gth

of

each

mis

sin

g si

de.

If n

eces

sary

,rou

nd

to

the

nea

rest

hu

nd

red

th.

1.2.

3.

6815

.49

11.3

1

If c

is t

he

mea

sure

of

the

hyp

oten

use

of

a ri

ght

tria

ngl

e,fi

nd

eac

h m

issi

ng

mea

sure

.If

nec

essa

ry,r

oun

d t

o th

e n

eare

st h

un

dre

dth

.

4.a

"24

,b"

45,c

"?

515.

a"

28,b

"96

,c"

?10

0

6.b

"48

,c"

52,a

"?

207.

c"

27,a

"18

,b"

?!

405

"%

20.1

2

8.b

"14

,c"

21,a

"?

!24

5"

%15

.65

9.a

"!

20",b

"10

,c"

?!

120

"%

10.9

5

10.a

"!

75",b

"!

6",c

"?

911

.b"

9x,c

"15

x,a

"?

12x

Det

erm

ine

wh

eth

er t

he

foll

owin

g si

de

mea

sure

s fo

rm r

igh

t tr

ian

gles

.Ju

stif

y yo

ur

answ

er.

12.1

1,18

,21

13.2

1,72

,75

No;

112

$18

2(

212 .

Yes;

212

$72

2%

752 .

14.7

,8,1

115

.9,1

0,!

161

"N

o;72

$82

(11

2 .N

o;92

$10

2(

( !16

1"

)2 .

16.9

,2!

10",1

117

.!7",

2!2",

!15"

Yes;

92$

2(!

10")2

%11

2 .Ye

s;( !

7")2

$( 2

!2")

2%

( !15"

)2 .

18.S

TOR

AG

ET

he s

hed

in S

teph

an’s

bac

k ya

rd h

as a

doo

r th

at m

easu

res

6 fe

et h

igh

and

3 fe

et w

ide.

Step

han

wou

ld li

ke t

o st

ore

a sq

uare

the

ater

pro

p th

at is

7 f

eet

on a

sid

e.W

ill it

fit

thr

ough

the

doo

r di

agon

ally

? E

xpla

in.

No;

the

grea

test

leng

th t

hat

will

fit

thr

ough

the

doo

r is

!45"

%6.

71 f

t.

SCR

EEN

SIZ

ESF

or E

xerc

ises

19–

21,u

se t

he

foll

owin

g in

form

atio

n.

The

siz

e of

a t

elev

isio

n is

mea

sure

d by

the

leng

th o

f th

e sc

reen

’s d

iago

nal.

19.I

f a

tele

visi

on s

cree

n m

easu

res

24 in

ches

hig

h an

d 18

inch

es w

ide,

wha

t si

ze t

elev

isio

n is

it?

30-in

.tel

evis

ion

20.D

arla

tol

d T

ri t

hat

she

has

a 35

-inc

h te

levi

sion

.The

hei

ght

of t

he s

cree

n is

21

inch

es.

Wha

t is

its

wid

th?

28 in

.

21.T

ri t

old

Dar

la t

hat

he h

as a

5-i

nch

hand

held

tel

evis

ion

and

that

the

scr

een

mea

sure

s 2

inch

es b

y 3

inch

es.I

s th

is a

rea

sona

ble

mea

sure

for

the

scr

een

size

? E

xpla

in.

No;

ifth

e sc

reen

mea

sure

s 2

in.b

y 3

in.,

then

its

diag

onal

is o

nly

abou

t 3.

61 in

.

124

b19

11

a

60

32cPra

ctic

e (A

vera

ge)

The

Pyt

hago

rean

The

orem

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-4

11-4

Answers (Lesson 11-4)

Page 12: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A13 Glencoe Algebra 1

Ans

wer

s

Rea

din

g t

o L

earn

Math

emati

csTh

e P

ytha

gore

an T

heor

em

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-4

11-4

©G

lenc

oe/M

cGra

w-H

ill66

5G

lenc

oe A

lgeb

ra 1

Lesson 11-4

Pre-

Act

ivit

yH

ow i

s th

e P

yth

agor

ean

Th

eore

m u

sed

in

rol

ler

coas

ter

des

ign

?

Rea

d th

e in

trod

ucti

on t

o L

esso

n 11

-4 a

t th

e to

p of

pag

e 60

5 in

you

r te

xtbo

ok.

The

dia

gram

in t

he in

trod

ucti

on s

how

s a

righ

t tr

iang

le a

nd p

art

of t

hero

ller

coas

ter.

Whi

ch s

ide

of t

he r

ight

tri

angl

e ha

s a

leng

th a

ppro

xim

atel

yeq

ual t

o th

e le

ngth

of

the

firs

t hi

ll of

the

rol

ler

coas

ter?

the

long

est

side

,whi

ch is

the

sid

e op

posi

te t

he r

ight

ang

le

Read

ing

the

Less

onC

omp

lete

eac

h s

ente

nce

.

1.T

he w

ords

leg

and

hypo

tenu

sere

fer

to t

he s

ides

of

a tr

iang

le.

2.In

a r

ight

tri

angl

e,ea

ch o

f the

tw

o si

des

that

form

the

rig

ht a

ngle

is a

of

the

rig

ht t

rian

gle.

3.T

he lo

nges

t si

de o

f a

righ

t tr

iang

le is

cal

led

the

of t

he r

ight

tri

angl

e.

Wri

te a

n e

quat

ion

th

at y

ou c

ould

sol

ve t

o fi

nd

th

e m

issi

ng

sid

e le

ngt

h o

f ea

chri

ght

tria

ngl

e.

4.5.

6.

c2%

92$

102

102

%62

$b2

102

%a2

$92

7.Su

ppos

e yo

u ar

e gi

ven

thre

e po

siti

ve n

umbe

rs.E

xpla

in h

ow y

ou c

an d

ecid

e w

heth

erth

ese

num

bers

are

the

leng

ths

of t

he s

ides

of

a ri

ght

tria

ngle

.

Sam

ple

answ

er:P

ut t

he n

umbe

rs in

ord

er f

rom

leas

t to

gre

ates

t.S

quar

eth

e th

ree

num

bers

.See

whe

ther

the

sum

of

the

squa

res

of t

he t

wo

smal

ler

num

bers

is e

qual

to

the

squa

re o

f th

e la

rges

t nu

mbe

r.If

it is

,th

en t

he n

umbe

rs a

re t

he le

ngth

s of

the

sid

es o

f a

righ

t tr

iang

le.

Hel

ping

You

Rem

embe

r

8.T

hink

of

a w

ord

or p

hras

e th

at y

ou c

an a

ssoc

iate

wit

h th

e P

ytha

gore

an T

heor

em t

o he

lpyo

u re

mem

ber

the

equa

tion

c2

"a2

%b2

.

Sam

ple

answ

er:T

hink

of

the

wor

d ca

b.Th

e le

tter

s of

this

wor

d ar

e th

esa

me

as th

ose

in th

e eq

uatio

n c

2%

a2$

b2 .

9106

109

10

hypo

tenu

se

leg

righ

t

©G

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6G

lenc

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Pyt

hago

rean

Tri

ples

Rec

all t

he P

ytha

gore

an t

heor

em:

In a

rig

ht t

rian

gle,

the

squa

re o

f th

e le

ngth

of

the

hypo

tenu

se

is e

qual

to

the

sum

of

the

squa

res

of t

he le

ngth

s of

the

legs

.

a2%

b2"

c2

Not

e th

at c

is t

he le

ngth

of

the

hyp

oten

use.

The

inte

gers

3,4

,and

5 s

atis

fy t

he

32%

42"

52

Pyt

hago

rean

the

orem

and

can

be

the

9 %

16"

25le

ngth

s of

the

sid

es o

f a

righ

t tr

iang

le.

25"

25

Fur

ther

mor

e,fo

r an

y po

siti

ve in

tege

r n,

For

n"

2:62

%82

"10

2

the

num

bers

3n,

4n,a

nd 5

nsa

tisf

y th

e 36

%64

"10

0P

ytha

gore

an t

heor

em.

100

"10

0

If t

hree

num

bers

sat

isfy

the

Pyt

hago

rean

the

orem

,the

y ar

e ca

lled

a P

yth

agor

ean

tri

ple.

Her

e is

an

easy

way

to

find

oth

er P

ytha

gore

an t

ripl

es.

The

num

bers

a,b

,and

car

e a

Pyt

hago

rean

tri

ple

if a

"m

2&

n2,b

"2m

n,an

d c

"m

2%

n2,w

here

man

d n

are

rela

tive

ly p

rim

e po

siti

ve in

tege

rs a

nd m

(n.

Ch

oose

m%

5 an

d n

%2.

a"

m2

&n2

b"

2mn

c"

m2

%n2

Ch

eck

202

%21

2!

292

"52

&22

"2(

5)(2

)"

52%

2240

0 %

441

!84

1"

25 &

4"

20"

25 %

484

1"

841

"21

"29

Use

th

e fo

llow

ing

valu

es o

f m

and

nto

fin

d P

yth

agor

ean

tri

ple

s.

1.m

"3

and

n"

22.

m"

4 an

d n

"1

3.m

"5

and

n"

3

5,12

,13

8,15

,17

16,3

0,34

4.m

"6

and

n"

55.

m"

10 a

nd n

"7

6.m

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and

n"

5

11,6

0,61

51,1

40,1

4939

,80,

89

ACB a

c b

En

rich

men

t

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-4

11-4

Exam

ple

Exam

ple

Answers (Lesson 11-4)

Page 13: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A14 Glencoe Algebra 1

Stu

dy

Gu

ide

and I

nte

rven

tion

The

Dis

tanc

e Fo

rmul

a

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-5

11-5

©G

lenc

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7G

lenc

oe A

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Lesson 11-5

The

Dis

tanc

e Fo

rmul

aT

he P

ytha

gore

an T

heor

em c

an b

e us

ed t

o de

rive

the

Dis

tan

ceF

orm

ula

show

n be

low

.The

Dis

tanc

e Fo

rmul

a ca

n th

en b

e us

ed t

o fi

nd t

he d

ista

nce

betw

een

any

two

poin

ts in

the

coo

rdin

ate

plan

e.

Dis

tanc

e Fo

rmul

aT

he d

ista

nce

betw

een

any

two

poin

ts w

ith c

oord

inat

es (

x 1, y

1) a

nd (

x 2, y

2) is

giv

en b

y

d"

!(x

2&

"x 1

)2%

"(y

2&

"y 1

)2"

.

Fin

d t

he

dis

tan

ce b

etw

een

th

ep

oin

ts a

t ("

5,2)

an

d (

4,5)

.

d"

!(x

2&

"x 1

)2%

"(y

2&

"y 1

)2"

Dis

tanc

e F

orm

ula

"!

(4 &

("

&5)

)2"

%(5

&"

2)2

"(x

1, y

1) "

(&5,

2),

(x2,

y2)

"(4

, 5)

"!

92%

3"

2 "S

impl

ify.

"!

81 %

"9"

Eva

luat

e sq

uare

s an

d si

mpl

ify.

"!

90"T

he d

ista

nce

is !

90",o

r ab

out

9.49

uni

ts.

Jill

dra

ws

a li

ne

segm

ent

from

poi

nt

(1,4

) on

her

com

pu

ter

scre

en t

o p

oin

t (9

8,49

).H

ow l

ong

is t

he

segm

ent?

d"

!(x

2&

"x 1

)2%

"(y

2&

"y 1

)2"

"!

(98

&"

1)2

%"

(49

&"

4)2

""

!97

2%

"45

2"

"!

9409

"%

202

"5"

"!

11,4

3"

4"T

he s

egm

ent

is a

bout

106

.93

unit

slo

ng.

Exam

ple1

Exam

ple1

Exam

ple2

Exam

ple2

Exer

cises

Exer

cises

Fin

d t

he

dis

tan

ce b

etw

een

eac

h p

air

of p

oin

ts w

hos

e co

ord

inat

es a

re g

iven

.E

xpre

ss a

nsw

ers

in s

imp

lest

rad

ical

for

m a

nd

as

dec

imal

ap

pro

xim

atio

ns

rou

nd

edto

th

e n

eare

st h

un

dre

dth

if

nec

essa

ry.

1.(1

,5),

(3,1

)2.

(0,0

),(6

,8)

3.(&

2,&

8),(

7,&

3)

2!5";

4.47

10!

106

";1

0.30

4.(6

,&7)

,(&

2,8)

5.(1

,5),

(&8,

4)6.

(3,&

4),(

&4,

&4)

17!

82";9

.06

7

7.(&

1,4)

,(3,

2)8.

(0,0

),(&

3,5)

9.(2

,&6)

,(&

7,1)

2!5";

4.47

!34"

;5.8

3!

130

";1

1.40

10.(

&2,

&5)

,(0,

8)11

.(3,

4),(

0,0)

12.(

3,&

4),(

&4,

&16

)

!17

3"

;13.

155

!19

3"

;13.

89

13.(

1,&

1),(

3,&

2)14

.(&

2,0)

,(&

3,&

9)15

.(&

9,0)

,(&

2,5)

!5";

2.24

!82"

;9.0

6!

74";8

.60

16.(

2,&

7),(

&2,

&2)

17.(

1,&

3),(

&8,

21)

18.(

&3,

&5)

,(1,

&8)

!41"

;6.4

0!

657

";2

5.63

5

©G

lenc

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Find

Coo

rdin

ates

If y

ou k

now

the

coo

rdin

ates

of

one

poin

t an

d on

ly o

ne c

oord

inat

e of

a

seco

nd p

oint

,you

can

use

the

Dis

tanc

e Fo

rmul

a to

fin

d th

e m

issi

ng c

oord

inat

e of

the

seco

nd p

oint

.

Fin

d t

he

valu

e of

aif

th

e d

ista

nce

bet

wee

n t

he

poi

nts

at

("3,

"2)

and

(a

,"5)

is

5 u

nit

s.

d"

!(x

2&

"x 1

)2%

"(y

2&

"y 1

)2"

Dis

tanc

e F

orm

ula

5"

!(a

&(

"&

3))2

"%

(&5

"&

(&"

2))2

"(x

1, y

1) "

(&3,

&2)

, (x 2

, y2)

"(a

, &5)

, and

d"

5

5"

!(a

%3

")2

%(

"&

3)2

"S

impl

ify.

5"

!a2

%6

"a

%9

"%

9"

Eva

luat

e sq

uare

s.

5"

!a2

%6

"a

%1

"8"

Sim

plify

.

52"

(!a2

%6

"a

%1

"8")

2S

quar

e ea

ch s

ide.

25"

a2%

6a%

18S

impl

ify.

0"

a2%

6a&

7S

ubtr

act 2

5 fr

om e

ach

side

.

0"

(a%

7)(a

&1)

Fac

tor.

a%

7 "

0or

a&

1 "

0Z

ero

Pro

duct

Pro

pert

y

a"

&7

a"

1

The

val

ue o

f ais

&7

or 1

.

Fin

d t

he

pos

sibl

e va

lues

of

aif

th

e p

oin

ts w

ith

th

e gi

ven

coo

rdin

ates

are

th

ein

dic

ated

dis

tan

ce a

par

t.

1.(1

,a),

(3,&

2);d

"!

5"2.

(0,0

),(a

,4);

d"

53.

(2,&

1),(

a,3)

;d"

5

"1

or "

33

or "

3"

1 or

5

4.(1

,&3)

,(a,

21);

d"

255.

(1,a

),(&

2,4)

;d"

36.

(3,&

4),(

&4,

a);d

"!

65""

6 or

84

"8

or 0

7.(a

,&4)

,(&

3,&

2);d

"!

13"8.

(0,3

),(3

,a);

d"

3!2"

9.(a

,3),

(2,&

4);d

"!

74""

6 or

00

or 6

"3

or 7

10.(

&2,

&5)

,(a,

&2)

;d"

511

.(3,

3),(

&1,

a);d

"5

12.(

&1,

&1)

,(4,

a);d

"!

41""

6 or

20

or 6

"5

or 3

13.(

a,5)

,(&

1,2)

;d"

!45"

14.(

4,&

2),(

a,0)

;d"

2!2"

15.(

&2,

1),(

a,&

3);d

"2!

5""

7 or

52

or 6

"4

or 0

Stu

dy

Gu

ide

and I

nte

rven

tion

(c

onti

nued

)

The

Dis

tanc

e Fo

rmul

a

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-5

11-5

Exam

ple

Exam

ple

Exer

cises

Exer

cises

Answers (Lesson 11-5)

Page 14: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A15 Glencoe Algebra 1

Ans

wer

s

Skil

ls P

ract

ice

The

Dis

tanc

e Fo

rmul

a

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-5

11-5

©G

lenc

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cGra

w-H

ill66

9G

lenc

oe A

lgeb

ra 1

Lesson 11-5

Fin

d t

he

dis

tan

ce b

etw

een

eac

h p

air

of p

oin

ts w

hos

e co

ord

inat

es a

re g

iven

.E

xpre

ss a

nsw

ers

in s

imp

lest

rad

ical

for

m a

nd

as

dec

imal

ap

pro

xim

atio

ns

rou

nd

edto

th

e n

eare

st h

un

dre

dth

if

nec

essa

ry.

1.(9

,7),

(1,1

)10

2.(5

,2),

(8,&

2)5

3.(1

,&3)

,(1,

4)7

4.(7

,2),

(&5,

7)13

5.(&

6,3)

,(10

,3)

166.

(3,3

),(&

2,3)

5

7.(&

1,&

4),(

&6,

0)!

41"%

6.40

8.(&

2,4)

,(5,

8)!

65"%

8.06

9.(&

3,4)

,(&

2,8)

!17"

%4.

1210

.(5,

&6)

,(7,

&9)

!13"

%3.

61

11.(

4,2)

,(8,

6)4!

2"%

5.66

12.(

5,2)

,(3,

10)

2!17"

%8.

25

13.(

12,&

1),(

4,&

11)

2!41"

%12

.81

14.(

&3,

&1)

,(&

11,3

)4!

5"%

8.94

15.(

9,3)

,(6,

&6)

3!10"

%9.

4916

.(0,

&4)

,(8,

4)8!

2"%

11.3

1

Fin

d t

he

pos

sibl

e va

lues

of

aif

th

e p

oin

ts w

ith

th

e gi

ven

coo

rdin

ates

are

th

ein

dic

ated

dis

tan

ce a

par

t.

17.(

&2,

&5)

,(a,

7);d

"13

a%

"7

or 3

18.(

8,&

2),(

5,a)

;d"

3a

%"

2

19.(

4,a)

,(1,

6);d

"5

a%

2 or

10

20.(

a,3)

,(5,

&1)

;d"

5a

%2

or 8

21.(

1,1)

,(a,

1);d

"4

a%

"3

or 5

22.(

2,a)

,(2,

3);d

"10

a%

"7

or 1

3

23.(

a,2)

,(&

3,3)

;d"

!2"

a%

"4

or "

224

.(&

5,3)

,(&

3,a)

;d"

!5"

a%

2 or

4

©G

lenc

oe/M

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w-H

ill67

0G

lenc

oe A

lgeb

ra 1

Fin

d t

he

dis

tan

ce b

etw

een

eac

h p

air

of p

oin

ts w

hos

e co

ord

inat

es a

re g

iven

.E

xpre

ss a

nsw

ers

in s

imp

lest

rad

ical

for

m a

nd

as

dec

imal

ap

pro

xim

atio

ns

rou

nd

edto

th

e n

eare

st h

un

dre

dth

if

nec

essa

ry.

1.(4

,7),

(1,3

)5

2.(0

,9),

(&7,

&2)

!17

0"

%13

.04

3.(4

,&6)

,(3,

&9)

!10"

%3.

164.

(&3,

&8)

,(&

7,2)

2!29"

%10

.77

5.(0

,&4)

,(3,

2)3!

5"%

6.71

6.(&

13,&

9),(

&1,

&5)

4!10"

%12

.65

7.(6

,2),

%4,&

or 2

.50

8.(&

1,7)

, %,6

&%

1.67

9.%2,

&&, %

1,&!

2"%

1.41

10. %

,&1 &,

%2,&

%1.

89

11.(!

3",3)

,(2!

3",5)

!7"

%2.

6512

.(2!

2",&

1),(

3!2",

3)3!

2"%

4.24

Fin

d t

he

pos

sibl

e va

lues

of

aif

th

e p

oin

ts w

ith

th

e gi

ven

coo

rdin

ates

are

th

ein

dic

ated

dis

tan

ce a

par

t.

13.(

4,&

1),(

a,5)

;d"

10a

%"

4 or

12

14.(

2,&

5),(

a,7)

;d"

15a

%"

7 or

11

15.(

6,&

7),(

a,&

4);d

"!

18"a

%3

or 9

16.(

&4,

1),(

a,8)

;d"

!50"

a%

"5

or "

3

17.(

8,&

5),(

a,4)

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"4

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Exe

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9–21

,use

th

e fo

llow

ing

info

rmat

ion

.T

hree

pla

yers

are

war

min

g up

for

a b

aseb

all g

ame.

Pla

yer

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stan

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feet

to

the

righ

t an

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feet

in fr

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of P

laye

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.P

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et t

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Pla

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raw

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odel

of

the

situ

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the

coo

rdin

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grid

.A

ssum

e th

at P

laye

r A

is lo

cate

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(0,

0).

20.T

o th

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ares

t te

nth,

wha

t is

the

dis

tanc

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twee

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and

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Pla

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Pla

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t

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APS

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acks

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map

of

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qual

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acks

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abou

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96 m

i

A(0

, 0)

B(9

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3)

x

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1 $ 21 $ 2

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5 # 21 $ 2Pra

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The

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____

____

____

____

____

____

____

____

____

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ATE

____

____

____

PE

RIO

D__

___

11-5

11-5

Answers (Lesson 11-5)

Page 15: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A16 Glencoe Algebra 1

Rea

din

g t

o L

earn

Math

emati

csTh

e D

ista

nce

Form

ula

NA

ME

____

____

____

____

____

____

____

____

____

____

____

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ATE

____

____

____

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D__

___

11-5

11-5

©G

lenc

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cGra

w-H

ill67

1G

lenc

oe A

lgeb

ra 1

Lesson 11-5

Pre-

Act

ivit

yH

ow c

an t

he

dis

tan

ce b

etw

een

tw

o p

oin

ts b

e d

eter

min

ed?

Rea

d th

e in

trod

ucti

on t

o L

esso

n 11

-5 a

t th

e to

p of

pag

e 61

1 in

you

r te

xtbo

ok.

Wha

t ar

e th

e co

ordi

nate

s of

poi

nts

A,B

,and

C?

A%

(4,3

),B

%("

3,"

2),a

nd C

%(4

,"2)

Read

ing

the

Less

on

1.Su

ppos

e yo

u w

ant

to u

se t

he D

ista

nce

Form

ula

to f

ind

the

dist

ance

bet

wee

n (6

,4)

and

(2,1

).U

se (x

1,y 1

) "(6

,4)

and

(x2,

y 2) "

(2,1

).C

ompl

ete

the

equa

tion

s by

wri

ting

the

co

rrec

t nu

mbe

rs in

the

bla

nks.

a.x 1

"y 1

"x 2

"y 2

"

b.d

"!"

""

"(

&)2

%(

&)2

2.Su

ppos

e yo

u w

ant

to u

se t

he D

ista

nce

Form

ula

to f

ind

the

dist

ance

bet

wee

n (3

,7)

and

(9,&

2).U

se (

x 1,y

1) "

(3,7

) an

d (x

2,y 2

) "(9

,&2)

.Com

plet

e th

e eq

uati

ons

by w

riti

ng t

heco

rrec

t nu

mbe

rs in

the

bla

nks.

a.x 1

"y 1

"x 2

"y 2

"

b.d

"!"

""

"(

&)2

%(

&)2

3.A

cla

ssm

ate

is u

sing

the

Dis

tanc

e Fo

rmul

a to

fin

d th

e di

stan

ce b

etw

een

two

poin

ts.S

he

has

done

eve

ryth

ing

corr

ectl

y so

far

,and

her

equ

atio

n is

d"

!(&

2 &

"5)

2%

"(7

&"

11)2

".

Thi

s eq

uati

on w

ill g

ive

her

the

dist

ance

bet

wee

n w

hat

two

poin

ts?

(5,1

1) a

nd (

"2,

7)

Hel

ping

You

Rem

embe

r

4.So

met

imes

it is

eas

ier

to r

emem

ber

a fo

rmul

a if

you

can

sta

te it

in w

ords

.How

can

you

stat

e th

e D

ista

nce

Form

ula

in e

asy-

to-r

emem

ber

wor

ds?

Sam

ple

answ

er:S

quar

e th

e di

ffer

ence

bet

wee

n th

e x-

coor

dina

tes,

then

add

that

to

the

squa

re o

f th

e di

ffer

ence

bet

wee

n th

e y-

coor

dina

tes.

Take

the

squa

re r

oot

of t

he s

um t

o fin

d th

e di

stan

ce b

etw

een

the

two

poin

ts.

7"

23

9

"2

97

3

41

62

12

46

x

y

O

A

B

©G

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2G

lenc

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lgeb

ra 1

A S

pace

-Sav

ing

Met

hod

Tw

o ar

rang

emen

ts f

or c

ooki

es o

n a

32 c

m b

y 40

cm

coo

kie

shee

t ar

e sh

own

at t

he r

ight

.The

coo

kies

hav

e 8-

cm d

iam

eter

saf

ter

they

are

bak

ed.T

he c

ente

rs o

f th

e co

okie

s ar

e on

the

ve

rtic

es o

f sq

uare

s in

the

top

arr

ange

men

t.In

the

oth

er,t

hece

nter

s ar

e on

the

ver

tice

s of

equ

ilate

ral t

rian

gles

.Whi

char

rang

emen

t is

mor

e ec

onom

ical

? T

he t

rian

gle

arra

ngem

ent

is m

ore

econ

omic

al,b

ecau

se it

con

tain

s on

e m

ore

cook

ie.

In t

he s

quar

e ar

rang

emen

t,ro

ws

are

plac

ed e

very

8 c

m.A

t w

hat

inte

rval

s ar

e ro

ws

plac

ed in

the

tri

angl

e ar

rang

emen

t?

Loo

k at

the

rig

ht t

rian

gle

labe

led

a,b,

and

c.A

leg

aof

the

tria

ngle

is t

he r

adiu

s of

a c

ooki

e,or

4 c

m.T

he h

ypot

enus

e c

is

the

sum

of

two

radi

i,or

8 c

m.U

se t

he P

ytha

gore

an t

heor

em t

o fi

nd b

,the

inte

rval

of

the

row

s.

c2"

a2%

b2

82"

42%

b2

64 &

16 "

b2

!48"

"b

4 !3"

"b

b"

4 !3"

'6.

93

The

row

s ar

e pl

aced

app

roxi

mat

ely

ever

y 6.

93 c

m.

Sol

ve e

ach

pro

blem

.

1.Su

ppos

e co

okie

s w

ith

10-c

m d

iam

eter

s ar

e ar

rang

ed in

the

tr

iang

ular

pat

tern

sho

wn

abov

e.W

hat

is t

he in

terv

al b

of t

he r

ows?

8.66

cm

2.F

ind

the

diam

eter

of

a co

okie

if t

he r

ows

are

plac

ed in

the

tr

iang

ular

pat

tern

eve

ry 3

!3"

cm.

6 cm

3.D

escr

ibe

othe

r pr

acti

cal a

pplic

atio

ns in

whi

ch t

his

kind

of

tria

ngul

ar p

atte

rn c

an b

e us

ed t

o ec

onom

ize

on s

pace

.A

nsw

ers

will

var

y.S

ampl

e an

swer

:pac

kagi

ng c

ans

(b

% ?

21 c

ooki

es

ca

(8

cm

20 c

ooki

es

En

rich

men

t

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-5

11-5

Answers (Lesson 11-5)

Page 16: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A17 Glencoe Algebra 1

Ans

wer

s

Stu

dy

Gu

ide

an

d I

nte

rven

tion

Sim

ilar

Tria

ngle

s

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-6

11-6

©G

lenc

oe/M

cGra

w-H

ill67

3G

lenc

oe A

lgeb

ra 1

Lesson 11-6

Sim

ilar

Tria

ngle

s!

RS

Tis

sim

ilar

to !

XY

Z.T

he a

ngle

s of

the

tw

o tr

iang

les

have

equ

al m

easu

re.T

hey

are

calle

d co

rres

pon

din

gan

gles

.The

sid

es o

ppos

ite

the

corr

espo

ndin

g an

gles

are

cal

led

corr

esp

ond

ing

sid

es.

If tw

o tr

iang

les

are

sim

ilar,

then

the

!A

BC

!!

DE

FS

imila

r Tr

iang

les

mea

sure

s of

thei

r co

rres

pond

ing

side

sar

e pr

opor

tiona

l and

the

mea

sure

s of

!

!th

eir

corr

espo

ndin

g an

gles

are

equ

al.

AC

" DF

BC

" EF

AB

" DE

A

BD

E

F

C

30!

30!

60!

60!

SZ

X Y

RT

Det

erm

ine

wh

eth

erth

e p

air

of t

rian

gles

is

sim

ilar

.Ju

stif

y yo

ur

answ

er.

Sinc

e co

rres

pond

ing

angl

es d

o no

t ha

veth

e eq

ual m

easu

res,

the

tria

ngle

s ar

eno

t si

mila

r.

50!

75!

45!

89!

R

S

T

X

Y

Z

Det

erm

ine

wh

eth

er t

he

pai

rof

tri

angl

es i

s si

mil

ar.J

ust

ify

you

r an

swer

.

The

mea

sure

of "

G!

180°

#(9

0°$

45°)

!45

°.T

he m

easu

re o

f "I

!18

0°#

(45°

$45

°) !

90°.

Sinc

e co

rres

pond

ing

angl

es h

ave

equa

lm

easu

res,

!E

FG

!!

HIJ

.

90!

45!

45!

45!

F

G

H

J

I

E

Exam

ple1

Exam

ple1

Exam

ple2

Exam

ple2

Exer

cises

Exer

cises

Det

erm

ine

wh

eth

er e

ach

pai

r of

tri

angl

es i

s si

mil

ar.J

ust

ify

you

r an

swer

.

1.2.

3.

Yes;

cor

resp

ondi

ng

No;

cor

resp

ondi

ng

Yes;

cor

resp

ondi

ng

angl

es h

ave

equa

l an

gles

do

not

have

an

gles

hav

e eq

ual

mea

sure

s.eq

ual m

easu

res.

mea

sure

s.

4.5.

6.

Yes;

cor

resp

ondi

ng

Yes;

cor

resp

ondi

ng

No;

cor

resp

ondi

ng

angl

es h

ave

equa

l an

gles

hav

e eq

ual

angl

es d

o no

t ha

ve

mea

sure

s.m

easu

res.

equa

l mea

sure

s.

20!

30!

120!

115!

45!

45!

80!

55!

40!

30!

30!

110!

90!

45!

60!

60!

30!

30!

30!

120!

©G

lenc

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ill67

4G

lenc

oe A

lgeb

ra 1

Find

Unk

now

n M

easu

res

If s

ome

of t

he m

easu

rem

ents

are

kno

wn,

prop

orti

ons

can

be u

sed

to f

ind

the

mea

sure

s of

the

oth

er s

ides

of

sim

ilar

tria

ngle

s.

IND

IREC

T M

EASU

REM

ENT

!A

BC

!!

AE

Din

th

e fi

gure

at

the

righ

t.F

ind

th

e h

eigh

t of

th

e ap

artm

ent

buil

din

g.

Let

BC

!x.

! !E

D!

7, A

D!

25, A

C!

300

25x

!21

00F

ind

the

cros

s pr

oduc

ts.

x!

84T

he a

part

men

t bu

ildin

g is

84

met

ers

high

.

For

eac

h s

et o

f m

easu

res,

fin

d t

he

mea

sure

s of

th

e m

issi

ng

sid

es i

f !

AB

C!

!D

EF

.

1.c

!15

,d!

8,e

!6,

f!

10a

"12

;b"

9

2.c

!20

,a!

12,b

!8,

f!

15d

"9;

e"

6

3.a

!8,

d!

8,e

!6,

f!

7b

"6;

c"

7

4.a

!20

,d!

10,e

!8,

f!

10b

"16

;c"

20

5.c

!5,

d!

10,e

!8,

f!

8a

";b

"5

6.a

!25

,b!

20,c

!15

,f!

12d

"20

;e"

16

7.b

!8,

d!

8,e

!4,

f!

10a

"16

;c"

20

8.IN

DIR

ECT

MEA

SUR

EMEN

TB

ruce

like

s to

am

use

his

brot

her

by s

hini

ng a

fla

shlig

ht o

n hi

s ha

nd a

ndm

akin

g a

shad

ow o

n th

e w

all.

How

far

is it

fro

m

the

flas

hlig

ht t

o th

e w

all?

51.6

in.o

r 4.

3 ft

9.IN

DIR

ECT

MEA

SUR

EMEN

TA

for

est

rang

er u

ses

sim

ilar

tria

ngle

s to

fin

d th

e he

ight

of

a tr

ee.F

ind

the

heig

ht o

f th

e tr

ee.

60 f

t

12 ft

20 ft

x

100

ft

5 in

.6

in.

x in.

4 ft

Note

: Not

dra

wn

to s

cale

25 # 4

A

ca

be

fd

CD

F

EB

25 " 300

7 " x

AD

" AC

ED

" BC

25 m

Note

: Not

dra

wn

to s

cale

275

m

7 m

ADE

CB

x

Stu

dy

Gu

ide

and I

nte

rven

tion

(c

onti

nued

)

Sim

ilar T

rian

gles

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-6

11-6

Exam

ple

Exam

ple

Exer

cises

Exer

cises

Answers (Lesson 11-6)

Page 17: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A18 Glencoe Algebra 1

Skil

ls P

ract

ice

Sim

ilar T

rian

gles

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-6

11-6

©G

lenc

oe/M

cGra

w-H

ill67

5G

lenc

oe A

lgeb

ra 1

Lesson 11-6

Det

erm

ine

wh

eth

er e

ach

pai

r of

tri

angl

es i

s si

mil

ar.J

ust

ify

you

r an

swer

.

1.2.

Yes;

!A

%!

D%

90°;

!B

%N

o;!

Y%

180°

"(6

0°$

60°)

%60

°.18

0°"

(90°

$40

°) %

50°

%!

E;

Sin

ce "

UV

Wha

s a

57°

angl

e,bu

t !

F%

180°

"(9

0°$

50°)

%40

°%

"X

YZ

does

not

,cor

resp

ondi

ng

!C

.Sin

ce t

he c

orre

spon

ding

an

gles

do

not

all h

ave

equa

l an

gles

hav

e eq

ual m

easu

res,

mea

sure

s,an

d th

e tr

iang

les

are

not

"A

BC

&"

DE

F.si

mila

r.

3.4.

No;

!F

%18

0°"

(45°

$40

°) %

Yes;

!G

%18

0°"

(65°

$52

°) %

63°

%95

°.S

ince

"H

JKha

s a

90°

!K

;!J

%18

0°"

(63°

$52

°) %

65°

%an

gle,

but

"E

FGdo

es n

ot,

!F

;!E

%!

H%

52°.

Sin

ce t

he

corr

espo

ndin

g an

gles

do

not

all

corr

espo

ndin

g an

gles

hav

e eq

ual

have

equ

al m

easu

res,

and

the

m

easu

res,

"E

FG&

"H

JK.

tria

ngle

s ar

e no

t si

mila

r.

For

eac

h s

et o

f m

easu

res

give

n,f

ind

th

e m

easu

res

of t

he

mis

sin

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11-6

11-6

Answers (Lesson 11-6)

Page 18: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A19 Glencoe Algebra 1

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angl

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n th

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11-6

11-6

Answers (Lesson 11-6)

Page 19: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A20 Glencoe Algebra 1

Stu

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11-7

11-7

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Lesson 11-7

Trig

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11-7

11-7

Exer

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Answers (Lesson 11-7)

Page 20: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A21 Glencoe Algebra 1

Ans

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s

Skil

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Trig

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11-7

11-7

©G

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Lesson 11-7

For

eac

h t

rian

gle,

fin

d s

in N

,cos

N,a

nd

tan

Nto

th

e n

eare

st t

en t

hou

san

dth

.

1.2.

3.

sin

N%

0.38

46,

sin

N%

0.6,

sin

N%

0.88

24,

cos

N%

0.92

31,

cos

N%

0.8,

cos

N%

0.47

06,

tan

N%

0.41

67ta

n N

%0.

75ta

n N

%1.

875

Use

a c

alcu

lato

r to

fin

d t

he

valu

e of

eac

h t

rigo

nom

etri

c ra

tio

to t

he

nea

rest

te

n t

hou

san

dth

.

4.si

n 20

°0.

3420

5.co

s 32

°0.

8480

6.ta

n 75

°3.

7321

7.ta

n 17

°0.

3057

8.si

n 38

°0.

6157

9.co

s 55

°0.

5736

Use

a c

alcu

lato

r to

fin

d t

he

mea

sure

of

each

an

gle

to t

he

nea

rest

deg

ree.

10.s

in A

"0.

7624

50°

11.c

os L

"0.

8691

30°

12.t

an H

"1.

3024

52°

13.t

an V

"0.

5876

30°

14.s

in R

"0.

4320

26°

15.c

os S

"0.

3749

68°

For

eac

h t

rian

gle,

fin

d t

he

mea

sure

of

the

ind

icat

ed a

ngl

e to

th

e n

eare

st d

egre

e.

16.

17.

18.

21°

27°

71°

Sol

ve e

ach

rig

ht

tria

ngl

e.S

tate

th

e si

de

len

gth

s to

th

e n

eare

st t

enth

an

d t

he

angl

em

easu

res

to t

he

nea

rest

deg

ree.

19.

20.

21.

!B

%62

°,!

A%

36°,

!A

%37

°,B

C%

9.4

ft,

AB

%21

.0 c

m,

!B

%53

°,A

C%

17.7

ft

BC

%12

.4 c

mA

B%

35 m

21 m

28 m

ACB

17 c

m

54)

ACB

20 ft

28)

CA

B

412

?

5

?

113

8?

8

15

17

NPR

0.8

0.6

1F

N

E

1026 24

FD

N

©G

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2G

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For

eac

h t

rian

gle,

fin

d s

in T

,cos

T,a

nd

tan

Tto

th

e n

eare

st t

en t

hou

san

dth

.

1.2.

3.

sin

T%

0.32

43,

sin

T%

0.96

,si

n T

%0.

8944

,co

s T

%0.

9459

,co

s T

%0.

28,

cos

T%

0.44

72,

tan

T%

0.34

29ta

n T

%3.

4286

tan

T%

2

Use

a c

alcu

lato

r to

fin

d t

he

valu

e of

eac

h t

rigo

nom

etri

c ra

tio

to t

he

nea

rest

ten

thou

san

dth

.

4.si

n 85

°0.

9962

5.co

s 5°

0.99

626.

tan

32.5

°0.

6371

Use

a c

alcu

lato

r to

fin

d t

he

mea

sure

of

each

an

gle

to t

he

nea

rest

deg

ree.

7.si

n D

"0.

5000

30°

8.co

s Q

"0.

1123

84°

9.ta

n B

"4.

7465

78°

For

eac

h t

rian

gle,

fin

d t

he

mea

sure

of

the

ind

icat

ed a

ngl

e to

th

e n

eare

st d

egre

e.

10.

55°

11.

72°

12.

41°

Sol

ve e

ach

rig

ht

tria

ngl

e.S

tate

th

e si

de

len

gth

s to

th

e n

eare

st t

enth

an

d t

he

angl

em

easu

res

to t

he

nea

rest

deg

ree.

13.

14.

15.

!A

%39

°,!

B%

26°,

!A

%60

°,A

C%

20.2

yd,

AC

%5.

7 cm

,!

B%

30°,

BC

%16

.4 y

dB

C%

11.7

cm

BC

%26

.0 f

t

HIK

ING

For

Exe

rcis

es 1

6 an

d 1

7,u

se t

he

foll

owin

g in

form

atio

n.

The

10-

mile

Low

er W

est

Rim

tra

il in

Mt.

Zion

Nat

iona

l Par

k as

cend

s 26

40 f

eet.

16.W

hat

is t

he a

vera

ge a

ngle

of

elev

atio

n of

the

hik

e fr

om t

he c

anyo

n fl

oor

to t

he t

op o

f th

eca

nyon

? (H

int:

Dra

w a

dia

gram

in w

hich

the

leng

th o

f th

e tr

ail f

orm

s th

e hy

pote

nuse

of

a ri

ght

tria

ngle

.Con

vert

fee

t to

mile

s.)

abou

t 2.

17.W

hat

is t

he h

oriz

onta

l dis

tanc

e co

vere

d on

the

hik

e?ab

out

10 m

i

18.R

AM

P D

ESIG

NA

n en

gine

er d

esig

ned

the

entr

ance

to

a m

useu

m t

o in

clud

e a

whe

elch

air

ram

p th

at is

15

feet

long

and

for

ms

a 6°

angl

e w

ith

a si

dew

alk

in f

ront

of

the

mus

eum

.H

ow h

igh

does

the

ram

p ri

se?

abou

t 1.

6 ft

15 f

30 ft

BC A

13 c

m64

)

A CB

26 y

d

51)

CB

A

1612

?4042

?13

9?

16

88!

'5

C T

B25

724

R

P

T24

70

74T

X

Y

Pra

ctic

e (A

vera

ge)

Trig

onom

etri

c R

atio

s

NA

ME

____

____

____

____

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____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-7

11-7

Answers (Lesson 11-7)

Page 21: Answers (Lesson 11-1) · rationalizing the denominator ... Pre-Activity How are radical expressions used in space exploration? Read the introduction to Lesson 11-1 at the top of page

© Glencoe/McGraw-Hill A22 Glencoe Algebra 1

Rea

din

g t

o L

earn

Math

emati

csTr

igon

omet

ric

Rat

ios

NA

ME

____

____

____

____

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____

____

____

____

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__D

ATE

____

____

____

PE

RIO

D__

___

11-7

11-7

©G

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3G

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Lesson 11-7

Pre-

Act

ivit

yH

ow a

re t

rigo

nom

etri

c ra

tios

use

d i

n s

urv

eyin

g?

Rea

d th

e in

trod

ucti

on t

o L

esso

n 11

-7 a

t th

e to

p of

pag

e 62

3 in

you

r te

xtbo

ok.

In w

hich

yea

rs w

ere

the

mea

sure

men

ts o

f th

e he

ight

of

Mt.

Eve

rest

incl

oses

t ag

reem

ent?

1954

and

199

9

Read

ing

the

Less

on

1.C

ompl

ete

each

sen

tenc

e.

a.T

he le

gs o

f tr

iang

le M

NR

are

segm

ents

an

d .

b.T

he h

ypot

enus

e of

tri

angl

e M

NR

is

.

c.T

he le

g op

posi

te "

Nis

,a

nd t

he le

g ad

jace

nt t

o "

Nis

.

d.T

he le

g op

posi

te "

Mis

,a

nd t

he le

g ad

jace

nt t

o "

Mis

.

2.W

rite

Kor

Sto

com

plet

e ea

ch e

quat

ion.

a.ta

n "

b.si

n "

c.si

n "

d.co

s "

e.co

s "

f.ta

n "

3.If

you

look

str

aigh

t in

fro

nt o

f yo

u an

d th

en u

p,th

e tw

o lin

es o

f si

ght

form

an

angl

e of

(dep

ress

ion/

elev

atio

n).I

f yo

u lo

ok s

trai

ght

in f

ront

of

you

and

then

dow

n,th

e tw

o lin

es o

f si

ght

form

an

angl

e of

(d

epre

ssio

n/el

evat

ion)

.

Hel

ping

You

Rem

embe

r

4.W

hat

is o

ne w

ay y

ou c

an r

emem

ber

the

trig

onom

etri

c ra

tios

sin

e,co

sine

,and

tan

gent

?

Sam

ple

answ

er:A

wel

l-kno

wn

mne

mon

ic d

evic

e is

SO

H-C

AH

-TO

A

(sin

%op

posi

te/h

ypot

enus

e,co

s %

adja

cent

/hyp

oten

use,

t an

%op

posi

te/a

djac

ent)

.

depr

essi

on

elev

atio

n

ST

$ KT

KK

T$ K

SK

ST

$ KS

SS

T$ K

SK

KT

$ KS

SK

T$ T

SS

K

S T

"MR

"NR

"NR

"MR

"MN

NR

MR

M

N R

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Mod

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The

pai

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g be

low

,apt

ly t

itle

d,“R

ight

Tri

angl

es,”

was

pai

nted

by

that

wel

l-kn

own

arti

st T

wo-

loos

e L

a-R

ecta

ngle

.Usi

ng t

he in

form

atio

nbe

low

,fin

d th

e di

men

sion

s of

thi

s m

aste

rpie

ce.(

Hin

t:T

he t

rian

gle

that

incl

udes

"F

is is

osce

les.

)

tan

A"

tan

B"

tan

C"

tan

D"

tan

E"

4ta

n F

"1

tan

G"

1.W

hat

is t

he le

ngth

of

the

pain

ting

?33

ft

2.W

hat

is t

he w

idth

of

the

pain

ting

?36

ft

1 $ 31 $ 2

1 $ 24 $ 5

2 $ 5

6 ft

B

A

G

C

D

F

E

En

rich

men

t

NA

ME

____

____

____

____

____

____

____

____

____

____

____

__D

ATE

____

____

____

PE

RIO

D__

___

11-7

11-7

Answers (Lesson 11-7)