assignment 8 math 2280

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Math 2280 - Assignment 8 Dylan Zwick Spring 2013 Section 5.4 - 1, 8, 15, 25, 33 Section 5.5 - 1, 7, 9, 18, 24 Section 5.6 - 1, 6, 10, 17, 19 1

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Math 2280 - Assignment 8

Dylan Zwick

Spring 2013

Section 5.4 - 1, 8, 15, 25, 33

Section 5.5 - 1, 7, 9, 18, 24

Section 5.6 - 1, 6, 10, 17, 19

1

Section 5.4 - Multiple Eigenvalue Solutions

5.4.1 - Find a general solution to the system of differential equations be‘ow.

The

I.-

(_(

Aje

I 1 / 1 J_ tooLH } - 0 0

/ ‘ICc) WoYK

Ix’=(l 4)x

a5 )7evq /tj:

(>3)2

I7eflv/ej-

C+Cj JcI10 )

il e ci’ e

(hct(Y

‘I

(4e yY/ O/f

\1)( )2

5.4.8 Find a general solution to the system of differential equations below.

/25 12 Ox’=f —18 —5 0 )x

\\ 6 6 13)

Z5 j o-y 0

6 lA

F$, /e; 7. 15 II

f / —7 Q elyekl ec7I

: ):)(-it)

0/

) 3 ‘‘ Ice e (7 eji ec/c1 5

IL Q

Kb) : 0

y e / 5c’ 10 I C)7 I

()7()e1frI3f

More room for Problem 5.4.8, if you need it.

4

1)

iD

-

—i

JC

cc—

—---

o-C

I(I

If)

IIIi

C-U

UoLID

CN

0

-dc

—II0

LrD

Lf

>c

—(T

hf-

0

_

I,.

-)

__

__

_

ii

__

__

__

__

U c

-

Th

5.4.25 - Find a general solution to the system of differential equations below. The eigenvalues of the matrix are given.

/ —2 17 4 \x’= f —1 6 1 ) x; A = 2.2.2.

0 1 2)

€ie cri

(7 L)

1 -1 b =(

I7QV(ec4cr4 ( )3 c) /ic(

2iVCd

Lj 1( H /1 H U to 00\ 0 C) -) c

7

c:—

c

I—

)

I

I

5.4.33 - The characteristic equation of the coefficient matrix A of the system

3 —4 1 043010 0 3 40043

is

= (A2 — 6.X + 25)2 = 0.

Therefore, A has the repeated complex conjugate pair 3+ 4i of eigenvalues. First show that the complex vectors

1 0i 010 10 i

form a length 2 chain {vi. v2} associated with the eigenvalue A =

3 — 4i. Then calculate the real and imaginary parts of the complex-valued solutions

v1e and (vitfv9)eAt

to find four independent real-valued solutions of x’ = Ax.

‘Note in the textbook there’s a typo in this vector.

9

C

i1’

___

__

__

:

—-

Lfl

-

E‘

D:5—

Zz

I

-

H

0)

(N NH

\f\

Nr

o0

1N

--

N

—0

‘-‘s

-_Z

(Th

tTj

‘sc;\

—J

0L

Ij

C

-Th

H

->c

4

Matrix Exponentials and Linear Systems

5.5.1 - Find a fundamental matrix for the system below, and then find asolution satisfying the given initial conditions.

2 ix’1 9)x. x(O)=(32).

1ve £ciI e ei7eyivci/j of fle

+j (A-i)(A-))I zf

\:

k1 eIj1vco( #cI iNI

- 1JL / / i)

P 7 a y e fl V c ic / t7

I9\ loI L b) ( d) ( i)

ye4 ‘c’ de4 Ic’ I& oJj:

(-;) e

(i (i))

e Ic aé,4q1 cify ( )12

>K(

CIi

CD C 0 C CD C CD CD

NJ

*

TU

I

cJI

L‘

—F)

I

__

JI

I

I—

cic

Ij

__

__

_

IIIi

____

c_t-

_t

(D

CI

I

0

__

__

__

II

II

UI

c

I(0 C

0

0I

N

SN

•___

(0 0)

—.

C

4

_

Th

I

I)

H

—fl

.

-

U

HS

I

—5

---

—5---

N—

5--—

—--

I—

.5

.-5_-

(—cr—

5-—

-—

---

(N.5

..)

____)

-

U.--

I—

5-------

IL

rN

More room for Problem 5.5.9, if you need it.

()D ((()

) 6) (e /

I! HI

4—

-7 +ZeC—C

17

1\

H

>

++

q)

-

so—

-Q__)

In0

cL4

Qj

.—

---

><1)

Qj

c_)

_•s

UzE0

—c:

UI

c4

LIcc

L

(c

RE

(-

C

N—

N

C

(I-S

C

N

0—

cr-

CI’

rr

Sn Sn

CD —o

CD

CD —I-.

çX

cJ)

— C CD CD CD I

\J

c.

1)

-4-

4

I’J

-

ccç

oc

(ThE

N

ç)

JTh

—I

-.-

j

More room for Problem 5.5.24, if you need it.

21

Nonhomogeneous Linear Systems

5.6.1 - Apply the method of undetermined coefficients to find a particularsolution to the system below.

= x + 2y + 3= 2x + y — 2

41 1

6 €

(::) 4J(

--

-

(

22

More room for Problem 5.6.1, if you need it.

/ (7)

23

II

1

_

*U

-d

(III

C

++

±

+1

—I---

—1---H

Ce,)

-_1

I.

Cl)ci)cL)

II

I-I

±Cl)

Lrj

0 0 0 0 0 rD (.31

0 (D

1/N

I’J

cii

-b

ç-i C

4.

•N

I

n.j

r-

aN

J1

N

fl

+CD -p

-4-

11W

CD

°

CD

I’3

CD

+n C CD CD -p

r

__

;

-t5C

_

-4

.,,

.----

C

,Jr’J

N

N

H

1JNH

I-

r-J

‘I

.—

y_

I’NI

_

rv.r’\)

(I

N

Ii

±

rI

N—

--

,

r-J

cJ

I’

1>c

1)

-J

H

ci

H CD

CD 0

><

CD

_

CD-I

-

0 CD

II

__

0I

IIT

h

_

II+

SS

. CDCD 0-p

iI

0

II

CDCD —

H

+-d

+U—

.C

J

‘N0

N1

I

c4

If)Ecj

I

c:r—(J\

000

0

Hii

a)

:--

-4-—

s

a)—

a)r—

J

-c1j

o+

+

LJ

a)q

)I

-J

cjr

a)

Ico

(U—

+-z

C?z

—çjC

\l

IIC

bC‘—

+..

Y;

cr-r—

JCU

_____1—ci)

r—J

CU-4

-•1

+

a)-

CII

c)0

0c:L

)

a)a)

I’

>a)

CUa)a)

a)I-4

H

L

(tA

More room for Problem 5.6.19, if you need it.

e 115lie

CIj 4I?

-ii- 7z4-f+

e (-7ie (e’J* L7)

Ie+ 5qz

-27 +Y?- 27

/Coi * f ?e

31