chapter 6. energy flows and balances

17
Dr. BUNRITH SENG Chapter 6 Energy Flows and Balances Mobile : +81 (0) 80 3259 9952 E-mail: [email protected]; [email protected] Department of Civil Engineering, Zaman University No. 8, St. 315, 12151 Phnom Penh, Cambodia Zaman University Department of Civil Engineering No. 8, St. 315, 12151 Phnom Penh, Cambodia

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Page 1: Chapter 6. Energy Flows and Balances

Dr. BUNRITH SENG

Chapter 6

Energy Flows and Balances

Mobile : +81 (0) 80 3259 9952

E-mail: [email protected]; [email protected]

Department of Civil Engineering, Zaman University

No. 8, St. 315, 12151 Phnom Penh, Cambodia

Zaman University Department of Civil Engineering

No. 8, St. 315, 12151 Phnom Penh, Cambodia

Page 2: Chapter 6. Energy Flows and Balances

2

Unit of Measure

Joule (J)

Calorie (Cal)

Kilowatt-hour (kWh)

Unit of Energy

Page 3: Chapter 6. Energy Flows and Balances

3

Energy Balances and Conversion

CONSUMED

energy

of Rate

PRODUCED

energy

of Rate

OUT

energy

of Rate

IN

energy

of Rate

DACCUMULATE

energy

of Rate

Energy Balance Equation

At Steady State

OUT

energy of Rate

IN

energy of Rate

Page 4: Chapter 6. Energy Flows and Balances

4

Energy Balances and Conversion (Cont.)

OUT

energy wasted

of Rate

OUT

energy useful

of Rate

IN

energy

of Rate

Energy out has two terms; energy wasted in the conversion and useful energy.

Efficiency

100INEnergy

OUTenergy Useful (%) Efficiency

Page 5: Chapter 6. Energy Flows and Balances

5

Example: A coal-fired power plant uses 1000 Mg of coal per day. The energy value of the coal is 28,000 kJ/kg. The plant produces 2.8106 kWh of electricity each day. What is the efficiency of the power plant?

Solution:

Energy IN = (28,000 kJ/kg) (1000Mg/d) (1000 kg/Mg)

36% 100kJ/d1028

kJ/d1010.1 (%) Efficiency

9

9

A CMF reactor would require 44% more volume than a PFR

Energy Balances and Conversion (Cont.)

= 28109 kJ/d

Useful energy output = (2.8106 kWh/d)(3.6106 J/kWh)(10-3 kJ/J)

= 10.1109 kJ/d

Page 6: Chapter 6. Energy Flows and Balances

6

Energy Balances and Conversion (Cont.)

Simplified drawing of a bomb calorimeter

Bomb Calorimeter

Results of a bomb calorimeter test

Note: 1 cal is defined as the amount of energy necessary to raise the temperature of 1g of water 1oC.

Page 7: Chapter 6. Energy Flows and Balances

7

Bomb Calorimeter at ITC

Energy Balances and Conversion (Cont.)

Page 8: Chapter 6. Energy Flows and Balances

8

Example: A calorimeter holds 4L of water. Ignition of a 10g sample of a waste-derived fuel of unknown energy value yields a temperature rise of 12.5oC. What is the energy value of this fuel? Ignore the mass of the bomb.

Solution:

Energy Balances and Conversion (Cont.)

OUTEnergy INEnergy

Tm OH2S OUTEnergy

TV .J/g.K 4.184 OUTEnergy

C)mL/L)(12.5 (4L)(10g/mL 1J/g.K 4.184 OUTEnergy o3

J 10209OUTEnergy INEnergy 3

J/g 900,20 10J/10290 fuel theof ueEnergy val 3 g

Page 9: Chapter 6. Energy Flows and Balances

9

Heat Energy

Energy Balances and Conversion (Cont.)

material theof

eTemperatur Absolute

material

of Mass

Energy

Heat

Heat Energy Balance

CONSUMED

energy

Heat

PRODUCED

energy

Heat

OUT

energy

Heat

IN

energy

Heat

DACCUMULATE

energy

Heat

At Steady state

00

OUT

energy

Heat

IN

energy

Heat

0

00TT 0 332211 outin

QQTQOr

Page 10: Chapter 6. Energy Flows and Balances

10

Energy Balances and Conversion (Cont.)

Example: A coal-fired power plant discharges 3 m3/s of cooling water at 80 oC into a river that has a flow of 15 m3/s and a temperature of 20 oC. What will be the temperature in the river immediately below the discharge?

Solution:

00TT 0 332211 outin

QQTQ

3

22113

Q

QTQTT

K 303/ 153

/m 1527320/m 3273803

33

3

sm

sKsKT

C30 be r willriver wate theof re temperatuThe o

Page 11: Chapter 6. Energy Flows and Balances

11

Energy Sources

Renewable Energy

Hydropower from rivers

Hydropower from tidal estuaries

Solar power

Refuse and other waste materials

Wind

Wood and other biomass, such as sugarcane and rice hulls

Nonrenewable Energy

Nuclear power

Coal, peat, and similar materials

Natural gas

Oil

Page 12: Chapter 6. Energy Flows and Balances

12

Energy Sources (Cont.)

Energy Flow in the United States

Page 13: Chapter 6. Energy Flows and Balances

13

Energy Equivalence

There are two important distinct energy equivalences:

Arithmetic energy equivalence

Conversion energy equivalence

Example: What are the arithmetic and conversion energy equivalents between gasoline (20,000 kJ/kg) and refuse-derived fuel (5,000 kJ/kg)?

Solution:

refuse kJ/kg 5,000

gasoline kJ/kg 20,000 eequivalencenergy Arithmetic

gasoline kg refuse/1 kg 4

Page 14: Chapter 6. Energy Flows and Balances

14

Solution:

refuse kJ/kg 2,500

gasoline kJ/kg 20,000 eequivalencenergy Conversion

gasoline kg refuse/1 kg 8

Energy Equivalence (Cont.)

But the processing of refuse to make the fuel also requires energy. This can be estimated at perhaps 50% of the refuse-derived fuel energy, so the actual net energy in the refuse is 2,500 kJ/kg. Therefore,

Page 15: Chapter 6. Energy Flows and Balances

15

Electric Power Production

Simplified drawing of a coal-fired power plant

Coal-fired Power plant

Page 16: Chapter 6. Energy Flows and Balances

16

OUT

energy wasted

of Rate

OUT

energy useful

of Rate

IN

energy

of Rate

DACCUMULATE

energy

of Rate

Electric Power Production (Cont.)

WU QQQ 00

Where, Q0 = energy flow into the black box QU = useful energy out of the black box QW = wasted energy out of the black box

Efficiency

100Q

Q(%) Efficiency

W

U

Page 17: Chapter 6. Energy Flows and Balances