nctm2011 afternoon session

18
SINGAPORE MATH Bar Model Method Dr Yeap Ban Har Marshall Cavendish Institute Singapore [email protected] Slides are available at www.banhar.blogspot.com Indianapolis Convention Center

Upload: jimmy-keng

Post on 06-Jul-2015

897 views

Category:

Education


0 download

DESCRIPTION

This session focuses on the use of the bar model to solve a range of problems. The presenter modelled a range of teacher behaviour to help students acquire the competencies that they are supposed to by engaging in word problems. It was presented at the Indianapolis conference. We hope not too many people were not able to get a seat at the session. If you were not able to gain entry to the session, please accept our apologies.

TRANSCRIPT

Page 1: NCTM2011 Afternoon Session

SINGAPORE MATHBar Model Method

Dr Yeap Ban HarMarshall Cavendish Institute

Singapore

[email protected]

Slides are available at www.banhar.blogspot.com

Ind

ian

apo

lis C

on

ven

tio

n C

en

ter

Page 2: NCTM2011 Afternoon Session

MCI-WSU Singapore Math Summer Institute 6 – 8 July 2011

Comprehensive program taught collaboratively by Singapore mathematics educators and

WSU’s professors.

Page 3: NCTM2011 Afternoon Session
Page 4: NCTM2011 Afternoon Session

The Curriculum (Ministry of Education 2006)

Page 5: NCTM2011 Afternoon Session

Kyla

Jake $9

$28

?

?$28 – $9 = $19

Kyla has $19.

Page 6: NCTM2011 Afternoon Session

Ming

Naomi

48

48 ÷ 4 = 12

Ming has 36 candies.

3 x 12 = 36

Page 7: NCTM2011 Afternoon Session

apples

15

3 units 1518 units 6 x 15 = 90

There are 90 fruits in the basket.

Page 8: NCTM2011 Afternoon Session

Method 13 units 15

18 units 6 x 15 = 60 + 30 = 90

Method 23 units 151 unit 5

18 units 18 x 5 = 50 + 40 = 90

18 units 6 x 15 = 3 x 30 = 90

18 units 18 x 5 = 180 ÷ 2 = 90

Page 9: NCTM2011 Afternoon Session

QuestionWhat if the fraction is such it is not easy to split the remainder part?

See the example presented in the morning session.

Page 10: NCTM2011 Afternoon Session

Allan spent ¼ of his allowance on a gift and ¼ ofthe remainder on a book. The book cost $18.Find the amount of Allan’s allowance.

4 x $18 = $72

$72 ÷ 3 = $24 Allan’s allowance = 4 x $24 = $96

Page 11: NCTM2011 Afternoon Session

Mon

Tue $3

Wed $3 $3

Thu $3 $3 $3

$100

$100 – 6 x $3 = $82

$82 ÷ 4 = $20.50

$20.50 + 3 x $3 = $29.50

She saved $29.50 on Thursday.

Page 12: NCTM2011 Afternoon Session

adults

children

2 units 380 – 260 = 120 1 unit 60

260 – 60 = 200200 + 200 = 400 400 people left at lunchtime.

Page 13: NCTM2011 Afternoon Session

apples

oranges 90

pears 15

38

Page 14: NCTM2011 Afternoon Session

apples

oranges 90

pears 15 23

Page 15: NCTM2011 Afternoon Session

apples

oranges ?

pears 15

90 + 15 = 1055 units

1 unit 105 ÷ 5 = 21

23

There were (21 + 21 + 23) apples, hence oranges.

There were 44 oranges used.

Page 16: NCTM2011 Afternoon Session

Extra ProblemFor you to try. Do not peek at the answer before you try it!

Page 17: NCTM2011 Afternoon Session

342

18%

24%

76%

76% 342

1% 4.5

100% 450

Mr Wong had 450 books at first.

Page 18: NCTM2011 Afternoon Session

MCI-WSU Singapore Math Summer Institute 6 – 8 July 2011

Comprehensive program taught collaboratively by Singapore mathematics educators and

WSU’s professors.