sat problem of the day:

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SAT Problem of the day: The graph of a quadratic function y is shown. For what value of x does y attain its greatest value? y = – x 2 + 6x – 3 Applications of the Vertex Formula Objective (4.3): Develop and apply a method for finding the maximum height of a projectile. (a) 0.5 (b) 3 (c) 5.5 (d) 6 (e) 8

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Applications of the Vertex Formula. Objective (4.3 ): Develop and apply a method for finding the maximum height of a projectile. SAT Problem of the day: The graph of a quadratic function y is shown. For what value of x does y attain its greatest value?. y = – x 2 + 6x – 3. - PowerPoint PPT Presentation

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Page 1: SAT Problem of the day:

SAT Problem of the day: The graph of a quadratic function y is shown. For what value of x does y attain its greatest value?

y = – x2 + 6x – 3

Applications of the Vertex FormulaObjective (4.3): Develop and apply a method for finding the maximum height of a projectile.

(a) 0.5(b) 3(c) 5.5(d) 6 (e) 8

Page 2: SAT Problem of the day:

• A projectile is an object in which the only force acting upon it is gravity.

Vocabularyre-visited

• A parabola is the graph of a quadratic function.

Page 3: SAT Problem of the day:

Which of the following would NOT be considered a projectile?

(a) Dropping a pumpkin off of a building.

(b) A plane taking off and then landing.

(c) Driving a golf ball.

(d) A person jumping on trampoline.

(b) A plane taking off and then landing.

Page 4: SAT Problem of the day:

Vertex

Vertex

The vertex of a parabola is either the lowest point on the graph or the highest point on the graph.

book page 276

Page 5: SAT Problem of the day:

minimum

maximum

When a parabola opens up and the vertexis the lowest point the y-coordinate of thevertex is the minimum.

When a parabola opens down and thevertex is the highest point the y-coordinateof the vertex is the maximum.

book page 277

Page 6: SAT Problem of the day:

When a parabola opens up its lowest point is known as the:

(a) minimum(b) maximum(c) vertex(d) a & c(e) b & c(f) all of the above

(d) a & c

Page 7: SAT Problem of the day:

To help identify the vertex of a quadratic function we can use the following formula:

– b2a x

=

Page 8: SAT Problem of the day:

Where do we see quadratic functions in our everyday lives?

pollanywhere.com

Page 9: SAT Problem of the day:

Where do we see quadratic functions in real life?

Page 10: SAT Problem of the day:

What component do we often neglect when applying formulas for projectile motion?

(a) initial height(b) initial velocity(c) height(d) air resistance(e) velocity(d) air resistance

Page 11: SAT Problem of the day:

Consider a firework display.

Page 12: SAT Problem of the day:

Collins Writing Type I: When a projectile is released into the air a number of factors come into play including initial height, maximum height, time, and velocity. If you were designing a firework display why do you think each of these factors would be important?

Time: 90 seconds Length: 3 Lines

http://www.online-stopwatch.com/large-stopwatch/

Page 13: SAT Problem of the day:

h = –16t2 + v0t + h0

hh0

tv0

Initial Height

Height

Time

Initial Velocity (or speed)

Term used to represent the

earth’s gravity.

When a projectile is released into the air, what types of factors come into play?

Page 14: SAT Problem of the day:

The path of a firework can be modeled using a quadratic function

h = –16t2 + v0t + h0

– b2a t

=

We can use the vertex formula to determine the time it takes for a firework to explode, and the maximum height that it reaches.

Page 15: SAT Problem of the day:

On July 4th Ocean City has a firework display. The fireworks are ignited from the football field with an initial velocity of 96 feet per second. How long does it take for the fireworks to reach their maximum height? What is the maximum height reached by the fireworks?

initial velocity of 96How long

maximum height

h = –16t2 + v0t + h0

– b2a

t =

the football field

Page 16: SAT Problem of the day:

A professional pyro-technician shoots fireworks vertically into the air off of a building that is 80 feet tall. The initial velocity of the firework is 64 feet per second. When will the fireworks reach their maximum height? What is the maximum height reached by the fireworks?

initial velocityWhen

maximum height h = –16t2 + v0t + h0

– b2a

t =

64 feet per second

Projectile MotionA.asf

80 feet tall

Page 17: SAT Problem of the day:
Page 18: SAT Problem of the day:

Textbook page 313Numbers 49 & 50

Page 19: SAT Problem of the day:

A baseball is thrown upward with an initial velocity of 48 feet per second from 6 feet above the ground. Determine the maximum height of the ball.

initial velocity

maximum height

h = –16t2 + v0t + h0

– b2a

t =

6 feet above the groundof 48 feet per second

Page 20: SAT Problem of the day:

EXIT TICKET

– b2a t

= h = –16t2 + v0t + h0