fluids case study on head loss
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ME 320 Case Study:
Pressure Losses Across Evaporators
Abstract
The question of whether or not the entrance length of a flow through a pipe
will be answered using experimental data taken from fluid flow through an
evaporator. Flow through a pipe is known to have two regions, an entrance region
and a fully developed region. Through the two parts of this report, the significance
of the entrance region will be put into question and it’ll be proven whether not a
fully developed approximation can be made. This will be done by tabulating
pressure losses in the different regions of the experimental flow and compared to
one another. An important result of this experiment is the predicted values of the
pressure loss in the different regions of the experimented flows and the comparison
of the approximations made during the analysis. At the conclusion of this report, it
will be proven that for the flows done in this experiment, the error made while
making a fully developed approximation is not significant enough to warrant a
reason for the analysis to be redone to include the entrance length, especially in
laminar flows.
Introduction
An evaporator is a heat exchanger in which a refrigerant liquid enters at low
pressure and temperature (relative to atmospheric) and leaves as a vapor. During
the vaporization process, the refrigerant "boils," absorbing energy from the
refrigerated space surrounding the evaporator, and everything within. The fluid
within the refrigerated space, typically air or water, is forced over the exterior sides
of the lateral tubes of the heat exchanger containing a volatile refrigerant (e.g.,
R134a is used in automobile cooling systems). Heat energy from the air/water flow
enters the lateral tubes of the heat exchanger by convection, and then is conducted
through the tube walls and into the refrigerant (again by convection.) The
schematic diagram in Fig 1 shows the geometry and the flow directions of the two
fluids in the evaporator under analysis.
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If the refrigerant is in a saturated state and sufficient latent heat enters the
refrigerant, it changes phase (i.e., it “evaporates”). The “top dividing header” in an
evaporator distributes the liquid refrigerant to the lateral tubes and the “bottom
combining header” collects the vaporized refrigerant, ultimately to be condensed
again in a condenser later in the cycle. Each lateral tube has 11 channels that the
liquid flows through. In this case study you shall analyze the pressure drop from the
inlet to the outlet of a single lateral tube due to a liquid water flow that does not
change phase. The data were collected by Habte [ref. 4] as a preliminary analysis of
two-phase pressure drop in the full evaporator [5].
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Setup, Data, and Methods of Analysis
The overall pressure drop across the evaporator is important to the overall
performance of the heat exchanger and will affect the choice of other components
in the system, such as the compressor. Although the overall pressure drop is the
sum of that within the two headers plus that within the lateral tubes, the greatest
contribution is in the pressure drop across each lateral tube in the evaporator. In
the experiment the pressure drop across a single lateral tube measured due to the
flow of liquid water at room temperature will be analyzed. The tests were conducted
with the procedure below. The tests were performed on a single aluminum flat tube
with 11 channels. The channel length was .6096 m, and because the tubes were
new and smooth when the tests were performed, roughness effects were negligible.
All data was collected at room temperature, about 20C. The two ends of the flat
tube were connected to plenum chambers each of which was connected to a
flexible hose. The two plenum chambers were connected to different sides of a
differential pressure gage that measures the pressure difference between the inlet
and outlet of the flat tube, P1 - P2. A variable-area flow meter was used to measure
the flow rate of water Q into the lateral tube. The flow rate of water through the
tube was set by adjusting the valve at the inlet to the test section. The variable area
flow meter (commonly known as a "rotameter") was calibrated before the test was
conducted to minimize error. The pressure drop measured with the differential
pressure gage was recorded for each fixed flow rate and the measurements were
repeated for different flow rates with the same tube geometry. Several
measurements were made at each flow rate and the pressure drops averaged to
improve accuracy.
The analysis will be in two parts. In the first part the head loss will be
evaluated experimentally and compare with standard engineering correlations by
approximating the flow as fully developed throughout the lateral tube. Recognizing
that there exists an entrance length, in the second part an analysis to estimate the
error introduced by the fully developed approximation made in part one will be
done and explained [5].
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Analysis and Results
Part I: Analysis of the Pressure Drop Using the Full-Developed
Approximation
Part I (a)
The “effective diameter” for the noncircular pipes that reduce to the circular
pipe diameter when the cross-section is circular needs to be determined so that the
correlations from data generated for circular pipes can be used. The given geometry
given for the channels in the flat tubes of the evaporator is the width, a, is .0018 m
and the height, b, is .001 m. The “effective diameter,” can be interpreted as the
hydraulic diameter, DH. The equation for the hydraulic diameter is
DH=4Acp 1
where Ac is the cross-sectional area and p is the wetted perimeter. When the
dimensions of the channels are put into equation (1), the hydraulic diameter is
found to be .001286 m.
The Reynolds number is defined as the ratio of inertial forces to viscous
forces in the fluid. The equation to tabulate Reynolds number for a non-circular pipe
is
Re=ρVDHμ (2)
where ρ is the fluid density, µ is the fluid viscosity and Vavg is the average flow
velocity. For equation (2), ρ and µ was found for water at room temperature, 998.3
kg/m3 and .001003 kg/m*s respectively. The average velocity for each flow in the
data was found by using the equation
V=QAc (3)
where Q is the experimental flow rate and Ac is the cross sectional area of a
channel. The cross sectional area used in equation (3) was found to be .0000018
m2. The flow rate was divided by 11 to accommodate the 11 channels per tube that
the flow was going through. The tabulated Reynolds number is shown in Table 1.
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Q volume flow rate[gal/hr]
P1 - P2 Pressure drop[psi] Q (m3/s)
Velocity(m/s) Re
1.0 0.075 9.63365E-08 0.053520295 68.50458
2.0 0.08 1.92597E-07 0.106998265 136.955
3.0 0.15 2.88857E-07 0.160476234 205.4054
4.0 0.325 3.85118E-07 0.213954203 273.8558
5.0 0.4 4.81378E-07 0.267432173 342.3062
6.0 0.525 5.77638E-07 0.320910142 410.75667.0 0.625 6.73899E-07 0.374388112 479.207
9.5 0.85 9.06778E-07 0.503765659 644.8069
12.5 1.23 1.19671E-06 0.664836842 850.9738
15.6 1.675 1.48663E-06 0.825908025 1057.141
18.6 1.8 1.77656E-06 0.986979208 1263.308
21.6 2.15 2.06649E-06 1.148050391 1469.475
24.7 2.6 2.35642E-06 1.309121574 1675.641
26.2 2.9 2.50138E-06 1.389657165 1778.725
27.7 2.95 2.64635E-06 1.470192757 1881.808
30.7 3.6 2.93628E-06 1.63126394 2087.975
33.8 4.2 3.2262E-06 1.792335123 2294.142
35.3 4.65 3.37117E-06 1.872870715 2397.22636.8 5.1 3.51613E-06 1.953406306 2500.309
Table 1. Given data with calculated average velocity and Reynolds number
Part I (b)
When a fluid is flowing through a pipe, there will be a few pressure losses
that the flow will induce across the length of the pipe. There will be both major and
minor head losses. The major head loss will either be laminar, transitional, or
turbulent depending on the Reynolds number and the critical Reynolds number for
the given pipe. The critical Reynolds number for the noncircular pipe is still
unknown in this experiment, so the laminar and turbulent head losses will be
tabulated for all flows. The equation for major head loss is
hf,maj=fLV22gDH 4
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where f is the friction coefficient and L is the length of the pipe. For equation (4) the
length of the pipe is given as .6096 m. The friction coefficients for laminar and
turbulent flows are different. For laminar flow, the friction coefficient equation is
f=61.144Re (5)
The friction coefficient for turbulent flows can be found using the explicit form of
the Colebrook equation, which is
1f=-1.8log6.9Re+εDH3.71.11 6
where ε is the roughness factor. For equation (5) the roughness factor is zero
because the pipes are assumed to be smooth. When the friction coefficients are
found, they can be plugged back into equation (4) to find the major head losses for
each flow. The equation for the minor head loss in the flow is
hf,min=KLV22g 7
where K L is the loss coefficient. The loss coefficient for laminar and turbulent flows
can be tabulated by using Table 8-4 in Cengel and Cimbala [1]. The loss coefficient
is the sum of the coefficients acting on the flow. In our case the loss coefficient for
the entrance is 0.5 and for the exit it’s 1 per the write-up, so our total loss
coefficient is 1.5. Once we have the head losses tabulated, the total pressure loss
can be predicted. The equation for total pressure loss is
∆PL=ρghf 8
where ΔPL is the pressure loss. Major and minor total pressure losses can be
calculated by plugging the respected head loss into equation (8). Table 2 shows the
calculated major head losses (laminar and turbulent) and the total pressure losses
(laminar and turbulent). Also table 2 shows the calculated friction coefficients for
each flow. Table 3 shows the calculated minor losses for each flow. Since critical
Reynolds number is still unknown at this point, both laminar and turbulent losses
are found for each flow.
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f lam hf,lam ΔPlam (Pa) f turb hf,turb ΔPturb (Pa)
0.892553 0.061769804 604.9316461 0.310583 0.021494 210.4987649
0.446453 0.123490759 1209.384892 0.183268 0.050693 496.4501777
0.297675 0.185211714 1813.838137 0.142102 0.088415 865.8773078
0.223271 0.246932669 2418.291383 0.120764 0.133562 1308.01435
0.178624 0.308653623 3022.744629 0.107356 0.185506 1816.720563
0.148857 0.370374578 3627.197874 0.097991 0.243815 2387.754588
0.127594 0.432095533 4231.65112 0.090997 0.308162 3017.926161
0.094825 0.581415071 5693.985589 0.079482 0.487336 4772.641107
0.071852 0.767313438 7514.548344 0.070586 0.753797 7382.173957
0.057839 0.953211806 9335.111099 0.064631 1.065142 10431.28409
0.0484 1.139110173 11155.67385 0.060286 1.418853 13895.28492
0.041609 1.32500854 12976.23661 0.056934 1.813006 17755.35021
0.03649 1.510906907 14796.79936 0.054245 2.246065 21996.43743
0.034375 1.603856091 15707.08074 0.053084 2.47678 24255.90184
0.032492 1.696805274 16617.36212 0.052023 2.716762 26606.126
0.029284 1.882703641 18437.92487 0.050147 3.224024 31573.90684
0.026652 2.068602009 20258.48763 0.048534 3.766926 36890.71851
0.025506 2.161551192 21168.76901 0.047807 4.051484 39677.49479
0.024455 2.254500376 22079.05038 0.047127 4.344657 42548.62932
Table 2. Major Pressure Losses
ΔPminor 2.144664
48.571874
519.28163
234.27393
653.54878
777.10618
6104.9461
3190.0113
1330.9424
6510.7233
4729.3539
5
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986.83431283.164
41445.898
11618.344
21992.3737
2405.2532626.261
3
2856.982
Table 3. Minor Pressure Losses
Part I (c)
Figure 3. Pressure Losses vs. Flow Rate
Figure 3 shows the predicted the pressure losses (laminar and turbulent)
versus the flow rate for each flow. Also in this plot, the real data is plotted against
the predictions. The flow in the pipe is being considered as fully developed for this
portion, so error is seen within the graph.
Figure 4. Pressure Losses vs. Reynolds Number
In figure 4, the real data follows the predicted data fairly well given the fact
the entrance length of the flow has been ignored. Figure 2 shows that the major
pressure losses increase with the Reynolds Number. This is due to the fact that the
major pressure losses are dependent of Reynolds number. As the velocity increases,
the inertial forces increase, leading to an increasing Reynolds number, thus leading
to higher major pressure losses. From figure 2, the critical Reynolds number for the
noncircular pipes used in this experiment can be estimated. With this given plot, a
critical Reynolds number is estimated to be approximately between 1000 and 1500.
From this plot, it’s not fully clear where the flow laminar or turbulent, so this range
is the best estimate that can be made. For flows under this critical number, the flow
will be seen as fully laminar. For flows over the critical Reynolds number, the flow
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will be fully turbulent. For flows in between these two Reynolds number, the flow
will be seen as transitional. The predicted values for the critical Reynolds numbers
are far less than that of circular pipes, which has a critical Reynolds number of
about 2300. This can be explained with the difference in the geometry of the pipes.
The fluid flowing through a noncircular pipe will have more surface area to “stick to”
(viscous forces) versus when it’s flowing through a circular pipe. The corners of the
noncircular pipe also add to the viscous affects because the flow cannot flow
smoothly through the pipe as to when there are no corners. In the fully developed
region of a flow, the velocity profile is assumed to be nearly parabolic. When in a
pipe with corners, the flow regions near the walls of the pipe are affected by the
corners, which explains the lower critical Reynolds number.
Part I (d)
Figure 5. Minor Pressure Losses Divided by Total Pressure Losses vs. Flow
Rate
Figure 5 shows the relative contribution of the theoretical minor loss
contribution to total pressure drop versus the flow rate. This ratio is found for both
the laminar and turbulent theoretical pressure losses. This plot shows that the ratio
of minor loss to total pressure loss in laminar flows increase more with flow rate
versus the ratio with turbulent pressure loss. This is because the velocity in the
turbulent flows is higher than that in laminar flows. The minor loss is low, but should
not be neglected in analysis because it does contribute to the pressure loss of the
flow. From this plot our estimate of critical Reynolds number made in part (c) is the
same.
Part I (e)
Once we have calculated the minor pressure losses for the flows, the
experimental pressure loss can be separated into major and minor pressure losses.
Once we have the experimental major pressure loss, the experimental friction
coefficient can be calculated.
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fexp=∆Pmaj2DH3ρLμ2Re2 9
ΔPmaj f exp
514.9621324
0.7598069
543.008708
7
0.200455
61014.93196
20.166563
72206.52218
3 0.2037192704.35412
9 0.1598093542.64139
10.145386
94204.27717
50.126768
75670.53238
70.094434
7
8149.609007 0.077924111037.9951
20.068389
911681.2091
7 0.0506813836.8938
70.044369
216643.2045
80.041043
318548.8980
80.040594
518721.1898
20.036605
822828.7525
20.036257
626552.7276
2 0.03493329434.3601
10.035465
332306.2801
70.035782
2
Table 4. Experimental Major Pressure Loss and Friction Coefficient
Table 4 shows the tabulated experimental pressure losses and the experimental
friction coefficients using equation (9).
Figure 6. Friction Coefficient versus Reynolds Number (linear-linear)
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Figure 7. Friction Coefficient versus Reynolds Number (log-log)
Figures 6 and 7 show the different friction coefficients (laminar, turbulent, and
experimental) versus the Reynolds number. The data points follow the same trend
as the Moody curves with fluctuations. The fluctuations in the data curve show uswhere the flow is laminar, transitional, and turbulent. With the help of these two
plots it’s easier to estimate Reynolds number from the data against the Moody
curves. From these plots, a critical Reynolds number is estimated to be 1300, which
is in our range of 1000-1500 made in part (c).
Part II: Estimating Accuracy of the “Fully Developed
Approximation.”
Part II (a)
In actual pipe flow, the flow is not fully developed for the whole length of the
pipe. There is an entrance length from the entrance to a certain length where the
flow has an increasing boundary layer which merges at the end of the entrance
length. The equation for the entrance length is
Le=.05ReDH (10)
Le,lam Le/L0.004404844
0.00722579
0.008806205
0.01444588
0.013207566
0.02166596
0.017608927
0.02888604
0.022010288
0.03610612
0.026411649 0.0433262
0.030813010.0505462
80.04146108
30.0680135
90.05471761
50.0897598
70.06797414
70.1115061
50.08123067
90.1332524
3
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Table 5. Entrance Length for Laminar Flows
Table 5 shows the calculated entrance lengths and the ratio of the entrance
length to the whole length of the pipe for the laminar flows. This table shows that
the entrance length is much smaller compared to the entire length of the part, but
no real conclusions can be made yet about whether or not the entrance length can
be neglected or not.
Part II (b)
The flow at the inlet of the pipe is nearly uniform, so it is reasonable to say
that the peak velocity is approximately equal to the average velocity. This
approximation cannot be made at all other locations in the pipe because the peak
velocity exceeds the average velocity.
Velocity profile is given by:
ur= -R24µdPdx1- r2R2 (11)
The average velocity is given by:
V= -R28µdPdx (12)
Combining equation (11) and (12) gives:
ur=2V1- r2R2 (13)
For u (0), we have peak velocity. So,
Vpeak=2V (14)
Therefore, from equation (14) we can say that the average velocity in fully
developed laminar pipe flow is one half of the peak velocity. The average velocity is
the same at all axial locations x in the channel because the velocity profile no
longer depends on x in the fully developed region. When the boundary layers merge
at the end of the entrance region, the velocity profile for the rest of the flow is
parabolic to the outlet. In the fully developed region, the velocity is dependent of r
and x, r being the distance from the center of the pipe to the boundary layer. In the
fully developed region, the boundary no longer exists or in other words the walls of
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the pipe become the boundary layer, thus the flow is constant in the fully developed
region.
Part II (c)
The Bernoulli equation is applicable on the streamline between the inlet and
the end of the entrance length because in this region the net viscous or frictional
forces are negligible compared to other forces acting on the fluid particles.
Pρ+V22+gz=constant 15
Equation (15) is the derived form of the Bernoulli equation. Since the Bernoulli
equation is applicable to the entrance length region of the flow, this equation can
be used to estimate ΔP1, which is defined as ΔP1=P1-Pe, as a function of the average
velocity. Pe is the pressure at the end of the entrance region, which will be called
point e and point 1 is the inlet of the pipe. The Bernoulli equation can be used to
estimate ΔP by setting the equation (15) for point 1 and point e equal to each other.
∆P1=ρ2Ve2-V12+ρgze-z1 (16)
After some manipulation, equation (16) will emerge. In this equation, both z terms
will be zero because we are using fluid particles along the streamline in the center
of the flow, so ze-z1 will equal zero. Using the approximations that V1 can be
approximated as the average velocity and that Ve=2Vavg, plugging these into
equation (16) would yield
∆P1=32ρV2 17
Equation (17) can be used to solve for the change in pressure in the entrance
region. Table 6 shows the tabulated changes in pressure in the entrance region for
the laminar flows.
ΔP1
4.289329
17.14375
38.56326
68.54787
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107.0976
154.2124
209.8923
380.0226
661.8849
1021.447
1458.708
Table 6. Change in Pressure in Entrance Region
Part II (d)
The pressure loss for the fully developed region, ΔP2 is defined as Pe-P2, where
P2 is the pressure at the outlet. For the change in pressure in the fully developed
region, the Bernoulli equation is not applicable because the viscous effects of the
flow are not negligible.
∆P2=fLFDDHρV22 18
In equation (18), f is the experimental friction coefficient found in Part I (e) and LFD is
the total length of the pipe minus the entrance length. The change in pressure when
the entrance is ignored and the flow is assumed to be fully developed, ΔPFD, is thechange in pressure found using equations (4), (5), and (6) (laminar flows).
∆PFD=fLDHρV22 (19)
In equation (19) the f is the friction coefficient found using equation (5) for laminar
flows and L is the total length of the pipe.
L-L(entr) ΔP2 ΔPFD0.60519
5600.560
5604.931
60.60079
41191.91
41209.38
50.59639
2 1774.541813.83
8
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0.591991
2348.437
2418.291
0.587592913.60
53022.74
50.58318
83470.04
53627.19
80.57878
74017.75
74231.65
10.56813
95306.71
75693.98
60.55488
26840.04
37514.54
80.54162
68294.18
99335.11
10.52836
99669.15
311155.6
7
Table 7. Length and Change in Pressure of Fully Developed Region after entranceregion and Change of Pressure if Whole Flow is Considered Fully Developed.
Table 7 shows the tabulated values of the length of the fully developed region after
the entrance length. This length is used to tabulate the change in pressure of the
fully developed region after the entrance length. Table 6 also shows the change in
pressure if the whole flow is considered fully developed, which is the change in
pressure for the fully developed region for laminar flows found in part I (b).
Part II (e)
With all the changes of pressure tabulated the percent error from part I can
be calculated using
ε=∆PFD∆P1+∆P2-1 20
Equation (20) can be manipulated to show the mathematical relationship between
the percent error and Reynolds number.
ε=fLDH3+fL-LeDH-1 21
In equation (21) the friction coefficient is a function of Reynolds number, which
shows the relationship of the error and Reynolds number. For equation (21) thefriction coefficient is the one predicted for laminar flow. This equation shows that
error will increase linearly with Reynolds number.
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% Error 0.14873
4
0.297390.44608
6
0.594823
0.74360.89241
71.04127
41.40156
61.85044
92.29969
72.74931
2
Table 8. Percent Errors
Equation (21) calculates the error that is made by assuming that the flow through a
pipe is fully developed through the whole flow. The error calculated in equation (21)
is the error in one channel of the flow, so the error is multiplied by 11 to calculate
the error in the whole pipe. Table 8 shows the tabulated percent errors from the
fully developed approximation of part I. The percent error is found by multiplying
equation (21) by 100.
Figure 8. % Error of Making the Fully Developed Approximation versus the
Reynolds Number
Figure 8 shows the error from the fully developed approximation plotted against the
Reynolds number. The plot shows that percent error increases linearly with
Reynolds number, which is expected from equation (17). The calculated error shows
that the error made from the fully developed approximation is laminar flow is
insignificant. The analysis made in part I will not have to be redone when the
Reynolds number is below the critical value because the error is minimal.
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Part II (f)
The relative error for a flow that is turbulent will be less compared to that of
laminar flow. In a fully turbulent flow, the boundary layers in the entrance region
will merge quicker than that of a laminar flow. The shorter entrance region will leadto the flow to more like a fully developed region, so making a fully developed
approximation will result in less of an error in turbulent flows.
Discussion and Summary
Things learned through this analysis:
• The flow through a noncircular pipe and a circular pipe is affected by the
different geometries. Also the circular pipe correlations can be used for
noncircular pipe flow after making a few approximations.
• The critical Reynolds number of a noncircular pipe was found to be about half
of that of a circular pipe. This was concluded after determining the predicted
values of major and minor pressure losses through the flow of the noncircular
pipes used in the experiment. This was explained by the fact that the flow
cannot flow smoothly through the noncircular pipes because of the geometry,
namely the corners.
• Making a fully developed approximation in laminar flows result in an
insignificant error when compared to the analysis done with the inclusion of
the entrance region. In turbulent flows, this error becomes even more
insignificant because the rate at which the boundary layers in the entrance
region will merge.
To reduce pressure loss while maximizing the aspect ratio of each lateral
tube, the length of the pipe or the flow rate can be reduced. The major pressure
loss is dependent on both of these things, so reducing them will reduce the overall
pressure loss. Also rounding the edges at the inlet and outlet of the pipe would
reduce the minor pressure loss of the flow, further reducing the pressure loss. Also
if the number of channels is reduced, this would lead to an increase in the effective
diameter, which would decrease the pressure loss.
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References
1. Cengel, Y & Cimbala, J.M. 2006 Fluid Mechanics, McGraw-Hill, New York, NY
2. Cengel, Y.A., Boles, M.A. (year) Thermodynamics, An Engineering Approach (any
edition),
McGraw-Hill, New York, NY.
3. Incropera, F. P. and DeWitt, D.P. (year) Introduction to Heat Transfer (any
edition), John
Wiley and Sons, New York (or another undergraduate text in heat transfer).
4. Habte, M. 2003 Two-Phase Flow Mal-distribution in a Brazed Aluminum
Evaporator. M.S.
Thesis, The Pennsylvania State University, Department of Mechanical Engineering.
5. Write-Up