march 27, 2015

13
Today: Warm Up Class Notes ; Solving Quadratic Equations Questions from Class Work?? Factoring Test

Upload: khyps13

Post on 15-Jul-2015

28 views

Category:

Documents


0 download

TRANSCRIPT

Today:

Warm Up

Class Notes; Solving Quadratic Equations

Questions from Class Work??

Factoring Test

Factoring (ax2 + bx + c) Trinomials

Factor 5x4y –

80x2y3

Warm Up/Test ReviewFactor 5x – 5y + ax -

ay

Factor 16x2 – 8xy + y2

2𝑥2 + 19𝑥 + 24

Quadratic Equations: (Write this down)

Class Notes:

1. Have a highest degree of 2.

2. Have a standard form of: ax2 + bx + c = 0

3. Have a graph which always results in a parabola.4. Have solutions which show the x intercept(s)

Solve: x2 + 3x - 4 = 0

(x ) (x ) = 0+ -4 1

x = (-4, 1)

x2 = 25, 4y2 + 2y - 1 = 0, y2 + 6y = 0, x2 + 2x - 4 = 0

The following are all examples of quadratic equations:

A). The graphs of quadratics are not straight lines, they are always in the shape of a Parabola.

B) Parabolas ALWAYS have two solutions.

C) The slope of a quadratic is not constant. The slope-intercept formula will not work with parabolas.

What about (x – 4)2 ?

These are referred to as repeated solutions.

Find the solutions to this quadratic equation.

D) The solutions of a equation are also called the roots of the equation.

Quadratic Equations

Parabolas: ...In Sports

Parabolas: ...In Archeticture

Parabolas: ...In Nature

Parabolas: ...Everywhere

And, of course, the most important Parabola of all

Solving Quadratic Equations by Factoring

Let's look at some of the different types of equations you'll face and how to deal with each of them

1: Set the equation = to 0 and solve:Example A. x2 + 6x + 9

x2 + 6x + 9 = 0; (x + 3) (x + 3) = 0, x = -3.This is a perfect square trinomial, and the parabola only touches the x axis at -3 and would be in this shape:

-3

Solving Quadratic Equations by Factoring

2. Solve x2 = 64. Remember the standard form?ax2 + bx + c = 0, where only a cannot = 0

In this case, b is 0, and c is 64.

We can solve by taking the square root of both sides.

3. Solve: 2x2 - x = 3Place all terms to the left of the = sign (Standard Form).

The result is x = + 8; x = 8, and x = -8

4. Solve: x2 = 5x ***Do not cancel an 'x' from each side.

Factor GCF first, then solve

Take 5, then we'll begin the test:

Please Clear Your Desks/Tables of everything Except scratch paper, pencil, calculator.

You will need:

Your correct code, pencil only, no phones., scratch paper

You can use a regular calculator, but one is not necessary for this test.

V.4, Question # 8