physical optics-part 1

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    PHYSICAL OPTICS

    1

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    Interference Youngs Double slit experiment

    Diffraction

    Dispersion of light and electromagnetic

    spectrum

    2

    Contents

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    The effects due to superposition of the two

    sets of waves is called interference. Types:

    Constructive interference

    Destructive interference.

    3

    INTERFERENCE

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    Constructive interferenceoccurs whenever waves

    come together so thatthey are in phase witheach other. This meansthat their oscillations at agiven point are in thesame direction, theresulting amplitude atthat point being muchlarger than the amplitude

    of an individual wave. 4

    Constructive Interference

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    Destructive

    interference occurswhen waves cometogether in such a waythat they completelycancel each other out.

    When two wavesinterfere destructively,they must have thesame amplitude in

    opposite directions. 5

    Destructive interference

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    Equal or frequency

    Superposition at the same time

    Superposition at the same place

    Travelling in same direction

    6

    Conditions for Interference

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    For constructive interference :

    Path difference = n

    For destructive interference :

    Path difference = (n+1/2)

    Path difference is the difference in length of the paths covered by

    two sets of waves which originate from two different sources and

    arrive at the place of superposition of waves

    7

    Conditions for Interference

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    Thomas Young first demonstrated interference in

    light waves from two sources in 1801 Light is incident on a screen with a narrow slit, So

    The light waves emerging from this slit arrive at asecond screen that contains two narrow, parallel slits,

    S1 and S2.

    8

    Youngs Double Slit Experiment

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    The narrow slits,

    S1 and S2 act assources of waves

    The wavesemerging fromthe slits originate

    from the samewave front andtherefore arealways in phase

    9

    Youngs Double Slit Experiment,Diagram

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    The light from the two slits form a visible pattern on a

    screen The pattern consists of a series of bright and dark

    parallel bands called fringes

    Constructive interference occurs where a bright fringe

    appears Destructive interference results in a dark fringe

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    Resulting Interference Pattern

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    The fringe pattern

    formed from a YoungsDouble Slit Experimentwould look like this

    The bright areasrepresent constructive

    interference The dark areas

    represent destructiveinterference

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    Fringe Pattern

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    Constructive

    interferenceoccurs at thecenter point

    The two waves

    travel the samedistance Therefore, they

    arrive in phase

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    Interference Patterns

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    The upper wave has to

    travel farther than thelower wave

    The upper wave travels onewavelength farther

    Therefore, the waves arrive inphase

    A bright fringe occurs

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    Interference Patterns, 2

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    The upper wave travelsone-half of awavelength fartherthan the lower wave

    The trough of thebottom wave overlapsthe crest of the upper

    wave This is destructiveinterference A dark fringe occurs

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    Interference Patterns, 3

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    The path difference, , is

    found from the tantriangle

    = r2 r1= d sin This assumes the paths are

    parallel

    Not exactly parallel, but avery good approximationsince L is much greaterthan d

    15

    Interference Equations

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    For a bright fringe, produced by constructive

    interference, the path difference must beeither zero or some integral multiple of thewavelength

    = d sin bright= m

    m = 0,

    1,

    2, m is called the order number

    When m = 0, it is the zeroth order maximum When m = 1, it is called the first order maximum

    16

    Interference Equations, 2

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    The positions of the fringes can be measured

    vertically from the zeroth order maximum y = L tan L sin Assumptions

    L>>d d>>

    Approximation is small and therefore the approximation tan sin

    can be used

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    Interference Equations, 3

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    When destructive interference occurs, a dark fringe is

    observed This needs a path difference of an odd half

    wavelength

    = d sin dark= (m + )

    m = 0,1, 2,

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    Interference Equations, 4

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    For bright fringes

    For dark fringes

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    Interference Equations, final

    0, 1, 2brightL

    y m md

    10, 1, 2

    2dark

    Ly m m

    d

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    Determination of wavelength of light

    = d/D * (fringe width)

    20

    Uses of Youngs Double SlitExperiment

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    A screen is separated from a double slit source by 1.2m.

    The distance between two slits is 0.03mm. The secondorder bright fringe is measured to be 4.5cm from centralline. Determine (a) wavelength of light (b) fringe spacing.

    Solution:

    (a) y= mD/dd=0.03mm , y= 4.5cm, m =2, D=1.2m

    = d y/m D = 5.6 *10^-7m

    (b) Fringe width = D/d = 0.2m

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    Example

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    Diffraction is the ability

    of light waves to bendaround obstaclesplaced in their path.

    Diffraction is thespreading out of wavesthrough an opening oraround the edge of anobstacle.

    22

    Diffraction

    http://www.micro.magnet.fsu.edu/primer/java/particleorwave/diffraction/
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    Diffraction

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    Light Diffraction through clouds

    24

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    When light encounters

    an obstacle it spreadsout and bends into ageometric shadow.The diffraction pattern

    is formed on thescreen.

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    Diffraction, contd..

    screen

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    Diffraction, like

    interferencecharacterizes thewave nature oflight.

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    Diffraction, contd..

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    Water Waves Spread Out behind aSmall Opening

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    Diffraction is referred

    to as the interferenceof infinite number ofwavelets.

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    Significance:

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    When the path lengthdifference between rays r1

    and r2 is l/2, the two rays willbe out of phase when theyreach P1 on the screen,resulting in destructiveinterference at P1. The pathlength difference is thedistance from the startingpoint of r2 at the center of

    the slit to point b.

    For D>>a, the path lengthdifference between rays r1and r2 is (a/2) sin q.

    30

    Diffraction by a Single Slit: Locatingthe Minima

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    Repeat previous analysis for pairs of rays, each separated by a verticaldistance of a/2 at the slit.

    Setting path length difference to

    /2 for each pair of rays, we obtain thefirst dark fringes at:

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    Diffraction by a Single Slit: Locating theMinima, cont'd

    sin sin2 2

    a

    a

    (first minimum)

    For second minimum, divide slit into 4 zonesof equal widths a/4 (separation between

    pairs of rays). Destructive interference occurswhen the path length difference for each pairis /2.

    sin sin 24 2

    a

    a

    (second minimum)

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    Dividing the slit into

    increasingly larger evennumbers of zones, wecan find higher orderminima:

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    (minima-dark fringes)sin , for 1,2,3a m m

    Diffraction by a Single Slit:Locating the Minima, cont'd